# Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)

4.

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Answer: Option

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Discussion:

144 comments Page 1 of 15.
Krishnakanth said:
1 month ago

Given numbers 1305, 4665, 6905.

Now take difference;

4665 - 1305 = 3360,

6905 - 4665 = 2240,

6905 - 1305 = 5600.

3360 factor it will give you 4,4,10,7 all divisible by the other 2 numbers.

So, multiple them and you will get 1120 add them because in question they said digits give you 4 i.e answer.

Now take difference;

4665 - 1305 = 3360,

6905 - 4665 = 2240,

6905 - 1305 = 5600.

3360 factor it will give you 4,4,10,7 all divisible by the other 2 numbers.

So, multiple them and you will get 1120 add them because in question they said digits give you 4 i.e answer.

(1)

Sumit said:
10 months ago

If we only take two differences i.e. 6905 - 4665 = 2240, 4665 - 1305 = 2360.

HCF of 2240 and 2360 is 40.

4+0 = 4.

HCF of 2240 and 2360 is 40.

4+0 = 4.

(4)

Ashu said:
11 months ago

Thanks for explaining @Saraswati.

(2)

Komal said:
1 year ago

Thank you for explaining the answer @Greeshma.

Barath dasari said:
1 year ago

(1305 - 4665) = 3360.

(4665 - 6905 ) = 2240.

( 6905 - 1305) = 5600.

Then HCF Of 3360 - 3 * 1120,

HCF Of 2240 - 2 * 1120,

HCF Of 5600 - 5 * 1120,

Sum Of Digits in N = 1 + 1 + 2 + 0 = 4.

I hope it's easy to understand.

(4665 - 6905 ) = 2240.

( 6905 - 1305) = 5600.

Then HCF Of 3360 - 3 * 1120,

HCF Of 2240 - 2 * 1120,

HCF Of 5600 - 5 * 1120,

Sum Of Digits in N = 1 + 1 + 2 + 0 = 4.

I hope it's easy to understand.

(6)

Aswini said:
2 years ago

@All.

So most of you people asked how (4665- 1305) (4665-6905) ( 6905- 1305).

So, By using (b-a) (b-c) (c-a) formula.

Given. a= 1305 , b=4665 c= 6905.

So most of you people asked how (4665- 1305) (4665-6905) ( 6905- 1305).

So, By using (b-a) (b-c) (c-a) formula.

Given. a= 1305 , b=4665 c= 6905.

(1)

Anomi said:
2 years ago

When these numbers are divided by 5 then the remainder is zero right. Then the Answer should be 5 right. Please explain to me.

(1)

Elissa said:
2 years ago

I understood well, thanks to all for explaining.

(1)

Deeksha said:
2 years ago

Good, Thanks you @Greeshma.

K.snigdha shree said:
2 years ago

Thanks all for epxlaining.

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