Online Aptitude Test - Aptitude Test - Random
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- Total number of questions: 20.
- Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
The smallest 6-digit number 100000.
111) 100000 (900
999
-----
100
---
Required number = 100000 + (111 - 100)
= 100011.
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3
Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9
Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.
So, Option B is the answer.
987 = 3 x 7 x 47
So, the required number must be divisible by each one of 3, 7, 47
553681
(Sum of digits = 28, not divisible by 3)
555181
(Sum of digits = 25, not divisible by 3)
555681 is divisible by 3, 7, 47.
| Given Exp. = 666 x | 1 | x | 1 | = 37. |
| 6 | 3 |
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
| Original share of 1 person = | 1 |
| 8 |
| New share of 1 person = | 1 |
| 7 |
| Increase = | ![]() |
1 | - | 1 | ![]() |
= | 1 |
| 7 | 8 | 56 |
Required fraction = |
(1/56) | = | ![]() |
1 | x | 8 | ![]() |
= | 1 |
| (1/8) | 56 | 1 | 7 |
Let the price of a saree and a shirt be Rs. x and Rs. y respectively.
Then, 2x + 4y = 1600 .... (i)
and x + 6y = 1600 .... (ii)
Divide equation (i) by 2, we get the below equation.
=> x + 2y = 800. --- (iii)
Now subtract (iii) from (ii)
x + 6y = 1600 (-)
x + 2y = 800
----------------
4y = 800
----------------
Therefore, y = 200.
Now apply value of y in (iii)
=> x + 2 x 200 = 800
=> x + 400 = 800
Therefore x = 400
Solving (i) and (ii) we get x = 400, y = 200.
Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.
| C.P. of 30 articles = Rs. | ![]() |
5 | x 30 | ![]() |
= Rs. 25. |
| 6 |
| S.P. of 30 articles = Rs. | ![]() |
6 | x 30 | ![]() |
= Rs. 36. |
| 5 |
Gain % = |
![]() |
11 | x 100 | % = 44%. |
| 25 |
Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.
What is the percent profit earned by the shopkeeper on selling the articles in his shop? | |
I. | Labeled price of the articles sold was 130% of the cost price. |
II. | Cost price of each article was Rs. 550. |
III. | A discount of 10% on labeled price was offered. |
I. Let C.P. be Rs. x.
| Then, M.P. = 130% of x = Rs. | ![]() |
13x | . |
| 10 |
III. S.P. = 90% of M.P.
| Thus, I and III give, S.P. = Rs. | ![]() |
90 | x | 13x | ![]() |
= Rs. | ![]() |
117x | ![]() |
| 100 | 10 | 100 |
| Gain = Rs. | ![]() |
117x | - x | ![]() |
= Rs. | 17x |
| 100 | 100 |
Thus, from I and III, gain % can be obtained.
Clearly, II is redundant.
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
Ravi, Gagan and Nitin are running a business firm in partnership. What is Gagan's share in the profit earned by them? | |
I. | Ravi, Gagan and Nitin invested the amounts in the ratio of 2 : 4 : 7. |
II. | Nitin's share in the profit is Rs. 8750. |
Let us name Ravi, Gagan and Nitin by R, G and N respectively.
I. R : G : N = 2 : 4 : 7.
II. N = 8750..
From I and II, we get:
When N = 7, then G = 4.
| When N = 8750, then G = | ![]() |
4 | x 8750 | ![]() |
= 5000. |
| 7 |
Thus, both I and II are needed to get the answer.
Correct answer is (E).
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
| Work done by X in 8 days = | ![]() |
1 | x 8 | ![]() |
= | 1 | . |
| 40 | 5 |
| Remaining work = | ![]() |
1 - | 1 | ![]() |
= | 4 | . |
| 5 | 5 |
| Now, | 4 | work is done by Y in 16 days. |
| 5 |
| Whole work will be done by Y in | ![]() |
16 x | 5 | ![]() |
= 20 days. |
| 4 |
X's 1 day's work = |
1 | , Y's 1 day's work = | 1 | . |
| 40 | 20 |
| (X + Y)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 3 | . |
| 40 | 20 | 40 |
| Hence, X and Y will together complete the work in | ![]() |
40 | ![]() |
= 13 | 1 | days. |
| 3 | 3 |
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
| So, | x | + | (61 -x) | = 9 |
| 4 | 9 |
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
| Formula for converting from km/hr to m/s: X km/hr = | ![]() |
X x | 5 | ![]() |
m/s. |
| 18 |
| Therefore, Speed = | ![]() |
45 x | 5 | m/sec |
= | 25 | m/sec. |
| 18 | 2 |
Total distance to be covered = (360 + 140) m = 500 m.
| Formula for finding Time = | ![]() |
Distance | ![]() |
| Speed |
Required time = |
![]() |
500 x 2 | sec |
= 40 sec. |
| 25 |
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
Is a given rectangular block, a cube? | |
I. | At least 2 faces of the rectangular block are squares. |
II. | The volume of the block is 64. |
I gives, any two of l, b, h are equal.
II gives, lbh = 64.
From I and II, the values of l, b, h may be (1 ,1 , 64), (2 ,2 ,16), (4, 4, 4).
Thus, the block may be a cube or cuboid.
Correct answer is (D).
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
| While A covers 360 m, B covers | ![]() |
4 | x 360 | m |
= 480 m. |
| 3 |
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
A wins by 20 m.
Angle traced by hour hand in 12 hrs. = 360°.
| Angle traced by it in | 11 | hrs = | ![]() |
360 | x | 11 | ![]() |
° | = 110°. |
| 3 | 12 | 3 |
Angle traced by minute hand in 60 min. = 360°.
| Angle traced by it in 40 min. = | ![]() |
360 | x 40 | ![]() |
° | = 240°. |
| 60 |
Required angle (240 - 110)° = 130°.
| S.P. | = P.W. of Rs. 2200 due 1 year hence | |||||
|
||||||
| = Rs. 2000. |
Gain = Rs. (2000 - 1950) = Rs. 50.
Each number is a composite number except 11.



