Online Aptitude Test - Aptitude Test 10

Suppose commodity X will cost 40 paise more than Y after z years.

Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40

0.25z = 0.40 + 2.10

z =	2.50	=	250	= 10.
	0.25		25

X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.

Let the number of students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10      x - y = 20 .... (i)

     and x + 20 = 2(y - 20)      x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = 100 , y = 80.

The required answer A = 100.

2ab = (a² + b²) - (a - b)²

   = 29 - 9 = 20

   ab = 10.

Let the numbers be x and y.

Then, xy = 120 and x² + y² = 289.

(x + y)² = x² + y² + 2xy = 289 + (2 x 120) = 529

x + y = 529 = 23.

Let A = 2k, B = 3k and C = 5k.

A's new salary =	115	of 2k =		115	x 2k		=	23k
	100			100				10

B's new salary =	110	of 3k =		110	x 3k		=	33k
	100			100				10

C's new salary =	120	of 5k =		120	x 5k		= 6k
	100			100

New ratio		23k	:	33k	: 6k		= 23 : 33 : 60
		10		10

A : B =

4x x 3 +

4x -

1

x 4x

x 7

:

5x x 3 +

5x -

1

x 5x

x 7

4

5

   = (12x + 21x) : (15x + 28x)

   = 33x :43x

   = 33 : 43.

A's share = Rs.		760 x	33		= Rs. 330.
			76

From I, II and III, we get P : Q : R = (120000 x 8) : (80000 x 12) : (x x 9).

Since R's investment is not given, the above ratio cannot be give.

Given data is inadequate.

C's 1 day's work =	1	-		1	+	1		=	1	-	7	=	1	.
	3			6		8			3		24		24

A's wages : B's wages : C's wages =	1	:	1	:	1	= 4 : 3 : 1.
	6		8		24

C's share (for 3 days) = Rs.		3 x	1	x 3200		= Rs. 400.
			24

Speed =		72 x	5	m/sec	= 20 m/sec.
			18

Time = 26 sec.

Let the length of the train be x metres.

Then,	x + 250	= 20
	26

x + 250 = 520

x = 270.

100 cm is read as 102 cm.

A₁ = (100 x 100) cm² and A₂ (102 x 102) cm².

(A₂ - A₁) = [(102)² - (100)²]

Percentage error =		404	x 100	%	= 4.04%
		100 x 100

1 hectare = 10,000 m²

So, Area = (1.5 x 10000) m² = 15000 m².

Depth =	5	m	=	1	m.
	100			20

Volume = (Area x Depth) =		15000 x	1	m3	= 750 m3.
			20

Video Explanation: https://youtu.be/dDbVuBzYop8

Let each edge be a metres. Then,

I. a² = 64       a = 8 m       Volume = (8 x 8 x 8) m³ = 512 m³.

Thus, I alone gives the answer.

II. a = 8 m       Volume = (8 x 8 x 8) m³ = 512 m³.

Thus, II alone gives the answer.

Correct answer is (C).

Angle traced by hour hand in	125	hrs =		360	x	125		°	= 312	1	°	.
	12			12		12				2

Angle traced by minute hand in 25 min =		360	x 25		°	= 150°.
		60

Reflex angle = 360° -		312	1	- 150		°	= 360° - 162	1	°	= 197	1°	.
			2					2			2

At 4 o'clock, the hands of the watch are 20 min. spaces apart.

To be in opposite directions, they must be 30 min. spaces apart.

Minute hand will have to gain 50 min. spaces.

55 min. spaces are gained in 60 min.

50 min. spaces are gained in		60	x 50	min. or 54	6	min.
		55			11

Required time = 54	6	min. past 4.
	11

To earn Rs. 10, money invested = Rs. 100.

To earn Rs. 12, money invested = Rs.		100	x 12		= Rs. 120.
		10

Market value of Rs. 100 stock = Rs. 120.

There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.

Let us mark these positions as under:

(1) (2) (3) (4) (5) (6)

Now, 3 vowels can be placed at any of the three places out 4, marked 1, 3, 5.

Number of ways of arranging the vowels = ³P₃ = 3! = 6.

Also, the 3 consonants can be arranged at the remaining 3 positions.

Number of ways of these arrangements = ³P₃ = 3! = 6.

Total number of ways = (6 x 6) = 36.

Clearly, n(S) = (6 x 6) = 36.

Let E = Event that the sum is a prime number.

Then E

= { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3),       (5, 2), (5, 6), (6, 1), (6, 5) }

n(E) = 15.

P(E) =	n(E)	=	15	=	5	.
	n(S)		36		12

Let AB be the observer and CD be the tower.

Draw BE CD.

Then, CE = AB = 1.6 m,

      BE = AC = 203 m.

DE	= tan 30° =	1
BE		3

DE =	203	m = 20 m.
	3

CD = CE + DE = (1.6 + 20) m = 21.6 m.