Electronics and Communication Engineering - Exam Questions Papers
Exercise : Exam Questions Papers - Exam Paper 12
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- Exam Questions Papers - Exam Paper 2
1.
8416 - 2A16 is equal to
Answer: Option
Explanation:
(2A)16 = (00101010)2
2's complement = 11010110 = (D6)16
(84)16 + (D6)16 ⇒ 1(5A)16 carry discarded ⇒ (5A)16 .
2.
Calculate the electrostatic force of repulsion between two mica particles at a distance of 10-13 m from each other. Charge on a particle is 3.2 x 10-19 C. (relative permittivity for mica is 5)
Answer: Option
Explanation:
By Coulomb's law:
Electrostatic force = =
= 18.43 x 10- 3 N.
3.
An electromechanical closed loop control system has the following characteristics equation :s3 + 6Ks2 + (K + 2)s = 8
where K is the forward gain of the system. The condition for closed loop stability is
where K is the forward gain of the system. The condition for closed loop stability is
Answer: Option
Explanation:
s3 + 6ks2 + (k + 2)s + 8 = 0
a0 = 1, a1 = 6k, a2 = k + 2, a3 = 8
Apply R.H. criteria.
4.
What is the propagation constant for air filled wave guide with dimensions a = 1.59" and b = 0.795" at 4.95 GHz. The wave impedance is
Answer: Option
Explanation:
.
5.
An antenna array comprises of two dipoles that are separated by
wavelength. The dipoles are fed by currents of the same magnitude and 90° in phase. The array factor is:

Answer: Option
Explanation:
Array factor
φ = 90°.
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