# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 14)

14.

At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?

Answer: Option

Explanation:

At 4 o'clock, the hands of the watch are 20 min. spaces apart.

To be in opposite directions, they must be 30 min. spaces apart.

Minute hand will have to gain 50 min. spaces.

55 min. spaces are gained in 60 min.

50 min. spaces are gained in | 60 | x 50 | min. or 54 | 6 | min. | |

55 | 11 |

Required time = 54 | 6 | min. past 4. |

11 |

Discussion:

52 comments Page 1 of 6.
Ness said:
4 months ago

Can someone please explain this to me in detail?

Shivam Tiwari said:
4 years ago

At 4'O clock ---------> 20 mins spaces.

To be in the opposite direction, they must have 30 mins spaces.

So, clock follows the only clockwise direction that's why it has to gain 50 mins spaces apart to be in the opposite direction.

55 mins spaces ----------------> 60 mins.

50 mins spaces---------------> 60/55*50 = 54(6/11)min.

So, the answer is 54(6/11)min past 4.

To be in the opposite direction, they must have 30 mins spaces.

So, clock follows the only clockwise direction that's why it has to gain 50 mins spaces apart to be in the opposite direction.

55 mins spaces ----------------> 60 mins.

50 mins spaces---------------> 60/55*50 = 54(6/11)min.

So, the answer is 54(6/11)min past 4.

Arunkumar said:
4 years ago

Thanks @Nithisha.

Nithisha said:
4 years ago

It's very simple.

As it was mentioned opposite(180°).

180° = (11/2*m)-30(hr),

180° = (11/2*m)-30(4),

m = 600/11,

m = 54.5454.

As it was mentioned opposite(180°).

180° = (11/2*m)-30(hr),

180° = (11/2*m)-30(4),

m = 600/11,

m = 54.5454.

Rinju said:
4 years ago

The two hands of a clock will be opposite direction between H and ( H+1) O' clock at 60a/11 minutes past H' O clock.

Solve this problem by using this method,

'a' is opposite to H,

In this case, H is 4 and a is 10,

Then 60*10/11,

600/11= 54 6/11 past 4.

Solve this problem by using this method,

'a' is opposite to H,

In this case, H is 4 and a is 10,

Then 60*10/11,

600/11= 54 6/11 past 4.

Avijit Samanta said:
4 years ago

Use this formula:

(5n+30)*12/11 if n<6.

(5n-30)*12/11 if n>6.

(5n+30)*12/11 if n<6.

(5n-30)*12/11 if n>6.

Ash said:
5 years ago

Guys when to use (4h-11/2 *m) and when to use (11/2*m-4h). Can anybody please explain this?

Nikita Agrawal said:
5 years ago

Somebody, please tell me the degrees of every direction.

Ajay Kumar said:
5 years ago

You explained very well. Thanks @Kiran.

Pratima said:
6 years ago

Between 4 and 5, the minute hand to move 20 min in right half of circle (watch) from the initial point that is 12 here.

And 30 minutes from 4 in another side to go in opposite direction. So total is 20+30=50.

And 30 minutes from 4 in another side to go in opposite direction. So total is 20+30=50.

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