Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 7)
7.
If log10 2 = 0.3010, then log2 10 is equal to:
Answer: Option
Explanation:
| log2 10 = | 1 | = | 1 | = | 10000 | = | 1000 | . |
| log10 2 | 0.3010 | 3010 | 301 |
Discussion:
18 comments Page 1 of 2.
Rajeev said:
1 decade ago
We know that change based of log.
Log2 10 written as log10 10 divided by log10 2.
We have a value of log10 2.
So simple calculation.
Log2 10 written as log10 10 divided by log10 2.
We have a value of log10 2.
So simple calculation.
(1)
Pandichitra said:
6 years ago
Thanks @Sagor.
(1)
Sagor said:
7 years ago
We know,
loga M= logb M ÷ logb a,
so, log2 10= log10 10 ÷ log10 2 [here b= 10],
=1 ÷ 0.3010,
=10000 ÷ 3010,
=1000/301.
loga M= logb M ÷ logb a,
so, log2 10= log10 10 ÷ log10 2 [here b= 10],
=1 ÷ 0.3010,
=10000 ÷ 3010,
=1000/301.
(1)
B Sridhara Naik said:
4 years ago
Good, Thanks for explaining.
Melissa Ramnauth said:
1 decade ago
I do not understand how you get 10000 divided (over) 3010 giving it a result of 1000 divided (over) 301.
Karma said:
6 years ago
@Chand.
To remove a decimal, we multiply both the numerator and denominator by 10000.
To remove a decimal, we multiply both the numerator and denominator by 10000.
Navya said:
6 years ago
I can't understand this problem. Please explain in detail.
Sydha said:
7 years ago
I am not getting the answer, please explain it.
Shiv said:
7 years ago
Simply log2^10 is reciprocal of log 10^2 so,
log2^10=1/log10^2.
=1/0.3010=10000/3010(removing decimal),
=1000/301.
log2^10=1/log10^2.
=1/0.3010=10000/3010(removing decimal),
=1000/301.
Mahalakshmi said:
7 years ago
How these base can be changed over here please explain?
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