Exercise :: Exam Questions Papers - Exam Paper 12
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1. | 8416 - 2A16 is equal to |
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Answer: Option A Explanation: (2A)16 = (00101010)2 2's complement = 11010110 = (D6)16 (84)16 + (D6)16 ⇒ 1(5A)16 carry discarded ⇒ (5A)16 . |
2. | Calculate the electrostatic force of repulsion between two mica particles at a distance of 10-13 m from each other. Charge on a particle is 3.2 x 10-19 C. (relative permittivity for mica is 5) |
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Answer: Option D Explanation: By Coulomb's law: Electrostatic force = = 18.43 x 10- 3 N. |
3. | An electromechanical closed loop control system has the following characteristics equation :s3 + 6Ks2 + (K + 2)s = 8 |
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Answer: Option A Explanation: s3 + 6ks2 + (k + 2)s + 8 = 0 a0 = 1, a1 = 6k, a2 = k + 2, a3 = 8 Apply R.H. criteria. |
4. | What is the propagation constant for air filled wave guide with dimensions a = 1.59" and b = 0.795" at 4.95 GHz. The wave impedance is |
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Answer: Option B Explanation:
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5. | An antenna array comprises of two dipoles that are separated by |
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Answer: Option A Explanation: Array factor
φ = 90°. |