Online Aptitude Test - Aptitude Test - Random
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- Total number of questions: 20.
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Marks : 2/20
Test Review : View answers and explanation for this test.
The square of a natural number never ends in 7.
42437 is not the square of a natural number.
| 1904 x 1904 | = (1904)2 |
| = (1900 + 4)2 | |
| = (1900)2 + (4)2 + (2 x 1900 x 4) | |
| = 3610000 + 16 + 15200. | |
| = 3625216. |
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R.
Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108, 36 and 90 is 18,
H.C.F. of given numbers = 0.18.
| What should come in place of both x in the equation | x | = | 162 | . |
| 128 | x |
| Let | x | = | 162 |
| 128 | x |
Then x2 = 128 x 162
= 64 x 2 x 18 x 9
= 82 x 62 x 32
= 8 x 6 x 3
= 144.
x = 144 = 12.
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Let the numbers be x and y.
| Then, xy = 9375 and | x | = 15. |
| y |
| xy | = | 9375 |
| (x/y) | 15 |
y2 = 625.
y = 25.
x = 15y = (15 x 25) = 375.
Sum of the numbers = x + y = 375 + 25 = 400.
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is Arun's present age? | |
I. | Five years ago, Arun's age was double that of his son's age at that time. |
II. | Present ages of Arun and his son are in the ratio of 11 : 6 respectively. |
III. | Five years hence, the respective ratio of Arun's age and his son's age will become 12 : 7. |
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
I. 5 years ago, Arun's age = 2 x His son's age.
| III. 5 years hence, | Arun's Age | = | 12 |
| Son's age | 7 |
Clearly, any two of the above will give Arun's present age.
Correct answer is (D).
3x - y = 27 = 33 
x - y = 3 ....(i)
3x + y = 243 = 35 x + y = 5 ....(ii)
On solving (i) and (ii), we get x = 4.
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Let the numbers be 3x and 5x.
| Then, | 3x - 9 | = | 12 |
| 5x - 9 | 23 |
23(3x - 9) = 12(5x - 9)
9x = 99
x = 11.
The smaller number = (3 x 11) = 33.
Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
3x = 36000
x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
| A's share = Rs. |
 |
35000 x | 21 |  |
= Rs. 14,700. |
| 50 |
Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30 = 6 : 10 : 5.
Let the total profit be Rs. 100.
| After paying to charity, A's share = Rs. | |
95 x | 3 | |
= Rs. 57. |
| 5 |
If A's share is Rs. 57, total profit = Rs. 100.
| If A's share Rs. 855, total profit = | |
100 | x 855 | |
= 1500. |
| 57 |
| Perimeter = Distance covered in 8 min. = | |
12000 | x 8 | m = 1600 m. |
| 60 |
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) m2 = 153600 m2.
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
| Required number of tiles = |
|
1517 x 902 | |
= 814. |
| 41 x 41 |
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Let investment in 12% stock be Rs. x.
Then, investment in 15% stock = Rs. (12000 - x).
| |
12 | x x + | 15 | x (12000 - x) = 1360. |
| 120 | 125 |
| |
x | + | 3 | (12000 - x) = 1360. |
| 10 | 25 |
5x + 72000 - 6x = 1360 x 50
x = 4000.
Go on multiplying the given numbers by 2, 3, 4, 5, 6.
So, the correct next number is 1440.