Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
170 comments Page 1 of 17.
Raghavendra said:
1 decade ago
I'm not clear with the answer. Why did you take the time same in both the cases?
(2)
Gowtham said:
1 decade ago
For the same interval if the person travelled in 14 kmph so only.
or else you could solve like this
1st hour 10 =14
2nd hour 20 =28
3rd hour 30 =42
4th hour 40 =56
5th hour 50 =70
At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km. So 70 - 50 = 20. I think u got it.
or else you could solve like this
1st hour 10 =14
2nd hour 20 =28
3rd hour 30 =42
4th hour 40 =56
5th hour 50 =70
At speed 10 kmph he reaches 50 km at the same time if he travels in 14 kmph he would reach 70 km. So 70 - 50 = 20. I think u got it.
(4)
Satish said:
1 decade ago
Please give express that how to make this equation ?
(1)
Nitesh said:
1 decade ago
@Gowtham
But it is not written that time instance is same.
But it is not written that time instance is same.
Savitha said:
1 decade ago
I am not clear with the explanation and I didn't understand this step x/10=x+20/14.
Kinnari said:
1 decade ago
It goes by the formula S=D/T (Speed = Distance/Time)
So, T = D/S => T=x/10 ............(1)
T = x+20/14 .........(2)
Taking both the times together we get frm (1) and (2)
x/10=x+20/14
Now solve it as shown above. Hope you get it now.
So, T = D/S => T=x/10 ............(1)
T = x+20/14 .........(2)
Taking both the times together we get frm (1) and (2)
x/10=x+20/14
Now solve it as shown above. Hope you get it now.
(1)
Krishna said:
1 decade ago
I agree with gautam .... the time is not constant in both cases.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
Ankit said:
1 decade ago
Thanks kinnari. I got it.
Muneer said:
1 decade ago
Let distance travelled be x,
Since the time taken is same here so,
time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph
(x+20)/14=x/10
5x+100=7x
2x=100
x=50
Since the time taken is same here so,
time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph
(x+20)/14=x/10
5x+100=7x
2x=100
x=50
Xyz said:
1 decade ago
Why did you take time same in both the cases?
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