Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 14)
14.
At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?
Answer: Option
Explanation:
At 4 o'clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min.
| 50 min. spaces are gained in |  |
60 | x 50 |  min. or 54 |
6 | min. |
| 55 | 11 |
| Required time = 54 |
6 | min. past 4. |
| 11 |
Discussion:
55 comments Page 1 of 6.
RAJ ARYAN said:
2 years ago
When to use (11/2) *m -30H & 30H - (11/2) *m?
Kindly explain.
Kindly explain.
(8)
Vidhanshu Borade said:
2 years ago
Step 1: Fix the hour hand to the starting time given i.e. here in this case at 4.
Step 2: Count the min spaces for the min hand to be in a straight line but in the opposite direction of 4 and denote it by m.
Step 3: In this case, the min hand has to be on 10 to be in the opposite side of 4 hence m = 50 min spaces.
Step 4: Use the formula: 12m/11 = 12*50/11 = 600/11 = 54 6/11.
Step 2: Count the min spaces for the min hand to be in a straight line but in the opposite direction of 4 and denote it by m.
Step 3: In this case, the min hand has to be on 10 to be in the opposite side of 4 hence m = 50 min spaces.
Step 4: Use the formula: 12m/11 = 12*50/11 = 600/11 = 54 6/11.
(4)
Joy said:
2 years ago
Guys, how do we get the 20 spaces? Anyone, explain to me.
(2)
Ness said:
3 years ago
Can someone please explain this to me in detail?
(1)
Shivam Tiwari said:
6 years ago
At 4'O clock ---------> 20 mins spaces.
To be in the opposite direction, they must have 30 mins spaces.
So, clock follows the only clockwise direction that's why it has to gain 50 mins spaces apart to be in the opposite direction.
55 mins spaces ----------------> 60 mins.
50 mins spaces---------------> 60/55*50 = 54(6/11)min.
So, the answer is 54(6/11)min past 4.
To be in the opposite direction, they must have 30 mins spaces.
So, clock follows the only clockwise direction that's why it has to gain 50 mins spaces apart to be in the opposite direction.
55 mins spaces ----------------> 60 mins.
50 mins spaces---------------> 60/55*50 = 54(6/11)min.
So, the answer is 54(6/11)min past 4.
(2)
Arunkumar said:
6 years ago
Thanks @Nithisha.
Nithisha said:
6 years ago
It's very simple.
As it was mentioned opposite(180°).
180° = (11/2*m)-30(hr),
180° = (11/2*m)-30(4),
m = 600/11,
m = 54.5454.
As it was mentioned opposite(180°).
180° = (11/2*m)-30(hr),
180° = (11/2*m)-30(4),
m = 600/11,
m = 54.5454.
(18)
Rinju said:
7 years ago
The two hands of a clock will be opposite direction between H and ( H+1) O' clock at 60a/11 minutes past H' O clock.
Solve this problem by using this method,
'a' is opposite to H,
In this case, H is 4 and a is 10,
Then 60*10/11,
600/11= 54 6/11 past 4.
Solve this problem by using this method,
'a' is opposite to H,
In this case, H is 4 and a is 10,
Then 60*10/11,
600/11= 54 6/11 past 4.
Avijit Samanta said:
7 years ago
Use this formula:
(5n+30)*12/11 if n<6.
(5n-30)*12/11 if n>6.
(5n+30)*12/11 if n<6.
(5n-30)*12/11 if n>6.
Ash said:
7 years ago
Guys when to use (4h-11/2 *m) and when to use (11/2*m-4h). Can anybody please explain this?
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