# Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 5)

5.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Answer: Option

Explanation:

Let AB be the tower.

Then, APB = 30° and AB = 100 m.

AB | = tan 30° = | 1 |

AP | 3 |

AP | = (AB x 3) m |

= 1003 m | |

= (100 x 1.73) m | |

= 173 m. |

Discussion:

28 comments Page 1 of 3.
Deeps said:
9 months ago

Why can't we use sin30?

It is also perpendicular right?

It is also perpendicular right?

(1)

Shivraj Singh said:
1 year ago

The value of √ 3 is 1.73.

(2)

Bala murali said:
2 years ago

Here, tan 30 is 1/√3.

Then how will 100/√3 become 1.73?

Then how will 100/√3 become 1.73?

(2)

Sagar said:
3 years ago

1.73 how?

(1)

Vivek Sunny said:
3 years ago

Approach 1*1= 1,

1.5*1.5=2.25,

2*2=4,

so.

√ 3 is between 1.5 and 2 so 1.73 is correct.

1.5*1.5=2.25,

2*2=4,

so.

√ 3 is between 1.5 and 2 so 1.73 is correct.

(2)

Rutuja said:
3 years ago

how Root 3 is calculated as 1.73?

Please anyone explain it.

Please anyone explain it.

Vikas said:
3 years ago

Why tan only?

Because we find the height of the tower that we get tan30 because;

tan30 = perpendicular/base.

Because we find the height of the tower that we get tan30 because;

tan30 = perpendicular/base.

Mounika said:
3 years ago

Why tan only? Please explain.

Nissipravalika said:
4 years ago

Hi,

How to calculate √3 value?

Anyone can explain please?

How to calculate √3 value?

Anyone can explain please?

(1)

Gitanshu said:
4 years ago

How to divide 34.64/1.732 without calc. Is there any simple trick?

(2)

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers