Online Aptitude Test - Aptitude Test - Random
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- Total number of questions: 20.
- Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3.
x = 2.
Largest 5-digit number = 99999
91) 99999 (1098
91
---
899
819
----
809
728
---
81
---
Required number = (99999 - 81)
= 99918.
Required sum = (2 + 4 + 6 + ... + 30)
This is an A.P. in which a = 2, d = (4 - 2) = 2 and l = 30.
Let the number of terms be n. Then,
tn = 30 
a + (n - 1)d = 30
2 + (n - 1) x 2 = 30
n - 1 = 14
n = 15
| Sn = |
n | (a + l) | = | 15 | x (2 + 30) = 240. |
| 2 | 2 |
20 x x = (64 + 36)(64 - 36) = 100 x 28
| x = |
100 x 28 | = 140 |
| 20 |
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
2 x 5 = 10.
Sum of decimal places = 4
0.002 x 0.5 = 0.001
1.5625 = ?
1|1.5625( 1.25
|1
|-------
22| 56
| 44
|-------
245| 1225
| 1225
|-------
| X
|-------
1.5625 = 1.25.
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
xz = y2 
10(0.48z) = 10(2 x 0.70) = 101.40
0.48z = 1.40
| z = |
140 | = | 35 | = 2.9 (approx.) |
| 48 | 12 |
| S.P. = 85% of Rs. 1400 = Rs. |  |
85 | x 1400 |  |
= Rs. 1190 |
| 100 |
Video Explanation: https://youtu.be/jn0XIafQvAc
| Part filled by (A + B) in 1 minute = | |
1 | + | 1 | |
= | 1 | . |
| 60 | 40 | 24 |
Suppose the tank is filled in x minutes.
| Then, | x | |
1 | + | 1 | |
= 1 |
| 2 | 24 | 40 |
| |
x | x | 1 | = 1 |
| 2 | 15 |
x = 30 min.
Suppose pipe A alone takes x hours to fill the tank.
| Then, pipes B and C will take | x | and | x | hours respectively to fill the tank. |
| 2 | 4 |
| |
1 | + | 2 | + | 4 | = | 1 |
| x | x | x | 5 |
| |
7 | = | 1 |
| x | 5 |
x = 35 hrs.
of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.
| Time taken = 1 hr 40 min 48 sec = 1 hr 40 | 4 | min = 1 | 51 | hrs = | 126 | hrs. |
| 5 | 75 | 75 |
Let the actual speed be x km/hr.
| Then, | 5 | x x | 126 | = 42 |
| 7 | 75 |
| x = |
|
42 x 7 x 75 | |
= 35 km/hr. |
| 5 x 126 |
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
| So, | x | + | (61 -x) | = 9 |
| 4 | 9 |
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 15 y = |
x | . |
| y | 15 |
|
x + 100 | = | x |
| 25 | 15 |
15(x + 100) = 25x
15x + 1500 = 25x
1500 = 10x
x = 150 m.
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
What is the speed of the boat in still water? | |
I. | The boat covers a distance of 48 kms in 6 hours while running upstream. |
II. | The boat covers the same distance in 4 hours while running downstream. |
| I. Speed upstream = | 48 | km/hr = 8 km/hr. |
| 6 |
| II. Speed downstream = | 48 | km/hr = 12 km/hr. |
| 4 |
| Speed of the boat = | 1 | (8 + 12) km/hr = 10 km/hr. |
| 2 |
Thus, I and II together give the answer.
Correct answer is (E).
| Amount |
|
||||||||||||||||
|
|||||||||||||||||
|
|||||||||||||||||
|
|||||||||||||||||
| = Rs. 3321. |
C.I. = Rs. (3321 - 3200) = Rs. 121
| A's speed = | |
5 x | 5 | m/sec |
= | 25 | m/sec. |
| 18 | 18 |
| Time taken by A to cover 100 m = | |
100 x | 18 | sec |
= 72 sec. |
| 25 |
Time taken by B to cover 92 m = (72 + 8) = 80 sec.
| B's speed = |
|
92 | x | 18 | kmph |
= 4.14 kmph. |
| 80 | 5 |
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
| P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Go on dividing by 4 to get the next number.
So, 200 is wrong.