Online Aptitude Test - Aptitude Test 10
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- Total number of questions: 20.
- Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
z = | 2.50 | = | 250 | = 10. |
0.25 | 25 |
X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
2ab = (a^{2} + b^{2}) - (a - b)^{2}
= 29 - 9 = 20
ab = 10.
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Let the numbers be x and y.
Then, xy = 120 and x^{2} + y^{2} = 289.
(x + y)^{2} = x^{2} + y^{2} + 2xy = 289 + (2 x 120) = 529
x + y = 529 = 23.
Let A = 2k, B = 3k and C = 5k.
A's new salary = | 115 | of 2k = | 115 | x 2k | = | 23k | ||
100 | 100 | 10 |
B's new salary = | 110 | of 3k = | 110 | x 3k | = | 33k | ||
100 | 100 | 10 |
C's new salary = | 120 | of 5k = | 120 | x 5k | = 6k | ||
100 | 100 |
New ratio | 23k | : | 33k | : 6k | = 23 : 33 : 60 | ||
10 | 10 |
A : B = | 4x x 3 + | 4x - | 1 | x 4x | x 7 | : | 5x x 3 + | 5x - | 1 | x 5x | x 7 | ||||||||
4 | 5 |
= (12x + 21x) : (15x + 28x)
= 33x :43x
= 33 : 43.
A's share = Rs. | 760 x | 33 | = Rs. 330. | ||
76 |
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is R's share of profit in a joit venture? | |
I. | Q started business investing Rs. 80,000. |
II. | R joined him after 3 months. |
III. | P joined after 4 months with a capital of Rs. 1,20,000 and got Rs. 6000 as his share profit. |
From I, II and III, we get P : Q : R = (120000 x 8) : (80000 x 12) : (x x 9).
Since R's investment is not given, the above ratio cannot be give.
Given data is inadequate.
C's 1 day's work = | 1 | - | 1 | + | 1 | = | 1 | - | 7 | = | 1 | . | ||
3 | 6 | 8 | 3 | 24 | 24 |
A's wages : B's wages : C's wages = | 1 | : | 1 | : | 1 | = 4 : 3 : 1. |
6 | 8 | 24 |
C's share (for 3 days) = Rs. | 3 x | 1 | x 3200 | = Rs. 400. | ||
24 |
Speed = | 72 x | 5 | m/sec | = 20 m/sec. | |
18 |
Time = 26 sec.
Let the length of the train be x metres.
Then, | x + 250 | = 20 |
26 |
x + 250 = 520
x = 270.
log_{2} 10 = | 1 | = | 1 | = | 10000 | = | 1000 | . |
log_{10} 2 | 0.3010 | 3010 | 301 |
100 cm is read as 102 cm.
A_{1} = (100 x 100) cm^{2} and A_{2} (102 x 102) cm^{2}.
(A_{2} - A_{1}) = [(102)^{2} - (100)^{2}]
= (102 + 100) x (102 - 100)
= 404 cm^{2}.
Percentage error = | 404 | x 100 | % | = 4.04% | |
100 x 100 |
1 hectare = 10,000 m^{2}
So, Area = (1.5 x 10000) m^{2} = 15000 m^{2}.
Depth = | 5 | m | = | 1 | m. |
100 | 20 |
Volume = (Area x Depth) = | 15000 x | 1 | m^{3} | = 750 m^{3}. | |
20 |
Video Explanation: https://youtu.be/dDbVuBzYop8
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
What is the volume of a cube? | |
I. | The area of each face of the cube is 64 square metres. |
II. | The length of one side of the cube is 8 metres. |
Let each edge be a metres. Then,
I. a^{2} = 64 a = 8 m Volume = (8 x 8 x 8) m^{3} = 512 m^{3}.
Thus, I alone gives the answer.
II. a = 8 m Volume = (8 x 8 x 8) m^{3} = 512 m^{3}.
Thus, II alone gives the answer.
Correct answer is (C).
Angle traced by hour hand in | 125 | hrs = | 360 | x | 125 | ° | = 312 | 1 | ° | . | ||
12 | 12 | 12 | 2 |
Angle traced by minute hand in 25 min = | 360 | x 25 | ° | = 150°. | ||
60 |
Reflex angle = 360° - | 312 | 1 | - 150 | ° | = 360° - 162 | 1 | ° | = 197 | 1° | . | ||
2 | 2 | 2 |
At 4 o'clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min.
50 min. spaces are gained in | 60 | x 50 | min. or 54 | 6 | min. | |
55 | 11 |
Required time = 54 | 6 | min. past 4. |
11 |
To earn Rs. 10, money invested = Rs. 100.
To earn Rs. 12, money invested = Rs. | 100 | x 12 | = Rs. 120. | ||
10 |
Market value of Rs. 100 stock = Rs. 120.
There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.
Let us mark these positions as under:
(1) (2) (3) (4) (5) (6)
Now, 3 vowels can be placed at any of the three places, marked 1, 3, 5.
Number of ways of arranging the vowels = ^{3}P_{3} = 3! = 6.
Also, the 3 consonants can be arranged at the remaining 3 positions.
Number of ways of these arrangements = ^{3}P_{3} = 3! = 6.
Total number of ways = (6 x 6) = 36.
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E | = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) } |
n(E) = 15.
P(E) = | n(E) | = | 15 | = | 5 | . |
n(S) | 36 | 12 |
Let AB be the observer and CD be the tower.
Draw BE CD.
Then, CE = AB = 1.6 m,
BE = AC = 203 m.
DE | = tan 30° = | 1 |
BE | 3 |
DE = | 203 | m = 20 m. |
3 |
CD = CE + DE = (1.6 + 20) m = 21.6 m.