Online Aptitude Test  Aptitude Test 4
 This is a FREE online test. Beware of scammers who ask for money to attend this test.
 Total number of questions: 20.
 Time allotted: 30 minutes.
 Each question carries 1 mark; there are no negative marks.
 DO NOT refresh the page.
 All the best!
Marks : 2/20
Test Review : View answers and explanation for this test.
Let the total number of shots be x. Then,
Shots fired by A =  5  x 
8 
Shots fired by B =  3  x 
8 
Killing shots by A =  1  of  5  x  =  5  x 
3  8  24 
Shots missed by B =  1  of  3  x  =  3  x 
2  8  16 
3x  = 27 or x =  27 x 16  = 144.  
16  3 
Birds killed by A =  5x  =  5  x 144  = 30.  
24  24 
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,  (6x + 6) + 4  =  11 
(5x + 6) + 4  10 
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
1. The difference of age b/w R and Q = The difference of age b/w Q and T.
2. Sum of age of R and T is 50 i.e. (R + T) = 50.
Question: R  Q = ?.
Explanation:
R  Q = Q  T
(R + T) = 2Q
Now given that, (R + T) = 50
So, 50 = 2Q and therefore Q = 25.
Question is (R  Q) = ?
Here we know the value(age) of Q (25), but we don't know the age of R.
Therefore, (RQ) cannot be determined.
1  +  1  = ? 
1 + a^{(n  m)}  1 + a^{(m  n)} 
1  +  1  = 


1 + a^{(n  m)}  1 + a^{(m  n)} 
=  a^{m}  +  a^{n} 
(a^{m} + a^{n})  (a^{m} + a^{n}) 
=  (a^{m} + a^{n}) 
(a^{m} + a^{n}) 
= 1.
1^{ }  +  1  +  1  = ? 
1 + x^{(b  a)} + x^{(c  a)}  1 + x^{(a  b)} + x^{(c  b)}  1 + x^{(b  c)} + x^{(a  c)} 
Given Exp. = 

=  x^{a}  +  x^{b}  +  x^{c} 
(x^{a} + x^{b} + x^{c})  (x^{a} + x^{b} + x^{c})  (x^{a} + x^{b} + x^{c}) 
=  (x^{a} + x^{b} + x^{c}) 
(x^{a} + x^{b} + x^{c}) 
= 1.
Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
Simran's share = Rs.  24500 x  3  = Rs. 10,500.  
7 
A's 2 day's work =  1  x 2  =  1  .  
20  10 
(A + B + C)'s 1 day's work =  1  +  1  +  1  =  6  =  1  .  
20  30  60  60  10 
Work done in 3 days =  1  +  1  =  1  .  
10  10  5 
Now,  1  work is done in 3 days. 
5 
Whole work will be done in (3 x 5) = 15 days.
Let the distance travelled by x km.
Then,  x    x  = 2 
10  15 
3x  2x = 60
x = 60 km.
Time taken to travel 60 km at 10 km/hr =  60  hrs  = 6 hrs.  
10 
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed =  60  kmph.  = 12 kmph.  
5 
Suppose he move 4 km downstream in x hours. Then,
Speed downstream =  4  km/hr.  
x 
Speed upstream =  3  km/hr.  
x 
48  +  48  = 14 or x =  1  .  
(4/x)  (3/x)  2 
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream =  1  (8  6) km/hr = 1 km/hr. 
2 
By the rule of alligation:
Cost of 1 kg pulses of 1^{st} kind Cost of 1 kg pulses of 2^{nd} kind  
Rs. 15  Mean Price Rs. 16.50  Rs. 20 
3.50  1.50 
Required rate = 3.50 : 1.50 = 7 : 3.
If log  a  +  log  b  = log (a + b), then: 
b  a 
log  a  + log  b  = log (a + b) 
b  a 
log (a + b) = log  a  x  b  = log 1.  
b  a 
So, a + b = 1.
A : B = 200 : 169.
A : C = 200 : 182.
C  =  C  x  A  =  182  x  200  = 182 : 169.  
B  A  B  200  169 
When C covers 182 m, B covers 169 m.
When C covers 350 m, B covers  169  x 350  m  = 325 m.  
182 
Therefore, C beats B by (350  325) m = 25 m.
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6^{th} March, 2005 will be 1 day beyond the day on 6^{th} March, 2004.
Given that, 6^{th} March, 2005 is Monday.
6^{th} March, 2004 is Sunday (1 day before to 6^{th} March, 2005).
Angle traced by hour hand in 12 hrs = 360°.
Angle traced by hour hand in 5 hrs 10 min. i.e.,  31  hrs =  360  x  31  °  = 155°.  
6  12  6 
Angle traced by the hour hand in 6 hours =  360  x 6  °  = 180°.  
12 
For an income of Rs. 756, investment = Rs. 9000.
For an income of Rs.  21  , investment = Rs.  9000  x  21  = Rs. 125.  
2  756  2 
For a Rs. 100 stock, investment = Rs. 125.
Market value of Rs. 100 stock = Rs.  125   1  = Rs. 124.75  
4 
Clearly, there are 52 cards, out of which there are 12 face cards.
P (getting a face card) =  12  =  3  . 
52  13 
Let S be the sample space.
Then, n(S) = ^{52}C_{2} =  (52 x 51)  = 1326. 
(2 x 1) 
Let E = event of getting 2 kings out of 4.
n(E) = ^{4}C_{2} =  (4 x 3)  = 6. 
(2 x 1) 
P(E) =  n(E)  =  6  =  1  . 
n(S)  1326  221 
P.W. = Rs. (2562  122) = Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
Rate =  100 x 122  %  = 15%.  
