Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 12)
12.
If logx 9 = - 1 , then x is equal to:
16 2
- 3
4
3
4
81
256
256
81
Answer: Option
Explanation:

logx 9 = - 1
16 2

x-1/2 = 9
16

1 = 9
x 16

x = 16
9

x = 16 2
9

x = 256
81

Discussion:
17 comments Page 1 of 2.

J. Bhargav sai said:   4 years ago
This is also correct answer.
Log x (9/16) = -1/2,
Log x (3/4)^2 = -1/2,
Log x^ (-1/2) = (3/4) ^2,
√x = (3/4) ^2.

Root and square both cancel.
And after x = (3/4).
X = (3/4),
(2)

Deepanesh said:   5 years ago
Log X = m.
X = 9/16.
m = -1/2,
a power m = X ->Formula.

Nagaraju Azmeera said:   5 years ago
Thanks for explaining @Pavitra.

Xcpen said:   7 years ago
X^-1/2 = 9/16,
1/x^1/2 = 9/16,
1/x^1/2 = (3/4)^1/2,
1/x = 3/4,
X = 4/3.

Himansu said:   8 years ago
log(0.1)=-1/3.

Multiplying LHS and RHS by -3 we get,
RHS = 1 and,
LHS = -3 logx(1/10),
= logx (10) to power 3,
= logx (1000)=1,
x = 1000.

Rushikesh said:   9 years ago
@ Mounika.

X = 2.15.

Hemant said:   9 years ago
Your explanation is too good @@Rohit.

Mounika said:   9 years ago
If logx (0.1) = -1/3, then the value of x is.

Please tell me the answer for this.

Kathir said:   9 years ago
@Rohit. Good explanation.

PAVITHRA_228 said:   10 years ago
As per the formula.

log x = m.

=> log x/log a = m.

=> log (9/16)/log a = -1/2.

=>2 log (9/16) = -log a.

=> log (9/16)^2 = log(1/a).

=> log (81/256) = log(1/a).

log gets cancelled,

=> a = 256/81.
(2)


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