Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 12 (Q.No. 28)
28.
In the Taylor series expansion of exp(x) + sin(x) about the point x = p, the coefficient of (x - p)2 is
exp (p)
0.5 exp (p)
exp (p) + 1
exp (p) - 1
Answer: Option
Explanation:

f(x) = ex + sin x

Coefficient of (x - p)2 = 1 / 2! f''(x)

f'(x) = ex + cos x

f'(x) = ex - sin x

f''(x)|x=p = ep

Thus coefficient of (x - p)2 = 0.5 .

Discussion:
Be the first person to comment on this question !

Post your comments here:

Your comments will be displayed after verification.