Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 2)
2.
A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30° with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60°. What is the distance between the base of the tower and the point P?
Answer: Option
Explanation:
One of AB, AD and CD must have given.
So, the data is inadequate.
Discussion:
42 comments Page 1 of 5.
Sange maney said:
2 years ago
According to me, the Data is inadequate. We need a height to calculate the base.
(4)
Gerald said:
2 years ago
The right answer is 3 units.
(2)
Rahul Banait said:
2 years ago
3 unit will be the right answer.
(3)
Chandan R S said:
2 years ago
I can't understand, please explain briefly.
(10)
Raghunathan said:
3 years ago
Thank you for the explanation.
(5)
Sai pusunur said:
3 years ago
Anyone, explain the right answer.
(1)
Bishal bhowmik said:
3 years ago
Please explain the answer properly.
(1)
Asif said:
5 years ago
Here, what is the height of the tower? Anyone explain it.
(2)
Mayank said:
5 years ago
Tan 60 = qr/zr
Tan 30 = qr/pz+zr
After solving this we get;
2zr = pz.
Tan 30 = qr/pz+zr
After solving this we get;
2zr = pz.
(3)
Rajashekar said:
5 years ago
The answer is simple. (3 units).
tan30 = x / a +b
=> x = a + b /√(3)
tan60 = x / b
=> x = √(3) b
Hence,
a + b /√(3) = √(3) b
a + b = √(3) * √(3) * b
a + b = 3b,
a = 2b.
Therefore, 2b + b = 3b, in terms of b we get ANSWER as 3 UNITS.
THANK YOU
tan30 = x / a +b
=> x = a + b /√(3)
tan60 = x / b
=> x = √(3) b
Hence,
a + b /√(3) = √(3) b
a + b = √(3) * √(3) * b
a + b = 3b,
a = 2b.
Therefore, 2b + b = 3b, in terms of b we get ANSWER as 3 UNITS.
THANK YOU
(13)
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