Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 7)
7.
If log10 2 = 0.3010, then log2 10 is equal to:
699
301
1000
301
0.3010
0.6990
Answer: Option
Explanation:
log2 10 = 1 = 1 = 10000 = 1000 .
log10 2 0.3010 3010 301
Discussion:
18 comments Page 1 of 2.

Arun said:   1 decade ago
log(a) X =log X/log a using this formula we can solve.. log(10) 2 = 0.3010.
Using that formula we can write log 2/log 10=0.3010.

So take reciprocal log 10/log 2 = 1/0.3010...use the first line formula log(10) 2 = log 10/log 2 [i.e.log(a) X = log X/log a]=1/0.3010 = 1/3*10power of -4 = 10000/3010 = 1000/301.

Sagor said:   7 years ago
We know,
loga M= logb M ÷ logb a,
so, log2 10= log10 10 ÷ log10 2 [here b= 10],
=1 ÷ 0.3010,
=10000 ÷ 3010,
=1000/301.
(1)

Rajeev said:   1 decade ago
We know that change based of log.

Log2 10 written as log10 10 divided by log10 2.

We have a value of log10 2.

So simple calculation.
(1)

Shiv said:   7 years ago
Simply log2^10 is reciprocal of log 10^2 so,
log2^10=1/log10^2.
=1/0.3010=10000/3010(removing decimal),
=1000/301.

Melissa Ramnauth said:   1 decade ago
I do not understand how you get 10000 divided (over) 3010 giving it a result of 1000 divided (over) 301.

Karma said:   6 years ago
@Chand.

To remove a decimal, we multiply both the numerator and denominator by 10000.

LavanyaGeetha said:   8 years ago
What is the answer for this question?

Log 64 base 16- log 16 base 64?

Navya said:   6 years ago
I can't understand this problem. Please explain in detail.

Sanjay said:   7 years ago
0.3010 is in decimals, to remove decimals we add zeros.

Mahalakshmi said:   7 years ago
How these base can be changed over here please explain?


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