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Speed in still water =	1	(11 + 5) kmph = 8 kmph.
	2

Let C.P. be Rs. x.

Then,	1920 - x	x 100 =	x - 1280	x 100
	x		x

1920 - x = x - 1280

2x = 3200

x = 1600

Required S.P. = 125% of Rs. 1600 = Rs.		125	x 1600		= Rs 2000.
		100

2 kmph =		2 x	5		m/sec =	5	m/sec.
			18			9

4 kmph =		4 x	5		m/sec =	10	m/sec.
			18			9

Let the length of the train be x metres and its speed by y m/sec.

Then,		x		= 9 and		x		= 10.
		y - 5 9				y - 10 9

9y - 5 = x and 10(9y - 10) = 9x

9y - x = 5 and 90y - 9x = 100.

On solving, we get: x = 50.

Length of the train is 50 m.

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

=		10 x	5	m/sec
			18

=		25	m/sec
		9

	2x	=	25
	36		9

2x = 100

x = 50.

   34.95
  240.016
 + 23.98
 --------
  298.946
 --------    

Whole work is done by A in		20 x	5		= 25 days.
			4

Now,		1 -	4		i.e.,	1	work is done by A and B in 3 days.
			5			5

Whole work will be done by A and B in (3 x 5) = 15 days.

A's 1 day's work =	1	, (A + B)'s 1 day's work =	1	.
	25		15

B's 1 day's work =		1	-	1		=	4	=	2	.
		15		25			150		75

So, B alone would do the work in	75	= 37	1	days.
	2		2

Given	a		x - 1	=		b		x - 3
	b					a

a

x - 1

=

a

-(x - 3)

=

a

(3 - x)

b

b

b

x - 1 = 3 - x

2x = 4

x = 2.

Let, B.D = Re. 1.

Then, B.G. = Re.	3	.
	25

T.D. = (B.D. - B.G.) = Re.		1 -	3		= Re.	22	.
			25			25

Sum =		1 x (22/25)		= Rs.	22	.
		1-(22/25)			3

S.I. on Rs.	22	for 1	1	years is Re. 1.
	3		2

Rate =		100 x 1	%	= 100 = 9 1 %. 11 11
		22 x 3 3 2

T.D. = P.W. x B.G. = 576 x 16 = 96.

The year 2007 is an ordinary year. So, it has 1 odd day.

1^st day of the year 2007 was Monday.

1^st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

Let the numbers be x and y.

Then, xy = 120 and x² + y² = 289.

(x + y)² = x² + y² + 2xy = 289 + (2 x 120) = 529

x + y = 529 = 23.

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1 hours as 5/3 hours]

Required speed =		1200 x	3	km/hr	= 720 km/hr.
			5

II gives the value of r.

But, in I, the breadth of rectangle is not given.

So, we cannot find the surface area of the cone.

Hence, the height of the cone cannot be determined.

Correct answer is (D).

Let the required number of days be x.

Less persons, More days (Indirect Proportion)

More working hours per day, Less days (Indirect Proportion)

Persons	30	:	39		:: 12 : x
Working hours/day	6	:	5

30 x 6 x x = 39 x 5 x 12

x =	(39 x 5 x 12)
	(30 x 6)

x = 13.

Other side	=	15 2 - 9 2 2 2	ft
	=	225 - 81 4 4	ft
	=	144 4	ft
	=	6 ft.

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

(A + B)'s 1 hour's work =		1	+	1		=	9	=	3	.
		12		15			60		20

(A + C)'s hour's work =		1	+	1		=	8	=	2	.
		12		20			60		15

Part filled in 2 hrs =		3	+	2		=	17	.
		20		15			60

Part filled in 6 hrs =		3 x	17		=	17	.
			60			20

Remaining part =		1 -	17		=	3	.
			20			20

Now, it is the turn of A and B and	3	part is filled by A and B in 1 hour.
	20

Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.