Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 13)
13.
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Answer: Option
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
| Perimeter = |  |
5300 |  |
m = 200 m. |
| 26.50 |
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Discussion:
14 comments Page 1 of 2.
Suman said:
3 years ago
Let, Length = x, then breadth = x-20,
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40) * 26.50 = 5300,
106x - 1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40) * 26.50 = 5300,
106x - 1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
(3)
SUBA said:
5 years ago
Why should we take perimeter here?
Geetha said:
5 years ago
I can't understand this problem please someone explain.
Saumya said:
6 years ago
For those who are asking why perimeter.
As the question mentions fencing, and for fencing outer boundary is calculated i.e. perimeter.
As the question mentions fencing, and for fencing outer boundary is calculated i.e. perimeter.
(1)
Soundarya said:
6 years ago
Why we are using perimeter, here? Please explain me.
Rubel Hossen said:
7 years ago
Let, Length = x, then breadth = x-20,
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40)*26.50 = 5300,
106x-1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40)*26.50 = 5300,
106x-1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
Shruti said:
8 years ago
Why we are taking perimeter?
That is formula for area.
That is formula for area.
Stalkerprice said:
1 decade ago
Calculate the perimeter by dividing 5300 by 23.50 then you can easily calculate breadth and then add 20 to breadth. Thats your answer.
NandhuBommi said:
1 decade ago
@prash
Hi prash u r wrong... the mistake u done is in calculating perimeter.. It is 2[L+L-20]=2[2L-20] = 4L-40 meters
so,
[4L - 40]*26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters. small multiply mistake leads to diff solutions ... Be careful..
Hi prash u r wrong... the mistake u done is in calculating perimeter.. It is 2[L+L-20]=2[2L-20] = 4L-40 meters
so,
[4L - 40]*26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters. small multiply mistake leads to diff solutions ... Be careful..
Prash said:
1 decade ago
Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [2L - 40] meters
[2L - 40]*26.50 = 5300
[2L - 40] = 5300 / 26.50 = 200
2L = 240
L = 120 meters
and perimeter = 2[L + L - 20] = [2L - 40] meters
[2L - 40]*26.50 = 5300
[2L - 40] = 5300 / 26.50 = 200
2L = 240
L = 120 meters
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