Aptitude - Area
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- Area - Formulas
- Area - General Questions
- Area - Data Sufficiency 1
- Area - Data Sufficiency 2
- Area - Data Sufficiency 3
Perimeter = Distance covered in 8 min. = | ![]() |
12000 | x 8 | ![]() |
60 |
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) m2 = 153600 m2.
100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
![]() |
![]() |
404 | x 100 | ![]() |
= 4.04% |
100 x 100 |
2(l + b) | = | 5 |
b | 1 |
2l + 2b = 5b
3b = 2l
b = | 2 | l |
3 |
Then, Area = 216 cm2
l x b = 216
![]() |
2 | l | = 216 |
3 |
l2 = 324
l = 18 cm.
Let original length = x metres and original breadth = y metres.
Original area = (xy) m2.
New length = | ![]() |
120 | x | ![]() |
= | ![]() |
6 | x | ![]() |
100 | 5 |
New breadth = | ![]() |
120 | y | ![]() |
= | ![]() |
6 | y | ![]() |
100 | 5 |
New Area = | ![]() |
6 | x x | 6 | y | ![]() |
= | ![]() |
36 | xy | ![]() |
5 | 5 | 25 |
The difference between the original area = xy and new-area 36/25 xy is
= (36/25)xy - xy
= xy(36/25 - 1)
= xy(11/25) or (11/25)xy
![]() |
![]() |
11 | xy x | 1 | x 100 | ![]() |
= 44%. |
25 | xy |
Video Explanation: https://youtu.be/I3jLjLPn1W4
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc