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Instruction:

  • This is a FREE online test. DO NOT pay money to anyone to attend this test.
  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).


Direction (for Q.No. 1):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

1.

What is Ravi's present age?

I. 

The present age of Ravi is half of that of his father.

II. 

After 5 years, the ratio of Ravi's age to that of his father's age will be 6 : 11.

 III. 

Ravi is 5 years younger than his brother.

A.
I and II only
B.
II and III only
C.
I and III only
D.
All I, II and III
E.
Even with all the three statements answer cannot be determined.

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

  I. Let Ravi's present age be x years. Then, his father's present age = 2x years.

 II. After 5 years, Ravi's age = 6
Father's age 11

III. Ravi is younger than his brother.

From I and II, we get x + 5 = 6 .   This gives x, the answer.
2x + 5 11

Thus, I and II together give the answer. Clearly, III is redundant.

Correct answer is (A).

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2.

Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?

A.
16 years
B.
18 years
C.
20 years
D.
Cannot be determined
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then, (6x + 6) + 4 = 11
(5x + 6) + 4 10

10(6x + 10) = 11(5x + 10)

5x = 10

x = 2.

Sagar's present age = (5x + 6) = 16 years.

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3.

The interest on Rs. 750 for 2 years is the same as the true discount on Rs. 960 due 2 years hence. If the rate of interest is the same in both cases, it is:

A.
12%
B.
14%
C.
15%
D.
16 2 %
3

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

S.I. on Rs. 750 = T.D. on Rs. 960.

This means P.W. of Rs. 960 due 2 years hence is Rs. 750.

T.D. = Rs. (960 - 750) = Rs. 210.

Thus, S.I. on R.s 750 for 2 years is Rs. 210.

Rate = 100 x 210 % = 14%
750 x 2

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4.

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

A.
1677
B.
1683
C.
2523
D.
3363

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

Required number = (840 x 2 + 3) = 1683.

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5.

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:

A.
2 : 3
B.
3 : 2
C.
3 : 4
D.
4 : 3

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the speed of the train be x km/hr and that of the car be y km/hr.

Then, 120 + 480 = 8       1 + 4 = 1 ....(i)
x y x y 15

And, 200 + 400 = 25     1 + 2 = 1 ....(ii)
x y 3 x y 24

Solving (i) and (ii), we get: x = 60 and y = 80.

Ratio of speeds = 60 : 80 = 3 : 4.

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Direction (for Q.No. 6):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

6.

How much did Rohit get as profit at the year-end in the business done by Nitin, Rohit and Kunal?

I. 

Kunal invested Rs. 8000 for nine months, his profit was times that of Rohit's and his investment was four times that of Nitin.

II. 

Nitin and Rohit invested for one year in the proportion 1 : 2 respectively.

 III. 

The three together got Rs. 1000 as profit at the year end.

A.
Only I and II
B.
Only I and III
C.
Question cannot be answered even with the information in all the three statements.
D.
All I, II and III
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

I and II give:

   K = Rs. (8000 x 9) for 1 month = Rs. 72000 for 1 month.

   N = Rs. 1 x 8000 x 12 for 1 month = Rs. 24000 for 1 month.
4

   R = Rs. 48000 for 1 month.

K : N : R = 72000 : 24000 : 48000 = 3 : 1 : 2.

III gives, total profit = Rs. 1000.

Rohit's share = Rs. 1000 x 2 = Rs. 333 1
6 3

Correct answer is (D).

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7.

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
A.
Rs. 650
B.
Rs. 690
C.
Rs. 698
D.
Rs. 700

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 - 117) = Rs. 698.

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Direction (for Q.No. 8):

Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.

8.

What is the percent profit earned by the shopkeeper on selling the articles in his shop?

I. 

Labeled price of the articles sold was 130% of the cost price.

II. 

Cost price of each article was Rs. 550.

 III. 

A discount of 10% on labeled price was offered.

A.
Only I
B.
Only II
C.
I and III
D.
All the three are required
E.
Question cannot be answer even with information in all the three statements.

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

  I. Let C.P. be Rs. x.

Then, M.P. = 130% of x = Rs. 13x .
10

III. S.P. = 90% of M.P.

Thus, I and III give, S.P. = Rs. 90 x 13x = Rs. 117x
100 10 100

Gain = Rs. 117x - x = Rs. 17x
100 100

Thus, from I and III, gain % can be obtained.

Clearly, II is redundant.

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Direction (for Q.No. 9):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

9.

What is the two-digit number?

I. 

Sum of the digits is 7.

II. 

Difference between the number and the number obtained by interchanging the digits is 9.

 III. 

Digit in the ten's place is bigger than the digit in the unit's place by 1.

A.
I and II only
B.
II and III only
C.
I and III only
D.
All I, II and III
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

Let the tens and units digit be x and y respectively.

  I. x + y = 7.

 II. (10x + y) - (10y + x) = 9       x - y = 1.

III. x - y = 1.

Thus, I and II as well as I and III give the answer.

Correct answer is (E).

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[#]
10.

What was the day of the week on 17th June, 1998?

A.
Monday
B.
Tuesday
C.
Wednesday
D.
Thursday

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan.  Feb.   March    April    May      June 
(31 +  28  +  31   +   30   +   31   +   17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

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Direction (for Q.No. 11):
Find out the wrong number in the given sequence of numbers.
11.

52, 51, 48, 43, 34, 27, 16

A.
27
B.
34
C.
43
D.
48

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Subtract 1, 3, 5, 7, 9, 11 from successive numbers.

So, 34 is wrong.

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12.

A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

A.
65 sec
B.
89 sec
C.
100 sec
D.
150 sec

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Speed = 240 m/sec = 10 m/sec.
24

Required time = 240 + 650 sec = 89 sec.
10

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13.

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.
9 a.m.
B.
10 a.m.
C.
10.30 a.m.
D.
11 a.m.

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

Therefore 20x + 25(x - 1) = 110

=> 45x = 135

=> x = 3.

So, they meet at 10 a.m.

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14.

A family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family?
A.
28  4 years
7
B.
31  5 years
7
C.
32  1 years
7
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Required average
= 67 x 2 + 35 x 2 + 6 x 3
2 + 2 + 3
= 134 + 70 + 18
7
= 222
7
= 31  5 years.
7

Video Explanation: https://youtu.be/OXLnoItd0MA

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15.

At what time between 9 and 10 o'clock will the hands of a watch be together?

A.
45 min. past 9
B.
50 min. past 9
C.
49 1 min. past 9
11
D.
48 2 min. past 9
11

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.

55 min. spaces gained in 60 min.

45 min. spaces are gained in 60 x 45 min or 49 1 min.
55 11

The hands are together at 49 1 min. past 9.
11

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16.

A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is:

A.
400 kg
B.
560 kg
C.
600 kg
D.
640 kg

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

By the rule of alligation, we have:

Profit on 1st part Profit on 2nd part
8% Mean Profit
14% 		18%
4 6

Ration of 1st and 2nd parts = 4 : 6 = 2 : 3

Quantity of 2nd kind = 3 x 1000 kg = 600 kg.
5

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[#]
17.

If logx y = 100 and log2 x = 10, then the value of y is:

A.
210
B.
2100
C.
21000
D.
210000

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

log 2 x = 10         x = 210.

logx y = 100

y = x100

y = (210)100     [put value of x]

y = 21000.

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[#]
18.

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A.
648
B.
1800
C.
2700
D.
10800

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

Machines 6 : 10 :: 270 : x
Time (in minutes) 1 : 4

6 x 1 x x = 10 x 4 x 270

x = (10 x 4 x 270)
(6)

x = 1800.

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[#]
Direction (for Q.Nos. 19 - 20):
Find out the wrong number in the series.
19.

10, 26, 74, 218, 654, 1946, 5834

A.
26
B.
74
C.
218
D.
654
E.
1946

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

2nd term = (1st term) x 3 - 4 = 10 x 3 - 4 = 26.

3rd term = (2nd term) x 3 - 4 = 26 x 3 - 4 = 74.

4th term = (3th term) x 3 - 4 = 74 x 3 - 4 = 218.

5th term = (4th term) x 3 - 4 = 218 x 3 - 4 = 650.

5th term must be 650 instead of 654.

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[#]
20.

3, 7, 15, 39, 63, 127, 255, 511

A.
7
B.
15
C.
39
D.
63
E.
127

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Go on multiplying 2 and adding 1 to get the next number.

So, 39 is wrong.

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[#]
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