Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
75 comments Page 1 of 8.
Frio said:
5 months ago
Thanks all for the explanation.
(2)
Bijip said:
10 months ago
Why we will take co-prime here? Please explain me.
(8)
Vaibhavi said:
2 years ago
Let the numbers be 37a × 37b
Then, 37a × 37b = 4107.
37ab = 4107/37,
37ab = 111,
ab = 111/37.
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
The Greater number = 111.
Then, 37a × 37b = 4107.
37ab = 4107/37,
37ab = 111,
ab = 111/37.
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
The Greater number = 111.
(20)
MANJULADEVI K said:
2 years ago
The product of 2 number is 4107.
The HCF of these number is 37.
4107= 37 * a
4107/37 = a
Answer is 111.
The HCF of these number is 37.
4107= 37 * a
4107/37 = a
Answer is 111.
(71)
Omprakash said:
3 years ago
Thanks, everyone.
(5)
Srivani said:
3 years ago
How you get ab=3? please explain.
(9)
Mayur said:
3 years ago
Simple;
HCF*LCM = PRODUCT.
37 * 111 = 4107.
HCF*LCM = PRODUCT.
37 * 111 = 4107.
(30)
Gopi said:
3 years ago
37 * x = 4107.
x = 111.
x = 111.
(6)
Mouni said:
3 years ago
HCF=37
The product of two no's=4107
37 * x = 4107, where x=greatest no
x = 4107%37 = 111.
The product of two no's=4107
37 * x = 4107, where x=greatest no
x = 4107%37 = 111.
(3)
Nilay said:
4 years ago
Thank you @Shilpa.
(1)
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