# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
50 km
56 km
70 km
80 km
Explanation:

Let the actual distance travelled be x km.

 Then, x = x + 20 10 14

14x = 10x + 200

4x = 200

x = 50 km.

Discussion:
164 comments Page 2 of 17.

Aryan said:   11 months ago
@All,

According to me, the solution is;

For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
(10)

Gaurav Raghav said:   11 months ago
Let the actual speed be x.
Let the time be y.

Distance = Speed * time

Therefore,
X= 10y.

But, now he would have travelled 20 km more if the speed was 14km/hr.
therefore,
14x= y+20.

Subtracting both equations,
14x = y+20,
10x = y.

we get;
4x = 20,
x = 5.
Put y in the equation
10 * 5 = 50 Kms.
Verify it by putting 5 in both equations.
(9)

Habtamu dese said:   1 year ago
Good to understand. Thanks everyone for explaining the answer.
(8)

Sriya said:   1 year ago
Thanks for your explanation, it's easy to understand @Gowtham.
(13)

Salsabil said:   2 years ago
According to me, by using the simple formula we can iterate lucidly like this way,

Let the time be x hours

According to the question;

14x - 10x = 20
4x = 20
x = 5 hours.

His actual speed is 10 km/h.

So, the actual distance is 10 * 5 = 50 km.
(195)

Vineel said:   2 years ago
Distance = a/x-y *y.
20/14 - 10 * 10,
20/4 * 10 = 5 * 10 = 50km.
(13)

Epaphra said:   2 years ago
@All.

According to me;

Let the actual distance = y.

At speed of 10KMPH, the distance is y.

So, 10kmph = y.
This implies, 1kmph=y/10 ------> (1).

When he travels at a speed, of 14kmph, the distance is y+20.
So, 14kmph = y+20.
This implies, 1kmph=(y+20)/14 -------> (2)
EQUATE (1)AND (2).

y/10 = (y+20)/14
14y = 10y+200
4y = 200
y = 50km.
(28)

Abc said:   2 years ago
Thanks @Kinnari.

Sai said:   2 years ago
Explain it clearly.
(2)

Liashee said:   2 years ago
D= (S1*T ) - (S2*T)
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.

Therefore Actual distance where actual speed was 10km/ hr.

D= S*T
= 10km/hr * 5hr.
= 50km.

I hope this was helpful.
(32)