Aptitude - Surds and Indices
Why should I learn to solve Aptitude questions and answers section on "Surds and Indices"?
Learn and practise solving Aptitude questions and answers section on "Surds and Indices" to enhance your skills so that you can clear interviews, competitive examinations, and various entrance tests (CAT, GATE, GRE, MAT, bank exams, railway exams, etc.) with full confidence.
Where can I get the Aptitude questions and answers section on "Surds and Indices"?
IndiaBIX provides you with numerous Aptitude questions and answers based on "Surds and Indices" along with fully solved examples and detailed explanations that will be easy to understand.
Where can I get the Aptitude section on "Surds and Indices" MCQ-type interview questions and answers (objective type, multiple choice)?
Here you can find multiple-choice Aptitude questions and answers based on "Surds and Indices" for your placement interviews and competitive exams. Objective-type and true-or-false-type questions are given too.
How do I download the Aptitude questions and answers section on "Surds and Indices" in PDF format?
You can download the Aptitude quiz questions and answers section on "Surds and Indices" as PDF files or eBooks.
How do I solve Aptitude quiz problems based on "Surds and Indices"?
You can easily solve Aptitude quiz problems based on "Surds and Indices" by practising the given exercises, including shortcuts and tricks.
- Surds and Indices - Formulas
- Surds and Indices - General Questions
Let (17)3.5 x (17)x = 178.
Then, (17)3.5 + x = 178.
3.5 + x = 8
x = (8 - 3.5)
x = 4.5
If | ![]() |
a | ![]() |
x - 1 | = | ![]() |
b | ![]() |
x - 3 | , then the value of x is: |
b | a |
Given ![]() |
a | ![]() |
x - 1 | = | ![]() |
b | ![]() |
x - 3 |
b | a |
![]() |
![]() |
a | ![]() |
x - 1 | = | ![]() |
a | ![]() |
-(x - 3) | = | ![]() |
a | ![]() |
(3 - x) |
b | b | b |
x - 1 = 3 - x
2x = 4
x = 2.
xz = y2 10(0.48z) = 10(2 x 0.70) = 101.40
0.48z = 1.40
![]() |
140 | = | 35 | = 2.9 (approx.) |
48 | 12 |
5a = 3125 5a = 55
a = 5.
5(a - 3) = 5(5 - 3) = 52 = 25.
3x - y = 27 = 33 x - y = 3 ....(i)
3x + y = 243 = 35 x + y = 5 ....(ii)
On solving (i) and (ii), we get x = 4.