# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
50 km
56 km
70 km
80 km
Explanation:

Let the actual distance travelled be x km.

 Then, x = x + 20 10 14

14x = 10x + 200

4x = 200

x = 50 km.

Discussion:
162 comments Page 1 of 17.

SILEBCE said:   1 month ago
According to me, the right answer is 50km.
(1)

Kaviprema k said:   2 months ago
We don't know the actual distance so let we consider it as x.
The actual speed is 10 km/ hr ->x.
Another speed is 14 km/hr ->x + 20 km.
( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)
So,
X/ 10 = x+20/14,
14x = 10x+200,
14x-10x = 200,
4x = 200,
x = 200/4,
x = 50.

So,the actual distance is 50 km.
(10)

Vishal said:   2 months ago
Why t in both the equation is same?

If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
(6)

MO HASAN said:   5 months ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(81)

Tariq said:   8 months ago
Given:
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?

Solution:

We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:

20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.

Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
(109)

Chahat said:   9 months ago
Thanks, everyone for explaining.
(19)

Meghan Desai said:   9 months ago
Let
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).

Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.

Actual distance (at actual speed):-
10kmphx 5hrs = 50km.

(29)

Pulyala ajith kumar said:   9 months ago
The difference between distances is 20km and d = s * t.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
(51)

Aryan said:   10 months ago
@All,

According to me, the solution is;

For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
(10)

Gaurav Raghav said:   10 months ago
Let the actual speed be x.
Let the time be y.

Distance = Speed * time

Therefore,
X= 10y.

But, now he would have travelled 20 km more if the speed was 14km/hr.
therefore,
14x= y+20.

Subtracting both equations,
14x = y+20,
10x = y.

we get;
4x = 20,
x = 5.
Put y in the equation
10 * 5 = 50 Kms.
Verify it by putting 5 in both equations.
(9)