Aptitude - Logarithm
Exercise : Logarithm - General Questions
- Logarithm - Formulas
- Logarithm - General Questions
11.
If log 2 = 0.30103, the number of digits in 264 is:
Answer: Option
Explanation:
log (264) | = 64 x log 2 |
= (64 x 0.30103) | |
= 19.26592 |
Its characteristic is 19.
Hence, then number of digits in 264 is 20.
12.
If logx | ![]() |
9 | ![]() |
= - | 1 | , then x is equal to: |
16 | 2 |
Answer: Option
Explanation:
logx | ![]() |
9 | ![]() |
= - | 1 |
16 | 2 |
![]() |
= | 9 |
16 |
![]() |
1 | = | 9 |
x | 16 |
![]() |
16 |
9 |
![]() |
![]() |
16 | ![]() |
2 |
9 |
![]() |
256 |
81 |
13.
If ax = by, then:
Answer: Option
Explanation:
ax = by
log ax = log by
x log a = y log b
![]() |
log a | = | y | . |
log b | x |
14.
If logx y = 100 and log2 x = 10, then the value of y is:
Answer: Option
Explanation:
log 2 x = 10 x = 210.
logx y = 100
y = x100
y = (210)100 [put value of x]
y = 21000.
15.
The value of log2 16 is:
Answer: Option
Explanation:
Let log2 16 = n.
Then, 2n = 16 = 24 n = 4.
log2 16 = 4.
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