Electronics and Communication Engineering - Exam Questions Papers - Discussion

1. 

8416 - 2A16 is equal to

[A]. 5A16
[B]. 4A16
[C]. 7A16
[D]. 15A16

Answer: Option A

Explanation:

(2A)16 = (00101010)2

2's complement = 11010110 = (D6)16

(84)16 + (D6)16 ⇒ 1(5A)16 carry discarded ⇒ (5A)16 .


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