# Aptitude - Area - Discussion

### Discussion :: Area - General Questions (Q.No.11)

11.

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

 [A]. 1520 m2 [B]. 2420 m2 [C]. 2480 m2 [D]. 2520 m2

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40. Area = (l x b) = (63 x 40) m2 = 2520 m2.

 Silambarasan said: (Nov 28, 2011) How is possible l 63 and b 40?

 Meghna said: (Apr 8, 2012) l+b=103 l-b=23 ------- 2b=80 ------- So b=40, substitute b in any equation you get l= 63 Area =lb= 63*40= 2520m^2

 Jaimin said: (Mar 8, 2013) (L-b) = 23. Perimeter of rectangle L+B+L+B=206. Now, L=23+b. Put this value in perimeter formula, Get value of L. You can easily find the value of b by [(L-B)=23]. Product of L and B is your answer.

 Himanshu said: (Nov 29, 2013) (l+b) = 103 ...........(i). (l-b) = 23 ...........(ii). Subtracting eq.(ii) from (i). (l+b)-(l-b) = 103-23. 2b = 80. b = 40.

 Tony said: (Apr 29, 2014) L = B+23 and 2(L+B) = 206. 2(B+23+B) = 206. 2(2B+23) = 206. 4B+46 = 206. 4B = 206-46. 4B = 160. B = 40. L = 40+23. L = 63. LxB = 63x40 = 2520cm*

 Srini said: (Apr 8, 2015) Any one explain clearly friends?

 Mishi said: (May 11, 2015) Let the length is x and breadth is y. Then 2x+2y = 206. So we know x-y = 23. Then we x+y+x-y = 126. So we got x = 63. Then y = 40. After multiple 63*40 = 2520 cm.

 Susan said: (May 14, 2016) How l+b =103?

 Ravneet said: (Jul 3, 2016) 63 - 40 = 23. i.e. l - b = 23. And 63 * 40 = 2520.

 Parashuram Rathod said: (Aug 18, 2016) 2 (l + b) = 206. Why multiply by 2?

 Avinash Kumar said: (Apr 7, 2017) Because perimeter of a rectangle =2 * (l+b).

 Ruby said: (Apr 13, 2018) l-b=23 then put l-23=b in it 2(i+b)=206 Solve it l=63 then substitut valu of l, 63-23=b , b=40 lb=63*40=2520.

 Enyos said: (Nov 1, 2019) Supposing you say width is x, then length is x+23, perimeter p = 2x +2(x+23)=206. Solving it gives 4x = 160; then x = 40, length therefore is 40+23 = 63. Area will then be; length *width; implying 63*40 = 2520.