Online Aptitude Test - Aptitude Test 2
- This is a FREE online test. Beware of scammers who ask for money to attend this test.
- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
- DO NOT refresh the page.
- All the best!
Marks : 2/20
Test Review : View answers and explanation for this test.
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
 |
625 | x | 14 | x | 11 |  |
is equal to: |
| 11 | 25 | 196 |
| Given Expression = | 25 | x | 14 | x | 11 | = 5. |
| 11 | 5 | 14 |
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
In a cricket team, the average age of eleven players in 28 years. What is the age of the captain? | |
I. | The captain is eleven years older than the youngest player. |
II. | The average age of 10 players, other than the captain is 27.3 years. |
III. | Leaving aside the captain and the youngest player, the average ages of three groups of three players each are 25 years, 28 years and 30 years respectively. |
Total age of 11 players = (28 x 11) years = 308 years.
I. C = Y + 11 C - Y = 11 .... (i)
II. Total age of 10 players (excluding captain) = (27.3 x 10) years = 273 years.
Age of captain = (308 - 273) years = 35 years.
Thus, C = 35. .... (ii)
From (i) and (ii), we get Y = 24
III. Total age of 9 players = [ (25 x 3) + (28 x 3) + (30 x 3)] years = 249 years.
C + Y = (308 - 249) = 59 .... (iii)
From (i) and (iii), we get C = 35.
Thus, II alone gives the answer.
Also, I and III together give the answer.
Correct answer is (C).
Let the number be x.
| Then, x + 17 = | 60 |
| x |
x2 + 17x - 60 = 0
(x + 20)(x - 3) = 0
x = 3.
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is the present age of Tanya? | |
I. | The ratio between the present ages of Tanya and her brother Rahul is 3 : 4 respectively. |
II. | After 5 years the ratio between the ages of Tanya and Rahul will be 4 : 5. |
III. | Rahul is 5 years older than Tanya. |
I. Let the present ages of Tanya and Rahul be 3x years and 4x years.
II. After 5 years, (Tanya's age) : (Rahul's age) = 4 : 5.
III. (Rahul's age) = (Tanya's age) + 5.
| From I and II, we get | 3x + 5 | = | 4 | . This gives x. |
| 4x + 5 | 5 |
Tanya's age = 3x can be found. Thus, I and II give the answer.
From I and III, we get 4x = 3x + 5. This gives x.
Tanya's age = 3x can be found. Thus, I and III give the answer.
From III : Let Tanya's present age be t years.
Then Rahul's present age = (t + 5) years.
| Thus, from II and III, we get : | t | = | 4 | . This gives t. |
| t + 5 | 5 |
Thus, II and III give the answer.
Correct answer is (E).
Number of valid votes = 80% of 7500 = 6000.
Valid votes polled by other candidate = 45% of 6000
| = | |
45 | x 6000 | |
= 2700. |
| 100 |
C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
| Gain = |
|
80 | x 100 | % = 5%. |
| 1600 |
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
A man mixes two types of rice (X and Y) and sells the mixture at the rate of Rs. 17 per kg. Find his profit percentage. | |
I. | The rate of X is Rs. 20 per kg. |
II. | The rate of Y is Rs. 13 per kg. |
The ratio, in which X and Y are mixed, is not given.
So, both I and II together cannot give the answer.
Correct answer is (D).
Le the required time be x seconds.
More metres, More time (Direct Proportion)
0.128 : 25 :: 1 : x 
0.128x = 25 x 1
| x = | 25 | = | 25 x 1000 |
| 0.128 | 128 |
x = 195.31.
Required time = 195 sec (approximately).
| Suppose A, B and C take x, | x | and | x | days respectively to finish the work. |
| 2 | 3 |
| Then, | |
1 | + | 2 | + | 3 | |
= | 1 |
| x | x | x | 2 |
| |
6 | = | 1 |
| x | 2 |
x = 12.
So, B takes (12/2) = 6 days to finish the work.
log 27 = 1.431
log (33 ) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
| log10 80 | = log10 (8 x 10) |
| = log10 8 + log10 10 | |
| = log10 (23 ) + 1 | |
| = 3 log10 2 + 1 | |
| = (3 x 0.3010) + 1 | |
| = 1.9030. |
| Perimeter = Distance covered in 8 min. = | |
12000 | x 8 | m = 1600 m. |
| 60 |
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) m2 = 153600 m2.
m2 m2 m2 m2l = 10 m,
h = 8 m.
So, r = l2 - h2 = (10)2 - 82 = 6 m.
Curved surface area = rl = ( x 6 x 10) m2 = 60 m2.
| P.W. of Rs. 12,880 due 8 months hence |
|
|||||||||||
|
||||||||||||
| = Rs. 11500. |
| Sum = | B.D. x T.D. | = Rs. | |
72 x 60 | |
= Rs. | |
72 x 60 | |
= Rs. 360. |
| B.D. - T.D. | 72 - 60 | 12 |
One of AB, AD and CD must have given.
So, the data is inadequate.
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.