# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)

3.

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Answer: Option

Explanation:

Let the actual distance travelled be *x* km.

Then, | x |
= | x + 20 |

10 | 14 |

14*x* = 10*x* + 200

4*x* = 200

*x* = 50 km.

Discussion:

164 comments Page 1 of 17.
Salsabil said:
2 years ago

According to me, by using the simple formula we can iterate lucidly like this way,

Let the time be x hours

According to the question;

14x - 10x = 20

4x = 20

x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.

Let the time be x hours

According to the question;

14x - 10x = 20

4x = 20

x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.

(195)

Tariq said:
10 months ago

Given:

S1= 14km/h

S2= 10km/h

D1= 20km

D2=?

Solution:

We know that; (Distance= Speed * Time)

We first need to know the time taken,

By putting values:

20km = 14km/h (s1) - 10km/h (s2)

20km = 4 km/h,

20/4 = 5.

So the time (T) is 5.

Similarly, putting values we get;

D2 (actual distance)= 10km/h (actual speed) * 5 (time).

Distance= 10*5km.

Actual distance= 50km.

S1= 14km/h

S2= 10km/h

D1= 20km

D2=?

Solution:

We know that; (Distance= Speed * Time)

We first need to know the time taken,

By putting values:

20km = 14km/h (s1) - 10km/h (s2)

20km = 4 km/h,

20/4 = 5.

So the time (T) is 5.

Similarly, putting values we get;

D2 (actual distance)= 10km/h (actual speed) * 5 (time).

Distance= 10*5km.

Actual distance= 50km.

(118)

MO HASAN said:
6 months ago

His actual speed is 10 km/h and from given question.

14x-10x = 20,

4x = 20,

x = 5 hours.

then the actual distance will be;

10*5 = 50 km.

14x-10x = 20,

4x = 20,

x = 5 hours.

then the actual distance will be;

10*5 = 50 km.

(83)

Pulyala ajith kumar said:
11 months ago

The difference between distances is 20km and d = s * t.

So 14x-10x = 20.

x = 5hrs

The actual distance is s*t = 10 * 5 = 50km.

So 14x-10x = 20.

x = 5hrs

The actual distance is s*t = 10 * 5 = 50km.

(52)

Liashee said:
2 years ago

D= (S1*T ) - (S2*T)

20= (14*T) - (10*T)

20= 14T - 10T

T = 20/4

T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T

= 10km/hr * 5hr.

= 50km.

I hope this was helpful.

20= (14*T) - (10*T)

20= 14T - 10T

T = 20/4

T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T

= 10km/hr * 5hr.

= 50km.

I hope this was helpful.

(32)

Meghan Desai said:
10 months ago

Let

Actual distance is 'X' - (at 10kmph),

Distance afterwards is 'X+20' - (at 14kmph).

Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)

2. X+20 = 14Y

X = 14Y-20 ---> (b).

Comparing a&b we have;

10Y = 14Y-20

So, 14Y-10Y = 20;

and, Y = 5hrs.

Actual distance (at actual speed):-

10kmphx 5hrs = 50km.

That's the answer.

Actual distance is 'X' - (at 10kmph),

Distance afterwards is 'X+20' - (at 14kmph).

Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)

2. X+20 = 14Y

X = 14Y-20 ---> (b).

Comparing a&b we have;

10Y = 14Y-20

So, 14Y-10Y = 20;

and, Y = 5hrs.

Actual distance (at actual speed):-

10kmphx 5hrs = 50km.

That's the answer.

(29)

Epaphra said:
2 years ago

@All.

According to me;

Let the actual distance = y.

At speed of 10KMPH, the distance is y.

So, 10kmph = y.

This implies, 1kmph=y/10 ------> (1).

When he travels at a speed, of 14kmph, the distance is y+20.

So, 14kmph = y+20.

This implies, 1kmph=(y+20)/14 -------> (2)

EQUATE (1)AND (2).

y/10 = (y+20)/14

14y = 10y+200

4y = 200

y = 50km.

According to me;

Let the actual distance = y.

At speed of 10KMPH, the distance is y.

So, 10kmph = y.

This implies, 1kmph=y/10 ------> (1).

When he travels at a speed, of 14kmph, the distance is y+20.

So, 14kmph = y+20.

This implies, 1kmph=(y+20)/14 -------> (2)

EQUATE (1)AND (2).

y/10 = (y+20)/14

14y = 10y+200

4y = 200

y = 50km.

(28)

Chahat said:
10 months ago

Thanks, everyone for explaining.

(19)

Vineel said:
2 years ago

Distance = a/x-y *y.

20/14 - 10 * 10,

20/4 * 10 = 5 * 10 = 50km.

20/14 - 10 * 10,

20/4 * 10 = 5 * 10 = 50km.

(13)

Sriya said:
1 year ago

Thanks for your explanation, it's easy to understand @Gowtham.

(13)

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers