Online Aptitude Test - Aptitude Test - Random

Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.

Then, 4x + 6y =	1	and 3x + 7y =	1	.
	8		10

Solving the two equations, we get: x =	11	, y =	1
	400		400

1 woman's 1 day's work =	1	.
	400

10 women's 1 day's work =		1	x 10		=	1	.
		400				40

Hence, 10 women will complete the work in 40 days.

1 woman's 1 day's work =	1
	70

1 child's 1 day's work =	1
	140

(5 women + 10 children)'s day's work =		5	+	10		=		1	+	1		=	1
		70		140				14		14			7

5 women and 10 children will complete the work in 7 days.

Mother's age when Ayesha's brother was born = 36 years.

Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.

Required difference = (42 - 36) years = 6 years.

36 = 2² x 3²

84 = 2² x 3 x 7

H.C.F. = 2² x 3 = 12.

L.C.M. of 252, 308 and 198 = 2772.

So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.

To earn Rs.	50	, investment = Rs. 64.
	3

To earn Rs. 1500, investment = Rs.		64 x	3	x 1500		= Rs. 5760.
			50

Total weight increased = (8 x 2.5) kg = 20 kg.

Weight of new person = (65 + 20) kg = 85 kg.

Video Explanation: https://youtu.be/ceg2jvHsiJU

Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) =		7 x 6	x 3		= 63.
		2 x 1

At 4 o'clock, the hands of the watch are 20 min. spaces apart.

To be in opposite directions, they must be 30 min. spaces apart.

Minute hand will have to gain 50 min. spaces.

55 min. spaces are gained in 60 min.

50 min. spaces are gained in		60	x 50	min. or 54	6	min.
		55			11

Required time = 54	6	min. past 4.
	11

C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.

S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.

Gain =		80	x 100	% = 5%.
		1600

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.

Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).

		140	x 5x		,		150	x 7x		and		175	x 8x
		100					100					100

7x,	21x	and 14x.
	2

The required ratio = 7x :	21x	: 14x
	2

14x : 21x : 28x

2 : 3 : 4.

Perimeter = Distance covered in 8 min. =		12000	x 8	m = 1600 m.
		60

Let length = 3x metres and breadth = 2x metres.

Then, 2(3x + 2x) = 1600 or x = 160.

Length = 480 m and Breadth = 320 m.

Area = (480 x 320) m² = 153600 m².

Let the ten's and unit digit be x and	8	respectively.
	x

Then,		10x +	8		+ 18 = 10 x	8	+ x
			x			x

10x² + 8 + 18x = 80 + x²

9x² + 18x - 72 = 0

x² + 2x - 8 = 0

(x + 4)(x - 2) = 0

x = 2.

5% of A + 4% of B =	2	(6% of A + 8% of B)
	3

	5	A +	4	B	=	2		6	A +	8	B
	100		100			3		100		100

	1	A +	1	B	=	1	A +	4	B
	20		25			25		75

		1	-	1	A =		4	-	1	B
		20		25			75		25

	1	A =	1	B
	100		75

A	=	100	=	4	.
B		75		3

Required ratio = 4 : 3

Video Explanation: YouTube Video

Number of runs made by running = 110 - (3 x 4 + 8 x 6)

= 110 - (60)

= 50.

Required percentage =		50	x 100	% = 45	5	%
		110			11

Video Explanation: https://youtu.be/X2zTnABqEHU

Let the sum paid to Y per week be Rs. z.

Then, z + 120% of z = 550.

z +	120	z = 550
	100

	11	z = 550
	5

z =		550 x 5	= 250.
		11

x^z = y²       10^(0.48z) = 10^{(2 x 0.70)} = 10^1.40

0.48z = 1.40

z =	140	=	35	= 2.9 (approx.)
	48		12

2 x 5 = 10.

Sum of decimal places = 4

0.002 x 0.5 = 0.001

1 ÷ 0.2 =	1	=	10	= 5;
	0.2		2

0.2 = 0.222...;

(0.2)² = 0.04.

0.04 < 0.2 < 0.22....<5.

Since 0.04 is the least, so (0.2)² is the least.