Electronics and Communication Engineering - Exam Questions Papers
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1.
The electric field of 2.5 x 107 V/m can give 1 eV energy to condition electron, then in a copper block what will be the mean free path of electron?
Answer: Option
Explanation:
The force on electron in eE. As the electron moves through distance d , the work done on it is eEd.
This is equal to energy transferred to electron.
∴ eEd = 1 eV
∴ d = 4 x 10-7m.
2.
25 persons are in a room. 15 of them play hockey, 17 of them play football and 10 of them play both hockey and football. Then the number of persons playing neither hockey nor football is:
Answer: Option
Explanation:
Representing the given information in the Venn diagrams, we have
Let the number of people who play only hockey = a
The number of people who play only football = b
Now, a = n(H) - 10 = 15 - 10 = 5
b = n(F) - 10 = 17 - 10 = 7
Clearly, a + b + 10 + n = 25
⇒ n = 25 - 7 - 5 -10 ⇒ n = 3
∴ The number of people who do not play neither Hockey nor Football is 3.
3.
For the circuit shown in the following figure I0-I3 are inputs to the 4:1 multiplexer R(MSB) and S are control bits

The output Z can be represented by

The output Z can be represented by
Answer: Option
Explanation:
Use this to find solution
4.
The transfer function of a system is
. For a unit-step input to the system the approximate setting time for 2% criterion is :

Answer: Option
Explanation:
ξωn = 1
for 2% = 4 sec.
5.
The Nyquist sampling interval, for the signal sine (700t) + sine (500t) is
Answer: Option
Explanation:
g(t) = sinc (700t) + sinc (500t)
g(t) is band-limited with fM = 350 Hz.
Hence the Nyquist rate will be 700 Hz.
Then Nyquist interval is sec.
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