# Aptitude - Height and Distance

## Why Aptitude Height and Distance?

In this section you can learn and practice Aptitude Questions based on "Height and Distance" and improve your skills in order to face the interview, competitive examination and various entrance test (CAT, GATE, GRE, MAT, Bank Exam, Railway Exam etc.) with full confidence.

## Where can I get Aptitude Height and Distance questions and answers with explanation?

IndiaBIX provides you lots of fully solved Aptitude (Height and Distance) questions and answers with Explanation. Solved examples with detailed answer description, explanation are given and it would be easy to understand. All students, freshers can download Aptitude Height and Distance quiz questions with answers as PDF files and eBooks.

## Where can I get Aptitude Height and Distance Interview Questions and Answers (objective type, multiple choice)?

Here you can find objective type Aptitude Height and Distance questions and answers for interview and entrance examination. Multiple choice and true or false type questions are also provided.

## How to solve Aptitude Height and Distance problems?

You can easily solve all kind of Aptitude questions based on Height and Distance by practicing the objective type exercises given below, also get shortcut methods to solve Aptitude Height and Distance problems.

### Exercise :: Height and Distance - General Questions

1.

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:

 A. 173 m B. 200 m C. 273 m D. 300 m

Explanation:

Let AB be the lighthouse and C and D be the positions of the ships. Then, AB = 100 m, ACB = 30° and ADB = 45°.

 AB = tan 30° = 1 AC = AB x 3 = 1003 m. AC 3

 AB = tan 45° = 1 AD = AB = 100 m. AD CD = (AC + AD) = (1003 + 100) m = 100(3 + 1) = (100 x 2.73) m = 273 m.

2.

A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30° with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60°. What is the distance between the base of the tower and the point P?

 A. 43 units B. 8 units C. 12 units D. Data inadequate E. None of these

Explanation:

One of AB, AD and CD must have given. 3.

The angle of elevation of a ladder leaning against a wall is 60° and the foot of the ladder is 4.6 m away from the wall. The length of the ladder is:

 A. 2.3 m B. 4.6 m C. 7.8 m D. 9.2 m

Explanation:

Let AB be the wall and BC be the ladder. Then, ACB = 60° and AC = 4.6 m.

 AC = cos 60° = 1 BC 2 BC = 2 x AC = (2 x 4.6) m = 9.2 m.

4.

An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:

 A. 21.6 m B. 23.2 m C. 24.72 m D. None of these

Explanation:

Let AB be the observer and CD be the tower. Draw BE CD.

Then, CE = AB = 1.6 m,

BE = AC = 203 m.

 DE = tan 30° = 1 BE 3 DE = 203 m = 20 m. 3 CD = CE + DE = (1.6 + 20) m = 21.6 m.

5.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

 A. 149 m B. 156 m C. 173 m D. 200 m

Explanation:

Let AB be the tower. Then, APB = 30° and AB = 100 m.

 AB = tan 30° = 1 AP 3 AP = (AB x 3) m = 1003 m = (100 x 1.73) m = 173 m.