Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
348 comments Page 1 of 35.
SHREYA said:
2 days ago
The speed of the car is x km/h.
The speed of the train = x + 50x/100,
= 150x/100,
= 3x/2 km/h.
The time taken by the car = 75/x.
The time taken by the train = 75/(3x/2).
The difference between them is 12.5 minutes.
75/x - 75/(3x/2) = 12.5 minutes.
To convert minutes to hours, divide the number by 60,
Therefore,
75/x - 75/(3x/2) = 12.5/60 hr,
75/x - 75/(3x/2) = 125/(10*60) hr,
75/x - 50/x = 5/24,
25/x = 5/24,
5x = 25*24.
x = 120 km/hr.
The speed of the train = x + 50x/100,
= 150x/100,
= 3x/2 km/h.
The time taken by the car = 75/x.
The time taken by the train = 75/(3x/2).
The difference between them is 12.5 minutes.
75/x - 75/(3x/2) = 12.5 minutes.
To convert minutes to hours, divide the number by 60,
Therefore,
75/x - 75/(3x/2) = 12.5/60 hr,
75/x - 75/(3x/2) = 125/(10*60) hr,
75/x - 50/x = 5/24,
25/x = 5/24,
5x = 25*24.
x = 120 km/hr.
(2)
Deepana M said:
2 weeks ago
The train can travel 50% faster than a car. How to define 150 here? Please explain.
(2)
Anu said:
4 weeks ago
Most of people saying 1/2 instead of 3/2 is wrong.
The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
(6)
Abhishek S k said:
1 month ago
I didn't understand this, anyone please explain to me?
(6)
Jithen M S said:
2 months ago
(The train can travel 50% faster than a car).
This means the train is travelling 1/2 time faster than the car, not 3/2 time faster.
Final Answer: Speed of the car = 100 kmph.
This means the train is travelling 1/2 time faster than the car, not 3/2 time faster.
Final Answer: Speed of the car = 100 kmph.
(6)
ANom said:
3 months ago
Speed of car =2/3 the speed of the train.
ie Vc=2/3 Vt, therefore,
Time taken by car =3/2 Time taken by train ie.Tc=3/2 Tt.
Also,
Tc = Tt+15/60 hr ie. Tc = Tt + 1/4.
Therefore:
3/2 Tt = Tt+1/4
Tt = 1/2 = 0.5 hr.
Therefore, Tc = 0.75 = hr.
Distance = v x t.
75 km = Vc x 0.75,
Vc = 100km
Vt = 120.
ie Vc=2/3 Vt, therefore,
Time taken by car =3/2 Time taken by train ie.Tc=3/2 Tt.
Also,
Tc = Tt+15/60 hr ie. Tc = Tt + 1/4.
Therefore:
3/2 Tt = Tt+1/4
Tt = 1/2 = 0.5 hr.
Therefore, Tc = 0.75 = hr.
Distance = v x t.
75 km = Vc x 0.75,
Vc = 100km
Vt = 120.
(3)
Lokesh said:
4 months ago
I am not understanding this question. Please explain to me.
(19)
Deshik said:
4 months ago
Formula:
Time = distance/speed.
Speed = distance/time.
Let speed of train = x.
Then speed of the car = x + (x(50)/100),
= x + x/2,
= 3x/2,
The time taken by the train = 75/x.
The time taken by the car = 75/(3x/2).
Difference between them = 12.5 minutes,
75/x - 75/(3x/2) = 125/10 minutes,
75/x - 75/(3x/2) = 125/(10*60) hr,
(225-150)/3x=125/600,
75/3x = 125/600,
25/x = 125/600,
x = (25*600)/125,
x = 120kmph.
Time = distance/speed.
Speed = distance/time.
Let speed of train = x.
Then speed of the car = x + (x(50)/100),
= x + x/2,
= 3x/2,
The time taken by the train = 75/x.
The time taken by the car = 75/(3x/2).
Difference between them = 12.5 minutes,
75/x - 75/(3x/2) = 125/10 minutes,
75/x - 75/(3x/2) = 125/(10*60) hr,
(225-150)/3x=125/600,
75/3x = 125/600,
25/x = 125/600,
x = (25*600)/125,
x = 120kmph.
(52)
ABHISHEK said:
4 months ago
The speed of car be x km/h.
Then speed of the train will be = 3x/2km/h,
and the time taken to cover up 75 km is equal, but the train lost about 12.5 minutes while stopping at the stations.
So 75/x - 50/x = 5/24,
x= 120km/h.
Then speed of the train will be = 3x/2km/h,
and the time taken to cover up 75 km is equal, but the train lost about 12.5 minutes while stopping at the stations.
So 75/x - 50/x = 5/24,
x= 120km/h.
(3)
Adlin Jenu said:
5 months ago
The speed of the train: speed of the car = 150 : 100 = 3 : 2.
From the formula ; ratio of the speed = a:b,
if the same distance then, ratio of the time = b : a
Time ratio = 2:3
1u = 12.5 min
2u = 25 min
3u = 37.5 min.
The time taken by the car in hr = 37.5/60 = 375/600,
= 5/8 hr.
SPEED OF THE CAR IS = 75 divided by 5/8.
= 15 * 8.
= 120 km /hr.
From the formula ; ratio of the speed = a:b,
if the same distance then, ratio of the time = b : a
Time ratio = 2:3
1u = 12.5 min
2u = 25 min
3u = 37.5 min.
The time taken by the car in hr = 37.5/60 = 375/600,
= 5/8 hr.
SPEED OF THE CAR IS = 75 divided by 5/8.
= 15 * 8.
= 120 km /hr.
(34)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers