Online Aptitude Test - Aptitude Test - Random
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- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
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Marks : 2/20
Test Review : View answers and explanation for this test.
87) 13601 (156
87
----
490
435
----
551
522
---
29
---
Therefore, the required number = 29.
Sum of digits = (4 + 8 + 1 + x + 6 + 7 + 3) = (29 + x), which must be divisible by 9.
x = 7.
For every natural number n, (xn - an) is completely divisible by (x - a).
| If | 144 | = | 14.4 | , then the value of x is: |
| 0.144 | x |
| 144 | = | 14.4 |
| 0.144 | x |
![]() |
144 x 1000 | = | 14.4 |
| 144 | x |
x = |
14.4 | = 0.0144 |
| 1000 |
Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 - 63x
120x = 40
| x = | 1 |
| 3 |
| Number of floors covered by David in (1/3) min. = | ![]() |
1 | x 57 | ![]() |
= 19. |
| 3 |
So, their paths cross at (11 +19) i.e., 30th floor.
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
Average age of employees working in a department is 30 years. In the next year, ten workers will retire. What will be the average age in the next year? | |
I. | Retirement age is 60 years. |
II. | There are 50 employees in the department. |
I. Retirement age is 60 years.
II. There are 50 employees in the department.
Average age of 50 employees = 30 years.
Total age of 50 employees = (50 x 30) years = 1500 years.
Number of employees next year = 40.
Total age of 40 employees next year (1500 + 40 - 60 x 10) = 940.
| Average age next year = | 940 | years = 23 | 1 | years. |
| 40 | 2 |
Thus, I and II together give the answer. So, correct answer is (E).
| 5% of A + 4% of B = | 2 | (6% of A + 8% of B) |
| 3 |
|
5 | A + | 4 | B | = | 2 | ![]() |
6 | A + | 8 | B | ![]() |
| 100 | 100 | 3 | 100 | 100 |
|
1 | A + | 1 | B | = | 1 | A + | 4 | B |
| 20 | 25 | 25 | 75 |
|
![]() |
1 | - | 1 | A = |
![]() |
4 | - | 1 | B |
| 20 | 25 | 75 | 25 |
|
1 | A = | 1 | B |
| 100 | 75 |
| A | = | 100 | = | 4 | . |
| B | 75 | 3 |
Required ratio = 4 : 3
Video Explanation: YouTube Video
Let C.P. be Rs. x.
| Then, | 1920 - x | x 100 = | x - 1280 | x 100 |
| x | x |
1920 - x = x - 1280
2x = 3200
x = 1600
Required S.P. = 125% of Rs. 1600 = Rs. |
![]() |
125 | x 1600 | ![]() |
= Rs 2000. |
| 100 |
Video Explanation: https://youtu.be/0tTd5TwCspY
Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
Simran's share = Rs. |
![]() |
24500 x | 3 | ![]() |
= Rs. 10,500. |
| 7 |
| Work done by X in 4 days = | ![]() |
1 | x 4 | ![]() |
= | 1 | . |
| 20 | 5 |
| Remaining work = | ![]() |
1 - | 1 | ![]() |
= | 4 | . |
| 5 | 5 |
| (X + Y)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 8 | = | 2 | . |
| 20 | 12 | 60 | 15 |
| Now, | 2 | work is done by X and Y in 1 day. |
| 15 |
| So, | 4 | work will be done by X and Y in | ![]() |
15 | x | 4 | ![]() |
= 6 days. |
| 5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days.
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
|
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
| log2 10 = | 1 | = | 1 | = | 10000 | = | 1000 | . |
| log10 2 | 0.3010 | 3010 | 301 |
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is the area of the hall? | |
I. | Material cost of flooring per square metre is Rs. 2.50 |
II. | Labour cost of flooring the hall is Rs. 3500 |
III. | Total cost of flooring the hall is Rs. 14,500. |
I. Material cost = Rs. 2.50 per m2
II. Labour cost = Rs. 3500.
III. Total cost = Rs. 14,500.
Let the area be A sq. metres.
Material cost = Rs. (14500 - 3500) = Rs. 11,000.
|
5A | = 11000 A = |
![]() |
11000 x 2 | ![]() |
= 4400 m2. |
| 2 | 5 |
Thus, all I, II and III are needed to get the answer.
Correct answer is (C).
Let the thickness of the bottom be x cm.
Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000
320 x 250 x (110 - x) = 8000 x 1000
(110 - x) = |
8000 x 1000 | = 100 |
| 320 x 250 |
x = 10 cm = 1 dm.
. The rate of interest obtained is:
Investment = Rs. [20 x (50 - 5)] = Rs. 900.
Face value = Rs. (50 x 20) = Rs. 1000.
| Dividend = Rs. | ![]() |
27 | x | 1000 | ![]() |
= Rs. 135. |
| 2 | 100 |
| Interest obtained = | ![]() |
135 | x 100 | % |
= 15% |
| 900 |
The word 'OPTICAL' contains 7 different letters.
When the vowels OIA are always together, they can be supposed to form one letter.
Then, we have to arrange the letters PTCL (OIA).
Now, 5 letters can be arranged in 5! = 120 ways.
The vowels (OIA) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
| The banker's discount on a certain sum due 2 years hence is | 11 | of the true discount. |
| 10 |
The rate percent is:
Let T.D. be Re. 1.
| Then, B.D. = Rs. | 11 | = Rs. 1.10. |
| 10 |
Sum = Rs. |
![]() |
1.10 x 1 | ![]() |
= Rs. | ![]() |
110 | ![]() |
= Rs. 11. |
| 1.10 - 1 | 10 |
S.I. on Rs. 11 for 2 years is Rs. 1.10
Rate = |
![]() |
100 x 1.10 | % |
= 5%. |
| 11 x 2 |
Each number is the proceeding number multiplied by -2.
So, the required number is -128.
A x 2 + 1, B x 3 + 1, C x 2 + 1, D x 3 + 1 and so on.
So, 356 is wrong.
Go on multiplying with 1, 2, 3, 4, 5, 6 to get next number.
So, 96 is wrong.

