Online Aptitude Test - Aptitude Test - Random
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Marks : 2/20
Test Review : View answers and explanation for this test.
Let n = 4q + 3. Then 2n = 8q + 6 = 4(2q + 1 ) + 2.
Thus, when 2n is divided by 4, the remainder is 2.
| Given Exp. = 666 x | 1 | x | 1 | = 37. |
| 6 | 3 |
Divisor = (5 x 46) = 230
10 x Quotient = 230 = |
230 | = 23 |
| 10 |
Dividend = (Divisor x Quotient) + Remainder
= (230 x 23) + 46
= 5290 + 46
= 5336.
3.87 - 2.59 = (3 + 0.87) - (2 + 0.59)
| = | ![]() |
3 + | 87 | ![]() |
- | ![]() |
2 + | 59 | ![]() |
| 99 | 99 |
| = 1 + | ![]() |
87 | - | 59 | ![]() |
| 99 | 99 |
| = 1 + | 28 |
| 99 |
= 1.28.
| (0.04)-1.5 = | ![]() |
4 | ![]() |
-1.5 |
| 100 |
| = | ![]() |
1 | ![]() |
-(3/2) |
| 25 |
= (25)(3/2)
= (52)(3/2)
= (5)2 x (3/2)
= 53
= 125.
Let A = 2k, B = 3k and C = 5k.
| A's new salary = | 115 | of 2k = | ![]() |
115 | x 2k | ![]() |
= | 23k |
| 100 | 100 | 10 |
| B's new salary = | 110 | of 3k = | ![]() |
110 | x 3k | ![]() |
= | 33k |
| 100 | 100 | 10 |
| C's new salary = | 120 | of 5k = | ![]() |
120 | x 5k | ![]() |
= 6k |
| 100 | 100 |
New ratio |
![]() |
23k | : | 33k | : 6k | ![]() |
= 23 : 33 : 60 |
| 10 | 10 |
| Let 40% of A = | 2 | B |
| 3 |
| Then, | 40A | = | 2B |
| 100 | 3 |
|
2A | = | 2B |
| 5 | 3 |
|
A | = | ![]() |
2 | x | 5 | ![]() |
= | 5 |
| B | 3 | 2 | 3 |
A : B = 5 : 3.
Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.
Three friends, P, Q and R started a partnership business investing money in the ratio of 5 : 4 : 2 respectively for a period of 3 years. What is the amount received by P as his share profit? | |
I. | Total amount invested in the business in Rs. 22,000. |
II. |
Profit earned at the end of 3 years is |
III. | The average amount of profit earned per year is Rs. 2750. |
| I and II give, profit after 3 years = Rs. | ![]() |
3 | x 22000 | ![]() |
= Rs. 8250. |
| 8 |
From III also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250.
P's share = Rs. |
![]() |
8250 x | 5 | ![]() |
= Rs. 3750. |
| 11 |
Thus, (either III is redundant [or] I and II are redundant).
Correct answer is (B).
Suppose, first pipe alone takes x hours to fill the tank .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.
|
1 | + | 1 | = | 1 |
| x | (x - 5) | (x - 9) |
|
x - 5 + x | = | 1 |
| x(x - 5) | (x - 9) |
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x - 15)(x - 3) = 0
x = 15. [neglecting x = 3]
Let the sum be Rs. P.
| Then, | ![]() |
P | ![]() |
1 + | 10 | ![]() |
2 | - P | ![]() |
= 525 |
| 100 |
|
P | ![]() |
![]() |
11 | ![]() |
2 | - 1 | ![]() |
= 525 |
| 10 |
P = |
![]() |
525 x 100 | ![]() |
= 2500. |
| 21 |
Sum = Rs . 2500.
| So, S.I. = Rs. | ![]() |
2500 x 5 x 4 | ![]() |
= Rs. 500 |
| 100 |
| The value of | ![]() |
1 | + | 1 | + | 1 | ![]() |
is: |
| log3 60 | log4 60 | log5 60 |
| Given expression | = log60 3 + log60 4 + log60 5 |
| = log60 (3 x 4 x 5) | |
| = log60 60 | |
| = 1. |
l2 + b2 = 41.
Also, lb = 20.
(l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = |
![]() |
404 | x 100 | % |
= 4.04% |
| 100 x 100 |
| B runs | 45 | m in 6 sec. |
| 2 |
B covers 300 m in |
![]() |
6 x | 2 | x 300 | sec |
= 80 sec. |
| 45 |
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
| 5 min. spaces are gained in | ![]() |
60 | x 5 | min |
= 5 | 5 | min. |
| 55 | 11 |
Required time = 5 |
5 | min. past 7. |
| 11 |
For an income of Rs. 8, investment = Rs. 100.
| For an income of Rs. 6, investment = Rs. | ![]() |
100 | x 6 | ![]() |
= Rs. 75. |
| 8 |
Market value of Rs. 100 stock = Rs. 75.
Let P.W. be Rs. x.
Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
x x 16 x |
9 | x | 1 | = 189 or x = 1575. |
| 12 | 100 |
P.W. = Rs. 1575.
Sum due = P.W. + T.D. = Rs. (1575 + 189) = Rs. 1764.
| Required sum | = P.W. of Rs. 702 due 6 months + P.W. of Rs. 702 due 1 year hence | |||||||||||||
|
||||||||||||||
| = Rs. (675 + 650) | ||||||||||||||
| = Rs. 1325. |
P.W. = Rs. (540 - 90) = Rs. 450.
S.I. on Rs. 450 = Rs. 90.
| S.I. on Rs. 540 = Rs. | ![]() |
90 | x 540 | ![]() |
= Rs. 108. |
| 450 |
B.D. = Rs. 108.


of the total investment.






