# Aptitude - Time and Distance

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- Time and Distance - Formulas
- Time and Distance - General Questions
- Time and Distance - Data Sufficiency 1

Speed = | 600 | m/sec. | |

5 x 60 |

= 2 m/sec.

Converting m/sec to km/hr (see important formulas section)

= | 2 x | 18 | km/hr | ||

5 |

= 7.2 km/hr.

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]

Required speed = | 1200 x | 3 | km/hr | = 720 km/hr. | |

5 |

Let the actual distance travelled be *x* km.

Then, | x |
= | x + 20 |

10 | 14 |

14*x* = 10*x* + 200

4*x* = 200

*x* = 50 km.

Let speed of the car be *x* kmph.

Then, speed of the train = | 150 | x |
= | 3 | x |
kmph. | |

100 | 2 |

75 | - | 75 | = | 125 | |

x |
(3/2)x |
10 x 60 |

75 | - | 50 | = | 5 | |

x |
x |
24 |

x = |
25 x24 | = 120 kmph. | ||

5 |

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = | 9 | x 60 | min | = 10 min. | |

54 |