Discussion :: Logarithm - General Questions (Q.No.7)
| 7. | If log10 2 = 0.3010, then log2 10 is equal to: |
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Answer: Option B Explanation:
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| Melissa Ramnauth said: (Oct 23, 2011) | |
| I do not understand how you get 10000 divided (over) 3010 giving it a result of 1000 divided (over) 301. | |
| Rajeev said: (Dec 8, 2011) | |
| We know that change based of log. Log2 10 written as log10 10 divided by log10 2. We have a value of log10 2. So simple calculation. |
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| Arun said: (Feb 20, 2014) | |
| log(a) X =log X/log a using this formula we can solve.. log(10) 2 = 0.3010. Using that formula we can write log 2/log 10=0.3010. So take reciprocal log 10/log 2 = 1/0.3010...use the first line formula log(10) 2 = log 10/log 2 [i.e.log(a) X = log X/log a]=1/0.3010 = 1/3*10power of -4 = 10000/3010 = 1000/301. |
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| Puneet said: (Sep 4, 2016) | |
| Why not answer is 0.6990? | |
| Muhammad Asif said: (Oct 10, 2016) | |
| Please explain me, I didn't understand. | |
| Ravi said: (Dec 3, 2016) | |
| B is right. I agree with that. | |
| I.Kiran Kumar said: (Dec 17, 2016) | |
| Please explain it, I didn't understand. | |
| Lavanyageetha said: (May 19, 2017) | |
| What is the answer for this question? Log 64 base 16- log 16 base 64? |
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| Chand said: (Jul 3, 2018) | |
| How 10000 came? Please explain it. | |
| Sanjay said: (Jul 7, 2018) | |
| 0.3010 is in decimals, to remove decimals we add zeros. | |
| Mahalakshmi said: (Sep 5, 2018) | |
| How these base can be changed over here please explain? | |
| Shiv said: (Oct 6, 2018) | |
| Simply log2^10 is reciprocal of log 10^2 so, log2^10=1/log10^2. =1/0.3010=10000/3010(removing decimal), =1000/301. |
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| Sagor said: (Jan 1, 2019) | |
| We know, loga M= logb M ÷ logb a, so, log2 10= log10 10 ÷ log10 2 [here b= 10], =1 ÷ 0.3010, =10000 ÷ 3010, =1000/301. |
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| Sydha said: (Jan 17, 2019) | |
| I am not getting the answer, please explain it. | |
| Pandichitra said: (Mar 28, 2019) | |
| Thanks @Sagor. | |
| Navya said: (May 7, 2019) | |
| I can't understand this problem. Please explain in detail. | |
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