Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
Then, | x | = | x + 20 |
10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
170 comments Page 1 of 17.
Salsabil said:
2 years ago
According to me, by using the simple formula we can iterate lucidly like this way,
Let the time be x hours
According to the question;
14x - 10x = 20
4x = 20
x = 5 hours.
His actual speed is 10 km/h.
So, the actual distance is 10 * 5 = 50 km.
Let the time be x hours
According to the question;
14x - 10x = 20
4x = 20
x = 5 hours.
His actual speed is 10 km/h.
So, the actual distance is 10 * 5 = 50 km.
(201)
Tariq said:
2 years ago
Given:
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?
Solution:
We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:
20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.
Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?
Solution:
We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:
20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.
Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
(128)
MO HASAN said:
1 year ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(94)
TAMIL SELVAN said:
8 months ago
By ratio method, if time is constant speed is directly proportional to distance so;
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
(94)
Priya said:
9 months ago
According to me;
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
(61)
Pulyala ajith kumar said:
2 years ago
The difference between distances is 20km and d = s * t.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
(53)
Vijeth BK said:
6 months ago
The speed of man is =10km/hr.
In question that given if he walked 14km/hr instead of 10km/hr,he will reach
20km more(but the time is same).
If he walked 10km/hr, we take that distance covered is Xkm.
If he walked 14km/hr, we take that distance covered X+20km.
But for a both cases time is the same.
(Time = distance/speed).
Since X/10 = (X+20)/14.
14X = 10X+200
4X = 200
X = 50km.
In question that given if he walked 14km/hr instead of 10km/hr,he will reach
20km more(but the time is same).
If he walked 10km/hr, we take that distance covered is Xkm.
If he walked 14km/hr, we take that distance covered X+20km.
But for a both cases time is the same.
(Time = distance/speed).
Since X/10 = (X+20)/14.
14X = 10X+200
4X = 200
X = 50km.
(49)
Jason Valentine said:
10 months ago
His actual speed is 10 km/h and from the given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
Then the actual distance will be;
10 * 5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
Then the actual distance will be;
10 * 5 = 50 km.
(44)
Liashee said:
3 years ago
D= (S1*T ) - (S2*T)
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.
Therefore Actual distance where actual speed was 10km/ hr.
D= S*T
= 10km/hr * 5hr.
= 50km.
I hope this was helpful.
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.
Therefore Actual distance where actual speed was 10km/ hr.
D= S*T
= 10km/hr * 5hr.
= 50km.
I hope this was helpful.
(32)
Meghan Desai said:
2 years ago
Let
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.
FORMULA: Distance = Speed x Time.
1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).
Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.
Actual distance (at actual speed):-
10kmphx 5hrs = 50km.
That's the answer.
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.
FORMULA: Distance = Speed x Time.
1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).
Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.
Actual distance (at actual speed):-
10kmphx 5hrs = 50km.
That's the answer.
(30)
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