Aptitude - Time and Distance
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- Time and Distance - Formulas
- Time and Distance - General Questions
- Time and Distance - Data Sufficiency 1
Speed = | ![]() |
600 | ![]() |
5 x 60 |
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= | ![]() |
2 x | 18 | ![]() |
km/hr |
5 |
= 7.2 km/hr.

Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
![]() |
![]() |
1200 x | 3 | ![]() |
= 720 km/hr. |
5 |
Let the actual distance travelled be x km.
Then, | x | = | x + 20 |
10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Let speed of the car be x kmph.
Then, speed of the train = | 150 | x | = | ![]() |
3 | x | ![]() |
100 | 2 |
![]() |
75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
![]() |
75 | - | 50 | = | 5 |
x | x | 24 |
![]() |
![]() |
25 x24 | ![]() |
= 120 kmph. |
5 |
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = | ![]() |
9 | x 60 | ![]() |
= 10 min. |
54 |