Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
325 comments Page 1 of 33.
Ravi said:
2 months ago
Anyone, please explain how can be the term (150/100) mean?
(18)
Pavan said:
3 months ago
Let time is t.
Suppose Car is going at speed x,
Train speed will be x+(x/2) = 3x/2 -------> 1
Speed of Train(dist/time) = 75/(t-12.5) ------> 2
1 =2.
3x/2 = 75/t ----->3
Speed of car = 75/t.
x = 75/t ----> 4.
substitute 4 in 3.
By solving you get;
time of car(t) = 37.5(in min)
By converting into hr.
t = 0.625 hr.
Speed of car = 75/0.625.
Ans : 120kmph
Suppose Car is going at speed x,
Train speed will be x+(x/2) = 3x/2 -------> 1
Speed of Train(dist/time) = 75/(t-12.5) ------> 2
1 =2.
3x/2 = 75/t ----->3
Speed of car = 75/t.
x = 75/t ----> 4.
substitute 4 in 3.
By solving you get;
time of car(t) = 37.5(in min)
By converting into hr.
t = 0.625 hr.
Speed of car = 75/0.625.
Ans : 120kmph
(17)
Navik said:
3 months ago
T:C ( speed) = 3:2.
T:C ( time) = 2:3.
Time taken by car = 12.5× 3.
Speed of the car = 120 km/h.
T:C ( time) = 2:3.
Time taken by car = 12.5× 3.
Speed of the car = 120 km/h.
(29)
Bindu sree said:
4 months ago
The speed of train and car = 150 : 100 = 3 : 2.
Speed = 1/time,
Time = 2 : 3.
Delay = 12.5 for train,
So, car time = train delay × 3 = 3 × 12.5 = 37.5min = 37.5/60 = 5/8h.
Finally speed = d/t =75/5/8 =120km/h.
Speed = 1/time,
Time = 2 : 3.
Delay = 12.5 for train,
So, car time = train delay × 3 = 3 × 12.5 = 37.5min = 37.5/60 = 5/8h.
Finally speed = d/t =75/5/8 =120km/h.
(48)
Rutuja P said:
5 months ago
Speed of car=Sc ; speed of train =St
Sc:St= 100:150 ( A train can travel 50% faster than a car)
= 2:3 -----> (1)
and therefore Tc:Tt= 3:2 -----> (2)
Delay given= 12.5 min = 12.5/60hrs.
Therefore time for car, Tc= 3*12.5/60 = 12.5/20 (refer (2)Tc:Tt= 3:2 )
Distance given= 75km.
We know, Speed= Distance/Time.
Therefore, the speed of the car,
Sc= 75/(12.5/20),
= 120 km/hr.
Sc:St= 100:150 ( A train can travel 50% faster than a car)
= 2:3 -----> (1)
and therefore Tc:Tt= 3:2 -----> (2)
Delay given= 12.5 min = 12.5/60hrs.
Therefore time for car, Tc= 3*12.5/60 = 12.5/20 (refer (2)Tc:Tt= 3:2 )
Distance given= 75km.
We know, Speed= Distance/Time.
Therefore, the speed of the car,
Sc= 75/(12.5/20),
= 120 km/hr.
(71)
Animesh Biswas said:
5 months ago
T:C ( speed) = 3:2.
T:C ( time) = 2:3.
Time is taken by car = 12.5× 3.
Speed of the car = 120 km/h.
T:C ( time) = 2:3.
Time is taken by car = 12.5× 3.
Speed of the car = 120 km/h.
(35)
Saloni Adhikari said:
5 months ago
Here, How can we say given time in the question is equal to the value obtained after subtraction? Please explain me.
(10)
AP bhai said:
5 months ago
Case1: For car;
D = TV.
75=TV.
Case2:
75={T+(12.5/60)}*1.5V.
75={(60T+12.5)*V}/40.
Now, compare case 1&2.
You get, T = 12.5/20;
As. D = TV.
75 = 12.5/20*V,
V = 120.
D = TV.
75=TV.
Case2:
75={T+(12.5/60)}*1.5V.
75={(60T+12.5)*V}/40.
Now, compare case 1&2.
You get, T = 12.5/20;
As. D = TV.
75 = 12.5/20*V,
V = 120.
(2)
Sai Durga said:
6 months ago
Let the speed of the car be x.
Now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
Now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
(43)
Sai Durga said:
6 months ago
Let the speed of the train be x.
So, train speed 50% faster than car means x + x/2 = 3x/2, speed = 75km/hr,
time delayed = 12.5 mins==12.5/60 sec.
Now;
D/s = T; (here speed = speed of the car -speed of the train),
So,
75/x -75/3x/2 = 12.5/60.
75/x - 50/x = 5/24.
x = 25 x 24/5
x = 120 km/hr.
So, train speed 50% faster than car means x + x/2 = 3x/2, speed = 75km/hr,
time delayed = 12.5 mins==12.5/60 sec.
Now;
D/s = T; (here speed = speed of the car -speed of the train),
So,
75/x -75/3x/2 = 12.5/60.
75/x - 50/x = 5/24.
x = 25 x 24/5
x = 120 km/hr.
(22)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers