Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 7)
7.
If log10 2 = 0.3010, then log2 10 is equal to:
Answer: Option
Explanation:
| log2 10 = | 1 | = | 1 | = | 10000 | = | 1000 | . |
| log10 2 | 0.3010 | 3010 | 301 |
Discussion:
18 comments Page 2 of 2.
Karma said:
6 years ago
@Chand.
To remove a decimal, we multiply both the numerator and denominator by 10000.
To remove a decimal, we multiply both the numerator and denominator by 10000.
Shiv said:
7 years ago
Simply log2^10 is reciprocal of log 10^2 so,
log2^10=1/log10^2.
=1/0.3010=10000/3010(removing decimal),
=1000/301.
log2^10=1/log10^2.
=1/0.3010=10000/3010(removing decimal),
=1000/301.
Mahalakshmi said:
7 years ago
How these base can be changed over here please explain?
Sanjay said:
7 years ago
0.3010 is in decimals, to remove decimals we add zeros.
Chand said:
7 years ago
How 10000 came? Please explain it.
LavanyaGeetha said:
9 years ago
What is the answer for this question?
Log 64 base 16- log 16 base 64?
Log 64 base 16- log 16 base 64?
Puneet said:
9 years ago
Why not answer is 0.6990?
Arun said:
1 decade ago
log(a) X =log X/log a using this formula we can solve.. log(10) 2 = 0.3010.
Using that formula we can write log 2/log 10=0.3010.
So take reciprocal log 10/log 2 = 1/0.3010...use the first line formula log(10) 2 = log 10/log 2 [i.e.log(a) X = log X/log a]=1/0.3010 = 1/3*10power of -4 = 10000/3010 = 1000/301.
Using that formula we can write log 2/log 10=0.3010.
So take reciprocal log 10/log 2 = 1/0.3010...use the first line formula log(10) 2 = log 10/log 2 [i.e.log(a) X = log X/log a]=1/0.3010 = 1/3*10power of -4 = 10000/3010 = 1000/301.
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