# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)

3.

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Answer: Option

Explanation:

Let the actual distance travelled be *x* km.

Then, | x |
= | x + 20 |

10 | 14 |

14*x* = 10*x* + 200

4*x* = 200

*x* = 50 km.

Discussion:

164 comments Page 2 of 17.
Aryan said:
11 months ago

@All,

According to me, the solution is;

For every 1 km/hr there is 5 km distance travelled;

So for 10km/hr there is 50km distance travelled;

which means for 4 more km/hr in question there is 20 kM distance.

So, for 10 km it's 50 km.

According to me, the solution is;

For every 1 km/hr there is 5 km distance travelled;

So for 10km/hr there is 50km distance travelled;

which means for 4 more km/hr in question there is 20 kM distance.

So, for 10 km it's 50 km.

(10)

Gaurav Raghav said:
11 months ago

Let the actual speed be x.

Let the time be y.

Distance = Speed * time

Therefore,

X= 10y.

But, now he would have travelled 20 km more if the speed was 14km/hr.

therefore,

14x= y+20.

Subtracting both equations,

14x = y+20,

10x = y.

we get;

4x = 20,

x = 5.

Put y in the equation

10 * 5 = 50 Kms.

Verify it by putting 5 in both equations.

Let the time be y.

Distance = Speed * time

Therefore,

X= 10y.

But, now he would have travelled 20 km more if the speed was 14km/hr.

therefore,

14x= y+20.

Subtracting both equations,

14x = y+20,

10x = y.

we get;

4x = 20,

x = 5.

Put y in the equation

10 * 5 = 50 Kms.

Verify it by putting 5 in both equations.

(9)

Habtamu dese said:
1 year ago

Good to understand. Thanks everyone for explaining the answer.

(8)

Sriya said:
1 year ago

Thanks for your explanation, it's easy to understand @Gowtham.

(13)

Salsabil said:
2 years ago

According to me, by using the simple formula we can iterate lucidly like this way,

Let the time be x hours

According to the question;

14x - 10x = 20

4x = 20

x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.

Let the time be x hours

According to the question;

14x - 10x = 20

4x = 20

x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.

(195)

Vineel said:
2 years ago

Distance = a/x-y *y.

20/14 - 10 * 10,

20/4 * 10 = 5 * 10 = 50km.

20/14 - 10 * 10,

20/4 * 10 = 5 * 10 = 50km.

(13)

Epaphra said:
2 years ago

@All.

According to me;

Let the actual distance = y.

At speed of 10KMPH, the distance is y.

So, 10kmph = y.

This implies, 1kmph=y/10 ------> (1).

When he travels at a speed, of 14kmph, the distance is y+20.

So, 14kmph = y+20.

This implies, 1kmph=(y+20)/14 -------> (2)

EQUATE (1)AND (2).

y/10 = (y+20)/14

14y = 10y+200

4y = 200

y = 50km.

According to me;

Let the actual distance = y.

At speed of 10KMPH, the distance is y.

So, 10kmph = y.

This implies, 1kmph=y/10 ------> (1).

When he travels at a speed, of 14kmph, the distance is y+20.

So, 14kmph = y+20.

This implies, 1kmph=(y+20)/14 -------> (2)

EQUATE (1)AND (2).

y/10 = (y+20)/14

14y = 10y+200

4y = 200

y = 50km.

(28)

Abc said:
2 years ago

Thanks @Kinnari.

Sai said:
2 years ago

Explain it clearly.

(2)

Liashee said:
2 years ago

D= (S1*T ) - (S2*T)

20= (14*T) - (10*T)

20= 14T - 10T

T = 20/4

T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T

= 10km/hr * 5hr.

= 50km.

I hope this was helpful.

20= (14*T) - (10*T)

20= 14T - 10T

T = 20/4

T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T

= 10km/hr * 5hr.

= 50km.

I hope this was helpful.

(32)

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