Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 2 of 8.
Nilay said:
4 years ago
Thank you @Shilpa.
(1)
Hemanth reddy said:
4 years ago
AB = hcf * lcm.
4107 = 37 * x.
X = 4107/37.
Lcm = 111.
We know that lcm is always greater than HCF.
So the greatest number is 111.
In case the smallest number is 37.
4107 = 37 * x.
X = 4107/37.
Lcm = 111.
We know that lcm is always greater than HCF.
So the greatest number is 111.
In case the smallest number is 37.
(13)
Shilpa said:
4 years ago
Co prime means the only common factor of two numbers is 1.
For this problem, let the numbers be 37a and 37b as we know both numbers is multiple of 37.
So, 37a*37b = 4107.
37ab = 111,
ab=3.
Here there's only one way to split 3. Ie 1*3 or 3*1.
So let a=1 and b=3.
Numbers are 37a and 37b.
Substitute the value for a and b.
37*1=37 and 37*3=111.
Here the highest number is 111.
Hence the answer is 111.
For this problem, let the numbers be 37a and 37b as we know both numbers is multiple of 37.
So, 37a*37b = 4107.
37ab = 111,
ab=3.
Here there's only one way to split 3. Ie 1*3 or 3*1.
So let a=1 and b=3.
Numbers are 37a and 37b.
Substitute the value for a and b.
37*1=37 and 37*3=111.
Here the highest number is 111.
Hence the answer is 111.
(13)
Sharad said:
5 years ago
When we find the LCM as 111, why does it mean that one of the number is 111 and the other is 37. They are just factors and multiples. Please anyone explain.
Marisankar said:
6 years ago
What is co-prime?
Shoaib nadaf said:
6 years ago
Hcf x lcm = Product .
37 x X = 4107.
X = 4107/37 = 111 answer.
37 x X = 4107.
X = 4107/37 = 111 answer.
Sai vamsi said:
6 years ago
x*y = 4107.
Hcf of two nums is 37. So these two nums are divisible by 37.
37x*37y = 4107.
37(x*y) = 4107.
x*y = 4107/37 = 111.
Hcf of two nums is 37. So these two nums are divisible by 37.
37x*37y = 4107.
37(x*y) = 4107.
x*y = 4107/37 = 111.
Harwani Payal said:
6 years ago
Assume Two numbers p and q.
Multiply them with 37.
37p*37p.
Now, 37p*37p = 4107.
1369pq = 4107.
pq = 4107/1369.
pq = 3.
Multiply them with 37.
37p*37p.
Now, 37p*37p = 4107.
1369pq = 4107.
pq = 4107/1369.
pq = 3.
Nidhu said:
6 years ago
We know that;
H.C.F * L.C.M = product of two numbers.
37* x = 4107,
x=4107/37,
x = 111.
H.C.F * L.C.M = product of two numbers.
37* x = 4107,
x=4107/37,
x = 111.
Manikanta said:
7 years ago
For a*b =3. So.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
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