Aptitude  Logarithm
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 Logarithm  Formulas
 Logarithm  General Questions
(a) Since log_{a} a = 1, so log_{10} 10 = 1.
(b) log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3
log (2 + 3) log (2 x 3)
(c) Since log_{a} 1 = 0, so log_{10} 1 = 0.
(d) log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3.
So, (b) is incorrect.
log_{5} 512 












= 3.876 
log 8  is equal to: 
log 8 
log 8  =  log (8)^{1/2}  =  log 8  =  1  . 
log 8  log 8  log 8  2 
log 27 = 1.431
log (3^{3} ) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(3^{2} ) = 2 log 3 = (2 x 0.477) = 0.954.
If log  a  +  log  b  = log (a + b), then: 
b  a 
log  a  + log  b  = log (a + b) 
b  a 
log (a + b) = log  a  x  b  = log 1.  
b  a 
So, a + b = 1.