Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
170 comments Page 2 of 17.
Epaphra said:
3 years ago
@All.
According to me;
Let the actual distance = y.
At speed of 10KMPH, the distance is y.
So, 10kmph = y.
This implies, 1kmph=y/10 ------> (1).
When he travels at a speed, of 14kmph, the distance is y+20.
So, 14kmph = y+20.
This implies, 1kmph=(y+20)/14 -------> (2)
EQUATE (1)AND (2).
y/10 = (y+20)/14
14y = 10y+200
4y = 200
y = 50km.
According to me;
Let the actual distance = y.
At speed of 10KMPH, the distance is y.
So, 10kmph = y.
This implies, 1kmph=y/10 ------> (1).
When he travels at a speed, of 14kmph, the distance is y+20.
So, 14kmph = y+20.
This implies, 1kmph=(y+20)/14 -------> (2)
EQUATE (1)AND (2).
y/10 = (y+20)/14
14y = 10y+200
4y = 200
y = 50km.
(29)
Kaviprema k said:
1 year ago
We don't know the actual distance so let we consider it as x.
The actual speed is 10 km/ hr ->x.
Another speed is 14 km/hr ->x + 20 km.
( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)
So,
X/ 10 = x+20/14,
14x = 10x+200,
14x-10x = 200,
4x = 200,
x = 200/4,
x = 50.
So,the actual distance is 50 km.
The actual speed is 10 km/ hr ->x.
Another speed is 14 km/hr ->x + 20 km.
( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)
So,
X/ 10 = x+20/14,
14x = 10x+200,
14x-10x = 200,
4x = 200,
x = 200/4,
x = 50.
So,the actual distance is 50 km.
(28)
Chahat Mishra said:
1 month ago
Very easy approach:
Here d1 - d2 = 14 - 10 = 4km/h.
Now 4 = 20.
Then 1 = 5.
The actual distance is 10 * 5 = 50km.
Here d1 - d2 = 14 - 10 = 4km/h.
Now 4 = 20.
Then 1 = 5.
The actual distance is 10 * 5 = 50km.
(27)
Anwaar said:
7 months ago
At usual time Period, a man Covers a Distance of 10 KM/hr ,But he has increased the Speed to 14 km/hr.
That means he will going 4 Km/hr additionally.
To Cover the Distance of 20 km with the Same of 14 km/hr he has to travel additional 5 hours.
4km * 5hrs = 20 km.
After 5 hours of travel if the person is travelling at the speed of 10 km/hr covers;
D = S * T/
D = 1 0 *5.
D = 50 KM.
That means he will going 4 Km/hr additionally.
To Cover the Distance of 20 km with the Same of 14 km/hr he has to travel additional 5 hours.
4km * 5hrs = 20 km.
After 5 hours of travel if the person is travelling at the speed of 10 km/hr covers;
D = S * T/
D = 1 0 *5.
D = 50 KM.
(23)
Chahat said:
2 years ago
Thanks, everyone for explaining.
(19)
Vineel said:
2 years ago
Distance = a/x-y *y.
20/14 - 10 * 10,
20/4 * 10 = 5 * 10 = 50km.
20/14 - 10 * 10,
20/4 * 10 = 5 * 10 = 50km.
(14)
Sriya said:
2 years ago
Thanks for your explanation, it's easy to understand @Gowtham.
(13)
Vishal said:
1 year ago
Why t in both the equation is same?
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
(12)
Anomiee said:
9 months ago
Thanks for explaining.
(12)
Aryan said:
2 years ago
@All,
According to me, the solution is;
For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
According to me, the solution is;
For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
(10)
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