# Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 5)

5.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Answer: Option

Explanation:

Let AB be the tower.

Then, APB = 30° and AB = 100 m.

AB | = tan 30° = | 1 |

AP | 3 |

AP | = (AB x 3) m |

= 1003 m | |

= (100 x 1.73) m | |

= 173 m. |

Discussion:

26 comments Page 1 of 3.
Bala murali said:
10 months ago

Here, tan 30 is 1/√3.

Then how will 100/√3 become 1.73?

Then how will 100/√3 become 1.73?

(2)

Sagar said:
1 year ago

1.73 how?

Vivek Sunny said:
2 years ago

Approach 1*1= 1,

1.5*1.5=2.25,

2*2=4,

so.

√ 3 is between 1.5 and 2 so 1.73 is correct.

1.5*1.5=2.25,

2*2=4,

so.

√ 3 is between 1.5 and 2 so 1.73 is correct.

Rutuja said:
2 years ago

how Root 3 is calculated as 1.73?

Please anyone explain it.

Please anyone explain it.

Vikas said:
2 years ago

Why tan only?

Because we find the height of the tower that we get tan30 because;

tan30 = perpendicular/base.

Because we find the height of the tower that we get tan30 because;

tan30 = perpendicular/base.

Mounika said:
2 years ago

Why tan only? Please explain.

Nissipravalika said:
3 years ago

Hi,

How to calculate √3 value?

Anyone can explain please?

How to calculate √3 value?

Anyone can explain please?

Gitanshu said:
3 years ago

How to divide 34.64/1.732 without calc. Is there any simple trick?

Priya said:
4 years ago

Thank you so much @Sarthak.

You explained it neat and clear.

You explained it neat and clear.

Vansh giroh said:
4 years ago

Here AP needs to find so using the AB value Tan 30 is taken and root 3 is 1.73. So the answer will be 173m.

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