Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
50 km
56 km
70 km
80 km
Answer: Option
Explanation:

Let the actual distance travelled be x km.

Then, x = x + 20
10 14

14x = 10x + 200

4x = 200

x = 50 km.

Discussion:
170 comments Page 1 of 17.

Salsabil said:   2 years ago
According to me, by using the simple formula we can iterate lucidly like this way,

Let the time be x hours

According to the question;

14x - 10x = 20
4x = 20
x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.
(201)

Tariq said:   2 years ago
Given:
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?

Solution:

We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:

20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.

Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
(128)

MO HASAN said:   1 year ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(94)

TAMIL SELVAN said:   8 months ago
By ratio method, if time is constant speed is directly proportional to distance so;
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.

Put this in the usual speed 10x= 10*5=50 km.
(94)

Priya said:   9 months ago
According to me;

Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
(61)

Pulyala ajith kumar said:   2 years ago
The difference between distances is 20km and d = s * t.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
(53)

Vijeth BK said:   6 months ago
The speed of man is =10km/hr.

In question that given if he walked 14km/hr instead of 10km/hr,he will reach
20km more(but the time is same).

If he walked 10km/hr, we take that distance covered is Xkm.

If he walked 14km/hr, we take that distance covered X+20km.

But for a both cases time is the same.
(Time = distance/speed).

Since X/10 = (X+20)/14.
14X = 10X+200
4X = 200
X = 50km.
(49)

Jason Valentine said:   10 months ago
His actual speed is 10 km/h and from the given question.
14x-10x = 20,
4x = 20,
x = 5 hours.

Then the actual distance will be;
10 * 5 = 50 km.
(44)

Liashee said:   3 years ago
D= (S1*T ) - (S2*T)
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T
= 10km/hr * 5hr.
= 50km.

I hope this was helpful.
(32)

Meghan Desai said:   2 years ago
Let
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).

Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.

Actual distance (at actual speed):-
10kmphx 5hrs = 50km.

That's the answer.
(30)


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