Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 11)
11.
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Answer: Option
Explanation:
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.
Discussion:
20 comments Page 1 of 2.
Aishwarya said:
3 years ago
How come 40 and 63? Please explain me.
(3)
Gresha said:
4 years ago
2(l+b) = perimeter.
(L+b) = half of perimeter.
206 = 2(l+b),
so, (l+b)= 206/2,
=103.
(L+b) = half of perimeter.
206 = 2(l+b),
so, (l+b)= 206/2,
=103.
(4)
Bharath said:
4 years ago
Not understanding this, please explain it.
(1)
Gundu. Jadhav said:
4 years ago
How we get 160? please explain.
(1)
Anna said:
4 years ago
Could you please explain how the 103? Explain please.
(1)
Pradnya said:
4 years ago
@Niya.
l-b=23 perimeter is calculated as or 2*(l+b) so perimeter given 206.
2(l+b)=206.
(l+b)=206 divide 2.
So, l+b= 103.
l-b=23 perimeter is calculated as or 2*(l+b) so perimeter given 206.
2(l+b)=206.
(l+b)=206 divide 2.
So, l+b= 103.
(1)
Niya said:
5 years ago
How we get 103? Please explain.
(1)
Enyos said:
6 years ago
Supposing you say width is x, then length is x+23, perimeter p = 2x +2(x+23)=206.
Solving it gives 4x = 160; then x = 40, length therefore is 40+23 = 63.
Area will then be; length *width; implying 63*40 = 2520.
Solving it gives 4x = 160; then x = 40, length therefore is 40+23 = 63.
Area will then be; length *width; implying 63*40 = 2520.
(1)
Ruby said:
7 years ago
l-b=23
then put l-23=b in it 2(i+b)=206
Solve it l=63 then substitut valu of l,
63-23=b , b=40 lb=63*40=2520.
then put l-23=b in it 2(i+b)=206
Solve it l=63 then substitut valu of l,
63-23=b , b=40 lb=63*40=2520.
Avinash kumar said:
8 years ago
Because perimeter of a rectangle =2 * (l+b).
(1)
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