Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
176 comments Page 2 of 18.
TAMIL SELVAN said:
2 years ago
By ratio method, if time is constant speed is directly proportional to distance so;
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
(120)
Ramachandra said:
2 years ago
Let,
Actual dist = X(at-10km\hr).
x/10 = x + 20/14,
14x = 10x + 20,
14x - 10x = 20,
4x = 20,
x = 20/4,
x = 5.
The actual distance at 10kmph * actual distance.
= 10 * 5,
= 50km.
So, the answer is 50km.
Actual dist = X(at-10km\hr).
x/10 = x + 20/14,
14x = 10x + 20,
14x - 10x = 20,
4x = 20,
x = 20/4,
x = 5.
The actual distance at 10kmph * actual distance.
= 10 * 5,
= 50km.
So, the answer is 50km.
(11)
Priya said:
2 years ago
According to me;
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
(66)
Jason Valentine said:
2 years ago
His actual speed is 10 km/h and from the given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
Then the actual distance will be;
10 * 5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
Then the actual distance will be;
10 * 5 = 50 km.
(49)
SILEBCE said:
2 years ago
According to me, the right answer is 50km.
(6)
Kaviprema k said:
2 years ago
We don't know the actual distance so let we consider it as x.
The actual speed is 10 km/ hr ->x.
Another speed is 14 km/hr ->x + 20 km.
( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)
So,
X/ 10 = x+20/14,
14x = 10x+200,
14x-10x = 200,
4x = 200,
x = 200/4,
x = 50.
So,the actual distance is 50 km.
The actual speed is 10 km/ hr ->x.
Another speed is 14 km/hr ->x + 20 km.
( because we have considered distance is x and if he had walked 14 km/ hr then he would have walked 20 km more)
So,
X/ 10 = x+20/14,
14x = 10x+200,
14x-10x = 200,
4x = 200,
x = 200/4,
x = 50.
So,the actual distance is 50 km.
(29)
Vishal said:
3 years ago
Why t in both the equation is same?
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
(13)
MO HASAN said:
3 years ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(94)
Tariq said:
3 years ago
Given:
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?
Solution:
We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:
20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.
Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?
Solution:
We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:
20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.
Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
(133)
Chahat said:
3 years ago
Thanks, everyone for explaining.
(20)
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