# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)

3.

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Answer: Option

Explanation:

Let the actual distance travelled be *x* km.

Then, | x |
= | x + 20 |

10 | 14 |

14*x* = 10*x* + 200

4*x* = 200

*x* = 50 km.

Discussion:

162 comments Page 1 of 17.
SILEBCE said:
1 month ago

According to me, the right answer is 50km.

(1)

Kaviprema k said:
2 months ago

We don't know the actual distance so let we consider it as x.

The actual speed is 10 km/ hr ->x.

Another speed is 14 km/hr ->x + 20 km.

( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)

So,

X/ 10 = x+20/14,

14x = 10x+200,

14x-10x = 200,

4x = 200,

x = 200/4,

x = 50.

So,the actual distance is 50 km.

The actual speed is 10 km/ hr ->x.

Another speed is 14 km/hr ->x + 20 km.

( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)

So,

X/ 10 = x+20/14,

14x = 10x+200,

14x-10x = 200,

4x = 200,

x = 200/4,

x = 50.

So,the actual distance is 50 km.

(10)

Vishal said:
2 months ago

Why t in both the equation is same?

If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.

If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.

(6)

MO HASAN said:
5 months ago

His actual speed is 10 km/h and from given question.

14x-10x = 20,

4x = 20,

x = 5 hours.

then the actual distance will be;

10*5 = 50 km.

14x-10x = 20,

4x = 20,

x = 5 hours.

then the actual distance will be;

10*5 = 50 km.

(81)

Tariq said:
8 months ago

Given:

S1= 14km/h

S2= 10km/h

D1= 20km

D2=?

Solution:

We know that; (Distance= Speed * Time)

We first need to know the time taken,

By putting values:

20km = 14km/h (s1) - 10km/h (s2)

20km = 4 km/h,

20/4 = 5.

So the time (T) is 5.

Similarly, putting values we get;

D2 (actual distance)= 10km/h (actual speed) * 5 (time).

Distance= 10*5km.

Actual distance= 50km.

S1= 14km/h

S2= 10km/h

D1= 20km

D2=?

Solution:

We know that; (Distance= Speed * Time)

We first need to know the time taken,

By putting values:

20km = 14km/h (s1) - 10km/h (s2)

20km = 4 km/h,

20/4 = 5.

So the time (T) is 5.

Similarly, putting values we get;

D2 (actual distance)= 10km/h (actual speed) * 5 (time).

Distance= 10*5km.

Actual distance= 50km.

(109)

Chahat said:
9 months ago

Thanks, everyone for explaining.

(19)

Meghan Desai said:
9 months ago

Let

Actual distance is 'X' - (at 10kmph),

Distance afterwards is 'X+20' - (at 14kmph).

Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)

2. X+20 = 14Y

X = 14Y-20 ---> (b).

Comparing a&b we have;

10Y = 14Y-20

So, 14Y-10Y = 20;

and, Y = 5hrs.

Actual distance (at actual speed):-

10kmphx 5hrs = 50km.

That's the answer.

Actual distance is 'X' - (at 10kmph),

Distance afterwards is 'X+20' - (at 14kmph).

Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)

2. X+20 = 14Y

X = 14Y-20 ---> (b).

Comparing a&b we have;

10Y = 14Y-20

So, 14Y-10Y = 20;

and, Y = 5hrs.

Actual distance (at actual speed):-

10kmphx 5hrs = 50km.

That's the answer.

(29)

Pulyala ajith kumar said:
9 months ago

The difference between distances is 20km and d = s * t.

So 14x-10x = 20.

x = 5hrs

The actual distance is s*t = 10 * 5 = 50km.

So 14x-10x = 20.

x = 5hrs

The actual distance is s*t = 10 * 5 = 50km.

(51)

Aryan said:
10 months ago

@All,

According to me, the solution is;

For every 1 km/hr there is 5 km distance travelled;

So for 10km/hr there is 50km distance travelled;

which means for 4 more km/hr in question there is 20 kM distance.

So, for 10 km it's 50 km.

According to me, the solution is;

For every 1 km/hr there is 5 km distance travelled;

So for 10km/hr there is 50km distance travelled;

which means for 4 more km/hr in question there is 20 kM distance.

So, for 10 km it's 50 km.

(10)

Gaurav Raghav said:
10 months ago

Let the actual speed be x.

Let the time be y.

Distance = Speed * time

Therefore,

X= 10y.

But, now he would have travelled 20 km more if the speed was 14km/hr.

therefore,

14x= y+20.

Subtracting both equations,

14x = y+20,

10x = y.

we get;

4x = 20,

x = 5.

Put y in the equation

10 * 5 = 50 Kms.

Verify it by putting 5 in both equations.

Let the time be y.

Distance = Speed * time

Therefore,

X= 10y.

But, now he would have travelled 20 km more if the speed was 14km/hr.

therefore,

14x= y+20.

Subtracting both equations,

14x = y+20,

10x = y.

we get;

4x = 20,

x = 5.

Put y in the equation

10 * 5 = 50 Kms.

Verify it by putting 5 in both equations.

(9)

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