Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)
4.
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Answer: Option
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Discussion:
147 comments Page 1 of 15.
Suraj Chaudhary said:
1 month ago
I can't understand this question properly.
So, please If anybody knows properly it. Please explain it.
So, please If anybody knows properly it. Please explain it.
Gourav said:
3 months ago
@Anomi
Here, we need to find the greatest number. So 5 is not the greatest number.
Here, we need to find the greatest number. So 5 is not the greatest number.
(2)
Agondeze milly said:
4 months ago
How do you get 4? I am not getting it clearly.
(6)
Krishnakanth said:
7 months ago
Given numbers 1305, 4665, 6905.
Now take difference;
4665 - 1305 = 3360,
6905 - 4665 = 2240,
6905 - 1305 = 5600.
3360 factor it will give you 4,4,10,7 all divisible by the other 2 numbers.
So, multiple them and you will get 1120 add them because in question they said digits give you 4 i.e answer.
Now take difference;
4665 - 1305 = 3360,
6905 - 4665 = 2240,
6905 - 1305 = 5600.
3360 factor it will give you 4,4,10,7 all divisible by the other 2 numbers.
So, multiple them and you will get 1120 add them because in question they said digits give you 4 i.e answer.
(10)
Sumit said:
1 year ago
If we only take two differences i.e. 6905 - 4665 = 2240, 4665 - 1305 = 2360.
HCF of 2240 and 2360 is 40.
4+0 = 4.
HCF of 2240 and 2360 is 40.
4+0 = 4.
(13)
Ashu said:
1 year ago
Thanks for explaining @Saraswati.
(3)
Komal said:
2 years ago
Thank you for explaining the answer @Greeshma.
(1)
Barath dasari said:
2 years ago
(1305 - 4665) = 3360.
(4665 - 6905 ) = 2240.
( 6905 - 1305) = 5600.
Then HCF Of 3360 - 3 * 1120,
HCF Of 2240 - 2 * 1120,
HCF Of 5600 - 5 * 1120,
Sum Of Digits in N = 1 + 1 + 2 + 0 = 4.
I hope it's easy to understand.
(4665 - 6905 ) = 2240.
( 6905 - 1305) = 5600.
Then HCF Of 3360 - 3 * 1120,
HCF Of 2240 - 2 * 1120,
HCF Of 5600 - 5 * 1120,
Sum Of Digits in N = 1 + 1 + 2 + 0 = 4.
I hope it's easy to understand.
(27)
Aswini said:
2 years ago
@All.
So most of you people asked how (4665- 1305) (4665-6905) ( 6905- 1305).
So, By using (b-a) (b-c) (c-a) formula.
Given. a= 1305 , b=4665 c= 6905.
So most of you people asked how (4665- 1305) (4665-6905) ( 6905- 1305).
So, By using (b-a) (b-c) (c-a) formula.
Given. a= 1305 , b=4665 c= 6905.
(5)
Anomi said:
2 years ago
When these numbers are divided by 5 then the remainder is zero right. Then the Answer should be 5 right. Please explain to me.
(2)
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