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Aptitude - Area

Exercise : Area - General Questions
11.
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
1520 m2
2420 m2
2480 m2
2520 m2
Answer: Option
Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) m2 = 2520 m2.

12.
The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
25% increase
50% increase
50% decrease
75% decrease
Answer: Option
Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x .
2

New breadth = 3y.

New area = x x 3y = 3 xy.
2 2

Increase % = 1 xy x 1 x 100 % = 50%.
2 xy

13.
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
40
50
120
Data inadequate
None of these
Answer: Option
Explanation:

Let breadth = x metres.

Then, length = (x + 20) metres.

Perimeter = 5300 m = 200 m.
26.50

2[(x + 20) + x] = 200

2x + 20 = 100

2x = 80

x = 40.

Hence, length = x + 20 = 60 m.

14.
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
34
40
68
88
Answer: Option
Explanation:

We have: l = 20 ft and lb = 680 sq. ft.

So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

15.
A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Rs. 456
Rs. 458
Rs. 558
Rs. 568
Answer: Option
Explanation:

Area to be plastered = [2(l + b) x h] + (l x b)
= {[2(25 + 12) x 6] + (25 x 12)} m2
= (444 + 300) m2
= 744 m2.

Cost of plastering = Rs. 744 x 75 = Rs. 558.
100

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