# Aptitude - Chain Rule - Discussion

Discussion Forum : Chain Rule - General Questions (Q.No. 2)

2.

If the cost of

*x*metres of wire is d rupees, then what is the cost of*y*metres of wire at the same rate?Answer: Option

Explanation:

Cost of *x* metres = Rs. d.

Cost of 1 metre = Rs. | d |
||

x |

Cost of y metres = Rs. |
d |
. y |
= Rs. | yd |
. | |||

x |
x |

Discussion:

15 comments Page 1 of 2.
Damilare james said:
2 years ago

I think the right answer is Rs.(yd).

(3)

Damilare james said:
2 years ago

I don't understand this. Please explain the answer in detail.

(1)

Mayank Kumar said:
4 years ago

Thanks everyone for explaining.

(1)

Chandrakala said:
5 years ago

According to me, the answer is xy/d.

(1)

Sundaresh said:
8 years ago

x = 5 meters d = 10rupees

y = 7 then d = ?

10/5 = 2; 2 * 7 = 14.

How to get this mean d/x *y?

y = 7 then d = ?

10/5 = 2; 2 * 7 = 14.

How to get this mean d/x *y?

(1)

Nikhil yamalwar said:
8 years ago

X/d = y/?

suppose ? = p, then cross multiplication.

You will get ans: x*p = yd.

P = (yd/x).

suppose ? = p, then cross multiplication.

You will get ans: x*p = yd.

P = (yd/x).

(1)

Manikandan said:
9 years ago

We know cost of x is d then y is using matrix multiplication format.

Kharinagendra said:
9 years ago

X meters.....d rupees.

Y meters......?

Then cross multiplication yd/x.

Y meters......?

Then cross multiplication yd/x.

Rajini said:
9 years ago

We know the cost of x rupees is d meters cost of one meter is d/x cost of y meters is d/x*y.

Parameswaran.G said:
1 decade ago

We known X and D,

Then we need Y meters of wire.

Let as,

WE GET ANSWER =(D/X)* Y.

Then we need Y meters of wire.

Let as,

WE GET ANSWER =(D/X)* Y.

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