# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
50 km
56 km
70 km
80 km
Explanation:

Let the actual distance travelled be x km.

 Then, x = x + 20 10 14

14x = 10x + 200

4x = 200

x = 50 km.

Discussion:
164 comments Page 1 of 17.

Salsabil said:   2 years ago
According to me, by using the simple formula we can iterate lucidly like this way,

Let the time be x hours

According to the question;

14x - 10x = 20
4x = 20
x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.
(195)

Tariq said:   10 months ago
Given:
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?

Solution:

We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:

20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.

Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
(118)

MO HASAN said:   6 months ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(83)

Pulyala ajith kumar said:   11 months ago
The difference between distances is 20km and d = s * t.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
(52)

Liashee said:   2 years ago
D= (S1*T ) - (S2*T)
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T
= 10km/hr * 5hr.
= 50km.

(32)

Meghan Desai said:   10 months ago
Let
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.

FORMULA: Distance = Speed x Time.

1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).

Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.

Actual distance (at actual speed):-
10kmphx 5hrs = 50km.

(29)

Epaphra said:   2 years ago
@All.

According to me;

Let the actual distance = y.

At speed of 10KMPH, the distance is y.

So, 10kmph = y.
This implies, 1kmph=y/10 ------> (1).

When he travels at a speed, of 14kmph, the distance is y+20.
So, 14kmph = y+20.
This implies, 1kmph=(y+20)/14 -------> (2)
EQUATE (1)AND (2).

y/10 = (y+20)/14
14y = 10y+200
4y = 200
y = 50km.
(28)

Chahat said:   10 months ago
Thanks, everyone for explaining.
(19)

Vineel said:   2 years ago
Distance = a/x-y *y.
20/14 - 10 * 10,
20/4 * 10 = 5 * 10 = 50km.
(13)

Sriya said:   1 year ago
Thanks for your explanation, it's easy to understand @Gowtham.
(13)