Exercise :: Exam Questions Papers - Exam Paper 12
- Exam Questions Papers - Exam Paper 1
- Exam Questions Papers - Exam Paper 2
- Exam Questions Papers - Exam Paper 3
- Exam Questions Papers - Exam Paper 4
- Exam Questions Papers - Exam Paper 5
- Exam Questions Papers - Exam Paper 6
- Exam Questions Papers - Exam Paper 7
- Exam Questions Papers - Exam Paper 8
- Exam Questions Papers - Exam Paper 9
- Exam Questions Papers - Exam Paper 10
- Exam Questions Papers - Exam Paper 11
- Exam Questions Papers - Exam Paper 12
- Exam Questions Papers - Exam Paper 13
- Exam Questions Papers - Exam Paper 14
- Exam Questions Papers - Exam Paper 15
- Exam Questions Papers - Exam Paper 16
- Exam Questions Papers - Exam Paper 17
- Exam Questions Papers - Exam Paper 18
- Exam Questions Papers - Exam Paper 19
- Exam Questions Papers - Exam Paper 20
- Exam Questions Papers - Exam Paper 21
- Exam Questions Papers - Exam Paper 22
26. | Figure shows four D type FFs are connected as a shift register using an XOR gate. The initial state and 3 subsequent states for 3 clock pulses are also given |
|||||||
Answer: Option D Explanation: After the 3rd pulse FF3 is 0 and FF4 is 1, so that XOR output is 1 which is fed to DA. So, Q_{A} = 1, Q_{A} to Q_{B} → 0 A_{B} to A_{C} → 0, Q_{C} → Q_{D} → 0. |
27. | A rectangular wave guide is designed to propagate at the dominant mode TE_{10} at a frequency of 5 GHz. The cut-off frequency is 0.8 of signal frequency. The ratio of the guide width to height is 2. The dimensions of the guide are |
|||||||
Answer: Option A Explanation: λ_{c} = 2a or ⇒ a = 3.75 cm Also, ∴ . |
28. | In the Taylor series expansion of exp(x) + sin(x) about the point x = p, the coefficient of (x - p)^{2} is |
|||||||
Answer: Option B Explanation: f(x) = e^{x} + sin x Coefficient of (x - p)^{2} = 1 / 2! f''(x) f'(x) = e^{x} + cos x f'(x) = e^{x} - sin x f''(x)|_{x=p} = e^{p} Thus coefficient of (x - p)^{2} = 0.5 . |
29. | The Z transform of a particular signal is given as |
|||||||
Answer: Option B Explanation: When get high value at ω = 0, and low value at ω = p, hence we get a low pass filter. So the system is min-phase causal system. For practical implementation of the system, the system has to be stable. |
30. | If g(t) = e^{-pt2} then G(1/p) is __________ where g(t) G(f) |
|||||||
Answer: Option B Explanation: The signal g(t) given above is a gaussian pulse and it satisfies the relation g(t) = - 2pt g(t) ∴ Its fourier transform is same as the signal itself in frequency domain G(f) = e^{-pf2} G(1/p) = e^{-p(1/p)2} = e^{-1/p}. |