# Aptitude - Area

### Exercise :: Area - General Questions

11.

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

 A. 1520 m2 B. 2420 m2 C. 2480 m2 D. 2520 m2

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40. Area = (l x b) = (63 x 40) m2 = 2520 m2.

12.

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

 A. 25% increase B. 50% increase C. 50% decrease D. 75% decrease

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

 New length = x . 2

 New area = x x 3y = 3 xy. 2 2 Increase % = 1 xy x 1 x 100 % = 50%. 2 xy

13.

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

 A. 40 B. 50 C. 120 D. Data inadequate E. None of these

Explanation:

Then, length = (x + 20) metres.

 Perimeter = 5300 m = 200 m. 26.50 2[(x + 20) + x] = 200 2x + 20 = 100 2x = 80 x = 40.

Hence, length = x + 20 = 60 m.

14.

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

 A. 34 B. 40 C. 68 D. 88

Explanation:

We have: l = 20 ft and lb = 680 sq. ft.

So, b = 34 ft. Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

15.

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

 A. Rs. 456 B. Rs. 458 C. Rs. 558 D. Rs. 568

Explanation:

 Area to be plastered = [2(l + b) x h] + (l x b) = {[2(25 + 12) x 6] + (25 x 12)} m2 = (444 + 300) m2 = 744 m2. Cost of plastering = Rs. 744 x 75 = Rs. 558. 100