Online Aptitude Test  Aptitude Test 2
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 Total number of questions: 20.
 Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432  384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
625  x  14  x  11  is equal to:  
11  25  196 
Given Expression =  25  x  14  x  11  = 5. 
11  5  14 
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
In a cricket team, the average age of eleven players in 28 years. What is the age of the captain?  
I.  The captain is eleven years older than the youngest player. 
II.  The average age of 10 players, other than the captain is 27.3 years. 
III.  Leaving aside the captain and the youngest player, the average ages of three groups of three players each are 25 years, 28 years and 30 years respectively. 
Total age of 11 players = (28 x 11) years = 308 years.
I. C = Y + 11 C  Y = 11 .... (i)
II. Total age of 10 players (excluding captain) = (27.3 x 10) years = 273 years.
Age of captain = (308  273) years = 35 years.
Thus, C = 35. .... (ii)
From (i) and (ii), we get Y = 24
III. Total age of 9 players = [ (25 x 3) + (28 x 3) + (30 x 3)] years = 249 years.
C + Y = (308  249) = 59 .... (iii)
From (i) and (iii), we get C = 35.
Thus, II alone gives the answer.
Also, I and III together give the answer.
Correct answer is (C).
Let the number be x.
Then, x + 17 =  60 
x 
x^{2} + 17x  60 = 0
(x + 20)(x  3) = 0
x = 3.
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x^{2} + 26x  140 = 0
11x^{2} + 13x  70 = 0
(x  2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42  36) years = 6 years.
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is the present age of Tanya?  
I.  The ratio between the present ages of Tanya and her brother Rahul is 3 : 4 respectively. 
II.  After 5 years the ratio between the ages of Tanya and Rahul will be 4 : 5. 
III.  Rahul is 5 years older than Tanya. 
I. Let the present ages of Tanya and Rahul be 3x years and 4x years.
II. After 5 years, (Tanya's age) : (Rahul's age) = 4 : 5.
III. (Rahul's age) = (Tanya's age) + 5.
From I and II, we get  3x + 5  =  4  . This gives x. 
4x + 5  5 
Tanya's age = 3x can be found. Thus, I and II give the answer.
From I and III, we get 4x = 3x + 5. This gives x.
Tanya's age = 3x can be found. Thus, I and III give the answer.
From III : Let Tanya's present age be t years.
Then Rahul's present age = (t + 5) years.
Thus, from II and III, we get :  t  =  4  . This gives t. 
t + 5  5 
Thus, II and III give the answer.
Correct answer is (E).
Number of valid votes = 80% of 7500 = 6000.
Valid votes polled by other candidate = 45% of 6000
=  45  x 6000  = 2700.  
100 
C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
Gain =  80  x 100  % = 5%.  
1600 
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
 Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
 Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
 Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
 Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
 Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
A man mixes two types of rice (X and Y) and sells the mixture at the rate of Rs. 17 per kg. Find his profit percentage.  
I.  The rate of X is Rs. 20 per kg. 
II.  The rate of Y is Rs. 13 per kg. 
The ratio, in which X and Y are mixed, is not given.
So, both I and II together cannot give the answer.
Correct answer is (D).
Le the required time be x seconds.
More metres, More time (Direct Proportion)
0.128 : 25 :: 1 : x 0.128x = 25 x 1
x =  25  =  25 x 1000 
0.128  128 
x = 195.31.
Required time = 195 sec (approximately).
Suppose A, B and C take x,  x  and  x  days respectively to finish the work. 
2  3 
Then,  1  +  2  +  3  =  1  
x  x  x  2 
6  =  1  
x  2 
x = 12.
So, B takes (12/2) = 6 days to finish the work.
log 27 = 1.431
log (3^{3} ) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(3^{2} ) = 2 log 3 = (2 x 0.477) = 0.954.
log_{10} 80  = log_{10} (8 x 10) 
= log_{10} 8 + log_{10} 10  
= log_{10} (2^{3} ) + 1  
= 3 log_{10} 2 + 1  
= (3 x 0.3010) + 1  
= 1.9030. 
Perimeter = Distance covered in 8 min. =  12000  x 8  m = 1600 m.  
60 
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) m^{2} = 153600 m^{2}.
l = 10 m,
h = 8 m.
So, r = l^{2}  h^{2} = (10)^{2}  8^{2} = 6 m.
Curved surface area = rl = ( x 6 x 10) m^{2} = 60 m^{2}.
P.W. of Rs. 12,880 due 8 months hence 




= Rs. 11500. 
Sum =  B.D. x T.D.  = Rs.  72 x 60  = Rs.  72 x 60  = Rs. 360.  
B.D.  T.D.  72  60  12 
One of AB, AD and CD must have given.
So, the data is inadequate.
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.