# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)

3.

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Answer: Option

Explanation:

Let the actual distance travelled be *x* km.

Then, | x |
= | x + 20 |

10 | 14 |

14*x* = 10*x* + 200

4*x* = 200

*x* = 50 km.

Discussion:

164 comments Page 1 of 17.
Raghavendra said:
1 decade ago

I'm not clear with the answer. Why did you take the time same in both the cases?

(2)

Gowtham said:
1 decade ago

For the same interval if the person travelled in 14 kmph so only.

or else you could solve like this

1st hour 10 =14

2nd hour 20 =28

3rd hour 30 =42

4th hour 40 =56

5th hour 50 =70

At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km. So 70 - 50 = 20. I think u got it.

or else you could solve like this

1st hour 10 =14

2nd hour 20 =28

3rd hour 30 =42

4th hour 40 =56

5th hour 50 =70

At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km. So 70 - 50 = 20. I think u got it.

(4)

Satish said:
1 decade ago

Please give express that how to make this equation ?

(1)

Nitesh said:
1 decade ago

@Gowtham

But it is not written that time instance is same.

But it is not written that time instance is same.

Savitha said:
1 decade ago

I am not clear with the explanation and I didn't understand this step x/10=x+20/14.

Kinnari said:
1 decade ago

It goes by the formula S=D/T (Speed = Distance/Time)

So, T = D/S => T=x/10 ............(1)

T = x+20/14 .........(2)

Taking both the times together we get frm (1) and (2)

x/10=x+20/14

Now solve it as shown above. Hope you get it now.

So, T = D/S => T=x/10 ............(1)

T = x+20/14 .........(2)

Taking both the times together we get frm (1) and (2)

x/10=x+20/14

Now solve it as shown above. Hope you get it now.

(1)

Krishna said:
1 decade ago

I agree with gautam .... the time is not constant in both cases.

So it is false ..... how to equate them

He travels at 10km/hr and walks d km in t1 hrs

Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs

How can u equate t1 and t2? It is not given.

So it is false ..... how to equate them

He travels at 10km/hr and walks d km in t1 hrs

Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs

How can u equate t1 and t2? It is not given.

Ankit said:
1 decade ago

Thanks kinnari. I got it.

Muneer said:
1 decade ago

Let distance travelled be x,

Since the time taken is same here so,

time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph

(x+20)/14=x/10

5x+100=7x

2x=100

x=50

Since the time taken is same here so,

time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph

(x+20)/14=x/10

5x+100=7x

2x=100

x=50

Xyz said:
1 decade ago

Why did you take time same in both the cases?

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers