Discussion :: Logarithm  General Questions (Q.No.7)
7.  If log_{10} 2 = 0.3010, then log_{2} 10 is equal to: 

Answer: Option B Explanation:

Melissa Ramnauth said: (Oct 23, 2011)  
I do not understand how you get 10000 divided (over) 3010 giving it a result of 1000 divided (over) 301. 
Rajeev said: (Dec 8, 2011)  
We know that change based of log. Log2 10 written as log10 10 divided by log10 2. We have a value of log10 2. So simple calculation. 
Arun said: (Feb 20, 2014)  
log(a) X =log X/log a using this formula we can solve.. log(10) 2 = 0.3010. Using that formula we can write log 2/log 10=0.3010. So take reciprocal log 10/log 2 = 1/0.3010...use the first line formula log(10) 2 = log 10/log 2 [i.e.log(a) X = log X/log a]=1/0.3010 = 1/3*10power of 4 = 10000/3010 = 1000/301. 
Puneet said: (Sep 4, 2016)  
Why not answer is 0.6990? 
Muhammad Asif said: (Oct 10, 2016)  
Please explain me, I didn't understand. 
Ravi said: (Dec 3, 2016)  
B is right. I agree with that. 
I.Kiran Kumar said: (Dec 17, 2016)  
Please explain it, I didn't understand. 
Lavanyageetha said: (May 19, 2017)  
What is the answer for this question? Log 64 base 16 log 16 base 64? 
Chand said: (Jul 3, 2018)  
How 10000 came? Please explain it. 
Sanjay said: (Jul 7, 2018)  
0.3010 is in decimals, to remove decimals we add zeros. 
Mahalakshmi said: (Sep 5, 2018)  
How these base can be changed over here please explain? 
Shiv said: (Oct 6, 2018)  
Simply log2^10 is reciprocal of log 10^2 so, log2^10=1/log10^2. =1/0.3010=10000/3010(removing decimal), =1000/301. 
Sagor said: (Jan 1, 2019)  
We know, loga M= logb M ÷ logb a, so, log2 10= log10 10 ÷ log10 2 [here b= 10], =1 ÷ 0.3010, =10000 ÷ 3010, =1000/301. 
Sydha said: (Jan 17, 2019)  
I am not getting the answer, please explain it. 
Pandichitra said: (Mar 28, 2019)  
Thanks @Sagor. 
Navya said: (May 7, 2019)  
I can't understand this problem. Please explain in detail. 
Karma said: (Sep 21, 2019)  
@Chand. To remove a decimal, we multiply both the numerator and denominator by 10000. 
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