Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 11)
11.
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Answer: Option
Explanation:
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.
Discussion:
20 comments Page 2 of 2.
Parashuram Rathod said:
9 years ago
2 (l + b) = 206.
Why multiply by 2?
Why multiply by 2?
Ravneet said:
9 years ago
63 - 40 = 23.
i.e. l - b = 23.
And 63 * 40 = 2520.
i.e. l - b = 23.
And 63 * 40 = 2520.
Susan said:
9 years ago
How l+b =103?
Mishi said:
1 decade ago
Let the length is x and breadth is y. Then 2x+2y = 206. So we know x-y = 23.
Then we x+y+x-y = 126. So we got x = 63. Then y = 40. After multiple 63*40 = 2520 cm.
Then we x+y+x-y = 126. So we got x = 63. Then y = 40. After multiple 63*40 = 2520 cm.
Srini said:
1 decade ago
Any one explain clearly friends?
Tony said:
1 decade ago
L = B+23 and 2(L+B) = 206.
2(B+23+B) = 206.
2(2B+23) = 206.
4B+46 = 206.
4B = 206-46.
4B = 160.
B = 40.
L = 40+23.
L = 63.
LxB = 63x40 = 2520cm*
2(B+23+B) = 206.
2(2B+23) = 206.
4B+46 = 206.
4B = 206-46.
4B = 160.
B = 40.
L = 40+23.
L = 63.
LxB = 63x40 = 2520cm*
(2)
Himanshu said:
1 decade ago
(l+b) = 103 ...........(i).
(l-b) = 23 ...........(ii).
Subtracting eq.(ii) from (i).
(l+b)-(l-b) = 103-23.
2b = 80.
b = 40.
(l-b) = 23 ...........(ii).
Subtracting eq.(ii) from (i).
(l+b)-(l-b) = 103-23.
2b = 80.
b = 40.
(1)
Jaimin said:
1 decade ago
(L-b) = 23.
Perimeter of rectangle L+B+L+B=206.
Now,
L=23+b.
Put this value in perimeter formula,
Get value of L.
You can easily find the value of b by [(L-B)=23].
Product of L and B is your answer.
Perimeter of rectangle L+B+L+B=206.
Now,
L=23+b.
Put this value in perimeter formula,
Get value of L.
You can easily find the value of b by [(L-B)=23].
Product of L and B is your answer.
Meghna said:
1 decade ago
l+b=103
l-b=23
-------
2b=80
-------
So b=40, substitute b in any equation you get l= 63
Area =lb= 63*40= 2520m^2
l-b=23
-------
2b=80
-------
So b=40, substitute b in any equation you get l= 63
Area =lb= 63*40= 2520m^2
Silambarasan said:
1 decade ago
How is possible l 63 and b 40?
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