Online Aptitude Test - Aptitude Test 9
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- Total number of questions: 20.
- Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
Video Explanation: https://youtu.be/ceg2jvHsiJU
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Total number of votes polled = (1136 + 7636 + 11628) = 20400.
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11628 | x 100 | ![]() |
20400 |
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
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295 | x 100 | ![]() |
= | 1475 | % = 70% (approximately). |
420 | 21 |
Video Explanation: https://youtu.be/bQA8SB8ycbw
Cost of x metres = Rs. d.
Cost of 1 metre = Rs. | ![]() |
d | ![]() |
x |
Cost of y metres = Rs. | ![]() |
d | . y | ![]() |
= Rs. | ![]() |
yd | ![]() |
x | x |
Let the height of the building x metres.
Less lengthy shadow, Less in the height (Direct Proportion)
40.25 : 28.75 :: 17.5 : x
40.25 x x = 28.75 x 17.5
x = | 28.75 x 17.5 |
40.25 |
x = 12.5
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
In how many days can 10 women finish a work? | |||||
I. | 10 men can complete the work in 6 days. | ||||
II. |
| ||||
III. | If 10 men work for 3 days and thereafter 10 women replace them, the remaining work in completed in 4 days. |
I. (10 x 6) men can complete the work in 1 day.
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1 |
60 |
II. | ![]() |
10 x | 24 | ![]() |
men + | ![]() |
10 x | 24 | ![]() |
women can complete the work in 1 day. |
7 | 7 |
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240 | ![]() |
men's 1 day work + | ![]() |
240 | ![]() |
women's 1 day work = 1. |
7 | 7 |
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240 | x | 1 | ![]() |
+ | ![]() |
240 | ![]() |
women's 1 day's work = 1. |
7 | 60 | 7 |
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240 | ![]() |
women's 1 day's work = | ![]() |
1 - | 4 | ![]() |
= | 3 |
7 | 7 | 7 |
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3 | x | 7 | x 10 | ![]() |
= | 1 |
7 | 240 | 8 |
So, 10 women can finish the work in 8 days.
III. (10 men's work for 3 days) + (10 women's work for 4 days) = 1
(10 x 3) men's 1 day's work + (10 x 4) women's 1 day's work = 1
30 men's 1 day's work + 40 women's 1 day's work = 1
Thus, I and III will give us the answer.
And, II and III will give us the answer.
Correct answer is (A).
Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.
8 men and 14 women are working together in a field. After working for 3 days, 5 men and 8 women leave the work. How many more days will be required to complete the work? | |
I. | 19 men and 12 women together can complete the work in 18 days. |
II. | 16 men can complete two-third of the work in 16 days. |
III. | In 1 day, the work done by three men in equal to the work done by four women. |
Clearly, I only gives the answer.
Similarly, II only gives the answer.
And, III only gives the answer.
Correct answer is (D).
Let original length = x and original breadth = y.
Decrease in area |
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7 | xy x | 1 | x 100 | ![]() |
= 28%. |
25 | xy |
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
What is the capacity of a cylindrical tank? | |
I. | Radius of the base is half of its height which is 28 metres. |
II. | Area of the base is 616 sq. metres and its height is 28 metres. |
I gives, h = 28 m and r = 14.
Capacity =
r2h, which can be obtained.
Thus, I alone gives the answer.
II gives, r2 = 616 m2 and h = 28 m.
Capacity = (
r2 x h) = (616 x 28) m3.
Thus, II alone gives the answer.
Correct answer is (C).
Distance covered by B in 9 sec. = | ![]() |
100 | x 9 | ![]() |
= 20 m. |
45 |
A beats B by 20 metres.
For an income of Rs. 8, investment = Rs. 100.
For an income of Rs. 6, investment = Rs. | ![]() |
100 | x 6 | ![]() |
= Rs. 75. |
8 |
Market value of Rs. 100 stock = Rs. 75.
We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).
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= (3C1 x 6C2) + (3C2 x 6C1) + (3C3) | |||||||||||||
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= (45 + 18 + 1) | ||||||||||||||
= 64. |
S.I. on Rs. 100 for double the time = Rs. 20.
T.D. on Rs. 120 = Rs. (120 - 100) = Rs. 20.
T.D. on Rs. 110 = Rs. | ![]() |
20 | x 110 | ![]() |
= Rs. 18.33 |
120 |
1, 1 + 12 = 2, 2 + 22 = 6, 6 + 32 = 15, 15 + 42 = 31, 31 + 52 = 56, 56 + 62 = 92
Last number of given series must be 92 not 91.
Numbers are (23 - 1), (33 - 1), (43 - 1), (53 - 1), (63 - 1), (73 - 1) etc.
So, the next number is (83 - 1) = (512 - 1) = 511.