Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 2)
2.
A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30° with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60°. What is the distance between the base of the tower and the point P?
Answer: Option
Explanation:
One of AB, AD and CD must have given.
So, the data is inadequate.
Discussion:
43 comments Page 1 of 5.
Jaidev said:
7 years ago
No, @Jhanvi.
If you take h as the height of the tower, b as the distance from P to the base of the tower and when the person walks to a new point lets say Q, so take x= distance from Q to base of the tower. Now solving these we have tan30=h/b and tan60=h/x. We are left with 3 unknowns and only two equations. Therefore the solution cannot be found.
If you take h as the height of the tower, b as the distance from P to the base of the tower and when the person walks to a new point lets say Q, so take x= distance from Q to base of the tower. Now solving these we have tan30=h/b and tan60=h/x. We are left with 3 unknowns and only two equations. Therefore the solution cannot be found.
Rajashekar said:
5 years ago
The answer is simple. (3 units).
tan30 = x / a +b
=> x = a + b /√(3)
tan60 = x / b
=> x = √(3) b
Hence,
a + b /√(3) = √(3) b
a + b = √(3) * √(3) * b
a + b = 3b,
a = 2b.
Therefore, 2b + b = 3b, in terms of b we get ANSWER as 3 UNITS.
THANK YOU
tan30 = x / a +b
=> x = a + b /√(3)
tan60 = x / b
=> x = √(3) b
Hence,
a + b /√(3) = √(3) b
a + b = √(3) * √(3) * b
a + b = 3b,
a = 2b.
Therefore, 2b + b = 3b, in terms of b we get ANSWER as 3 UNITS.
THANK YOU
(13)
Harry grewal said:
7 years ago
No, the Information is inadequate. Moreover, the graph is also wrong.
The angle must be made from man's eye, not from the foot. The person is in standing position. Not laying on the ground.
The angle must be made from man's eye, not from the foot. The person is in standing position. Not laying on the ground.
Kk rawat said:
1 decade ago
The angle of elevation of the top of a TV tower is from three points a, b, c, in straight line through the foot of the tower are alpha, two alpha, three alpha then the of the tower is?
Raji said:
1 decade ago
The distance between the base of the tower and the distance at which the man stands from the pole must be given. Otherwise this problem can not be solved. And hence the answer (D).
(1)
Shashi Kumar said:
6 years ago
Value of H is not given, without the value of h we can't find the distance between base of the tower and the point P that's why answer is Option D.
(4)
Jiya said:
1 decade ago
This data is insufficient because not any perfect side given. If any perpendicular distance given than solve it otherwise not solve.
Sayan Biswas said:
1 decade ago
The problem contains 3 unknown variables in 2 equations. We need another equation to solve it. Hence data inadequate.
Amar ATI KOLKATA said:
9 years ago
Height of the Tower or Distance travelled by man should be provided to get a solution of this question.
Apalkitam said:
1 decade ago
The height of the triangular in the form of the conventional. So it should be larger one.
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