Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
173 comments Page 1 of 18.
Bhajan Lal said:
2 weeks ago
If he is going at 10km/hr the distance is 10*t.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km.
14t-10t = 20,
4t = 20.
t = 5 hours.
Now, actual distance = 10 * 5.
= 50 km.
But,
The actual distance travelled by him is : 14 * 5 = 70 Km.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km.
14t-10t = 20,
4t = 20.
t = 5 hours.
Now, actual distance = 10 * 5.
= 50 km.
But,
The actual distance travelled by him is : 14 * 5 = 70 Km.
Naviyaashree KA said:
4 weeks ago
If he is going at 10km/hr the distance is 10*t.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km
14t-10t = 20
4t = 20
t = 5 hours
Now, actual distance = 10 * 5.
= 50 km.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km
14t-10t = 20
4t = 20
t = 5 hours
Now, actual distance = 10 * 5.
= 50 km.
(11)
Rishika V said:
4 months ago
In both speed, the time period is same right?
(11)
Chahat Mishra said:
7 months ago
Very easy approach:
Here d1 - d2 = 14 - 10 = 4km/h.
Now 4 = 20.
Then 1 = 5.
The actual distance is 10 * 5 = 50km.
Here d1 - d2 = 14 - 10 = 4km/h.
Now 4 = 20.
Then 1 = 5.
The actual distance is 10 * 5 = 50km.
(122)
Anwaar said:
1 year ago
At usual time Period, a man Covers a Distance of 10 KM/hr ,But he has increased the Speed to 14 km/hr.
That means he will going 4 Km/hr additionally.
To Cover the Distance of 20 km with the Same of 14 km/hr he has to travel additional 5 hours.
4km * 5hrs = 20 km.
After 5 hours of travel if the person is travelling at the speed of 10 km/hr covers;
D = S * T/
D = 1 0 *5.
D = 50 KM.
That means he will going 4 Km/hr additionally.
To Cover the Distance of 20 km with the Same of 14 km/hr he has to travel additional 5 hours.
4km * 5hrs = 20 km.
After 5 hours of travel if the person is travelling at the speed of 10 km/hr covers;
D = S * T/
D = 1 0 *5.
D = 50 KM.
(37)
Vijeth BK said:
1 year ago
The speed of man is =10km/hr.
In question that given if he walked 14km/hr instead of 10km/hr,he will reach
20km more(but the time is same).
If he walked 10km/hr, we take that distance covered is Xkm.
If he walked 14km/hr, we take that distance covered X+20km.
But for a both cases time is the same.
(Time = distance/speed).
Since X/10 = (X+20)/14.
14X = 10X+200
4X = 200
X = 50km.
In question that given if he walked 14km/hr instead of 10km/hr,he will reach
20km more(but the time is same).
If he walked 10km/hr, we take that distance covered is Xkm.
If he walked 14km/hr, we take that distance covered X+20km.
But for a both cases time is the same.
(Time = distance/speed).
Since X/10 = (X+20)/14.
14X = 10X+200
4X = 200
X = 50km.
(87)
Anomiee said:
1 year ago
Thanks for explaining.
(18)
TAMIL SELVAN said:
1 year ago
By ratio method, if time is constant speed is directly proportional to distance so;
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
(116)
Ramachandra said:
1 year ago
Let,
Actual dist = X(at-10km\hr).
x/10 = x + 20/14,
14x = 10x + 20,
14x - 10x = 20,
4x = 20,
x = 20/4,
x = 5.
The actual distance at 10kmph * actual distance.
= 10 * 5,
= 50km.
So, the answer is 50km.
Actual dist = X(at-10km\hr).
x/10 = x + 20/14,
14x = 10x + 20,
14x - 10x = 20,
4x = 20,
x = 20/4,
x = 5.
The actual distance at 10kmph * actual distance.
= 10 * 5,
= 50km.
So, the answer is 50km.
(8)
Priya said:
1 year ago
According to me;
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
(66)
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