# Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 2)

2.

A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30° with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60°. What is the distance between the base of the tower and the point P?

Answer: Option

Explanation:

One of AB, AD and CD must have given.

So, the data is inadequate.

Discussion:

42 comments Page 1 of 5.
Sange maney said:
8 months ago

According to me, the Data is inadequate. We need a height to calculate the base.

(1)

Gerald said:
12 months ago

The right answer is 3 units.

(2)

Rahul Banait said:
1 year ago

3 unit will be the right answer.

(2)

Chandan R S said:
1 year ago

I can't understand, please explain briefly.

(7)

Raghunathan said:
2 years ago

Thank you for the explanation.

(2)

Sai pusunur said:
2 years ago

Anyone, explain the right answer.

(1)

Bishal bhowmik said:
2 years ago

Please explain the answer properly.

(1)

Asif said:
4 years ago

Here, what is the height of the tower? Anyone explain it.

(1)

Mayank said:
4 years ago

Tan 60 = qr/zr

Tan 30 = qr/pz+zr

After solving this we get;

2zr = pz.

Tan 30 = qr/pz+zr

After solving this we get;

2zr = pz.

(3)

Rajashekar said:
4 years ago

The answer is simple. (3 units).

tan30 = x / a +b

=> x = a + b /√(3)

tan60 = x / b

=> x = √(3) b

Hence,

a + b /√(3) = √(3) b

a + b = √(3) * √(3) * b

a + b = 3b,

a = 2b.

Therefore, 2b + b = 3b, in terms of b we get ANSWER as 3 UNITS.

THANK YOU

tan30 = x / a +b

=> x = a + b /√(3)

tan60 = x / b

=> x = √(3) b

Hence,

a + b /√(3) = √(3) b

a + b = √(3) * √(3) * b

a + b = 3b,

a = 2b.

Therefore, 2b + b = 3b, in terms of b we get ANSWER as 3 UNITS.

THANK YOU

(10)

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