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Instruction:

  • This is a FREE online test. DO NOT pay money to anyone to attend this test.
  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).


1.

The banker's discount of a certain sum of money is Rs. 72 and the true discount on the same sum for the same time is Rs. 60. The sum due is:

A.
Rs. 360
B.
Rs. 432
C.
Rs. 540
D.
Rs. 1080

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Sum = B.D. x T.D. = Rs. 72 x 60 = Rs. 72 x 60 = Rs. 360.
B.D. - T.D. 72 - 60 12

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2.

The G.C.D. of 1.08, 0.36 and 0.9 is:

A.
0.03
B.
0.9
C.
0.18
D.
0.108

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18,

H.C.F. of given numbers = 0.18.

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3.

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

A.
55
601
B.
601
55
C.
11
120
D.
120
11

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

The required sum = 1 + 1 = a + b = 55 = 11
a b ab 600 120

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4.

A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?

A.
Rs. 4991
B.
Rs. 5991
C.
Rs. 6001
D.
Rs. 6991

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

Required sale = Rs. [ (6500 x 6) - 34009 ]

   = Rs. (39000 - 34009)

   = Rs. 4991.

Video Explanation: https://youtu.be/tP4hszReksU

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5.

The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?

A.
76 kg
B.
76.5 kg
C.
85 kg
D.
Data inadequate
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Total weight increased = (8 x 2.5) kg = 20 kg.

Weight of new person = (65 + 20) kg = 85 kg.

Video Explanation: https://youtu.be/ceg2jvHsiJU

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6.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

A.
149 m
B.
156 m
C.
173 m
D.
200 m

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let AB be the tower.

Then, APB = 30° and AB = 100 m.

AB = tan 30° = 1
AP 3

AP = (AB x 3) m
= 1003 m
= (100 x 1.73) m
= 173 m.

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7.

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

A.
3
B.
10
C.
17
D.
20

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the number be x.

Then, x + 17 = 60
x

x2 + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3.

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8.

If one-third of one-fourth of a number is 15, then three-tenth of that number is:

A.
35
B.
36
C.
45
D.
54

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let the number be x.

Then, 1 of 1 of x = 15      x = 15 x 3 x 4 = 180.
3 4

So, required number = 3 x 180 = 54.
10

Video Explanation: https://youtu.be/z49OUnzTnwY

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9.

The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is:

A.
Rs. 400
B.
Rs. 500
C.
Rs. 600
D.
Rs. 800

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the sum be Rs. P.

Then, P 1 + 10 2 - P = 525
100

P 11 2 - 1 = 525
10

P = 525 x 100 = 2500.
21

Sum = Rs . 2500.

So, S.I. = Rs. 2500 x 5 x 4 = Rs. 500
100

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10.

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A.
2
B.
2 1
2
C.
3
D.
4

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000 1 + 7 n = 34347
100

107 n = 34347 = 11449 = 107 2
100 30000 10000 100

n = 2 years.

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11.

Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

A.
10 min. 20 sec.
B.
11 min. 45 sec.
C.
12 min. 30 sec.
D.
14 min. 40 sec.

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Part filled in 4 minutes = 4 1 + 1 = 7 .
15 20 15

Remaining part = 1 - 7 = 8 .
15 15

Part filled by B in 1 minute = 1
20

1 : 8 :: 1 : x
20 15

x = 8 x 1 x 20 = 10 2 min = 10 min. 40 sec.
15 3

The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.

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12.

Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit?

A.
Rs. 9,423
B.
Rs. 10,250
C.
Rs. 12,500
D.
Rs. 10,500

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.

Simran's share = Rs. 24500 x 3 = Rs. 10,500.
7

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13.

If ax = by, then:

A.
log a = x
b y
B.
log a = x
log b y
C.
log a = y
log b x
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

ax = by

log ax = log by

x log a = y log b

log a = y .
log b x

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14.

The value of 0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02 is:
0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04

A.
0.0125
B.
0.125
C.
0.25
D.
0.5

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Given expression = (0.1)3 + (0.02)3 = 1 = 0.125
23 [(0.1)3 + (0.02)3] 8

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15.

.009 = .01
?

A.
.0009
B.
.09
C.
.9
D.
9

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let .009 = .01;     Then x = .009 = .9 = .9
x .01 1

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16.

The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:

A.
12 years
B.
14 years
C.
18 years
D.
20 years

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

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17.

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

A.
2 times
B.
1 times
2
C.
3 times
4
D.
3 times

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

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Direction (for Q.No. 18):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

  • Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
  • Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
  • Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
  • Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
  • Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
18.

The towns A, B and C are on a straight line. Town C is between A and B. The distance from A to B is 100 km. How far is A from C?

I. 

The distance from A to B is 25% more than the distance from C to B.

 II. 

The distance from A to C is of the distance C to B.

A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

.__________.______________________________________.
A     x    C            (100 - x)                 B       

Let AC = x km. Then, CB = (100 -x) km.


 I. AB = 125% of CB

100 = 125 x (100 - x)
100

100 - x = 100 x 100 = 80
125

x = 20 km.

AC = 20 km.

Thus, I alone gives the answer.


II. AC = 1 CB
4

x = 1 (100 - x)
4

5x = 100

x = 20.

AC = 20 km.

Thus, II alone gives the answer.

Correct answer is (C).

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19.

A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is:

A.
4830
B.
5120
C.
6420
D.
8960

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Clearly, l = (48 - 16)m = 32 m,

b = (36 -16)m = 20 m,

h = 8 m.

Volume of the box = (32 x 20 x 8) m3 = 5120 m3.

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20.

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

A.
2%
B.
2.02%
C.
4%
D.
4.04%

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

100 cm is read as 102 cm.

A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.

(A2 - A1) = [(102)2 - (100)2]

= (102 + 100) x (102 - 100)

= 404 cm2.

Percentage error = 404 x 100 % = 4.04%
100 x 100

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