Aptitude - Simplification - Discussion

Discussion :: Simplification - General Questions (Q.No.8)

8. 

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

[A]. 30 birds
[B]. 60 birds
[C]. 72 birds
[D]. 90 birds

Answer: Option A

Explanation:

Let the total number of shots be x. Then,

Shots fired by A = 5 x
8

Shots fired by B = 3 x
8

Killing shots by A = 1 of 5 x = 5 x
3 8 24

Shots missed by B = 1 of 3 x = 3 x
2 8 16

3x = 27 or x = 27 x 16 = 144.
16 3

Birds killed by A = 5x = 5 x 144 = 30.
24 24


Pollard said: (Aug 18, 2010)  
Please anybody explain very simply..?

Suriya said: (Nov 3, 2010)  
Please anybody explain very simply. ? please help.

Hary said: (Dec 12, 2010)  
This can also be solved practically rather than theoretically.

It is given that B has missed 27 times and B kills once for 2 shots. So, total number of shots B has got is 27*2=54.

And also it is given that A gets 5 shots while B gets 3 shots. So,.

54/3=18.

The number of shots A gets is= 18*5=90.

But A kills once in every 3 shots, so 90/3=30.

No of birds killed by A is=30.

Naddy said: (Jan 15, 2011)  
Given:No of shots=8(A=5,B=3)
Suceeded shots of A= 1 of 3,so 1/3
Suceeded shots of B= 1 of 2,so 1/2
Failure shots of B=27

so Suceeded shots by A=1/3 of 5/8x=5/24*x
Suceeded shots by B=1/2 of 3/8x=3/16*x

therefore failure shots,3x/16=27 (because 27 is missed shots as per question),so x=144
Therefore succeded shots by A=5x/24 *144= 30

Chetna said: (Mar 25, 2011)  
How is the no. of failure shots equal to the no. of succeded shots.. i.e. 3x/18=27??

Franco said: (Mar 26, 2011)  
No. of failure shots equal to the no. of succeded shots
because B suceeds once in 2 shots
so probability of success is 1/2
probability of failure 1-(probability of success) =>1-1/2 = 1/2

Nabanita Sarkar said: (Jul 9, 2014)  
When B shots 2 it missed 1.
So, when B missed 27 B shoots (27*2) = 54.

When B shoots 3 at the same time A shoots 5.
So, total shoots of A = (5/3)*54 = 5*18= 90.

When A shoots 3 it killed 1.
So, when A shoots 90 it killed = 90/3 = 30.

Deepak said: (Jul 11, 2014)  
It is hard to understand how 5/8 and 3/8 comes please anyone can explain?

Rajtiwari said: (Jul 21, 2014)  
When total no of shots = 8.
A fired 5 times of 8 = 5/8.
B fires 3 times of 8.
Hence B's fired = 3/8.
A succeed 3 times in 5/8 shots.

Hence A succeed = 5/24 times similarly.
B succeed 2 times in 3/8 SHOTS.

B SUCCEED = 3/16 times and also failed 3/16 times.
If total no shots = x .

Then,
B's failed time = 3x/16.

Since,
B failed 27 time = 3x/16.

27=3x/16.
X=144=total no of shots.

A's total shot=failed+succeed.
=27+27=54.

B's shot=total-A's shot.
=144-54=90.

Then,
B's succeed =90/3=30.

Rahul said: (Oct 15, 2014)  
It is given that if A fires 5 shots B fires only 3 times.
It is given that p(A)=1/3 and p(B)=1/2.

It is also given that A missed 27 times so he fired totally 54 times.
From the above we can calculate that totally A fired 90 times.

So total successful firings by A=90*1/3=30.

Abhinav said: (Mar 16, 2015)  
B kills once in 2 shots.

No. of failure shots = 1.

No. of succeeded shots = 1.

When no. of failure shots = 27 then no. of succeeded shots = 27,

So, total no. of shots by B = 27+27 = 54.

When B shoots 3 shot then A shoots 5 shots.

So, When B shoots 1 shot then A shoots 5/3 shot.

So, When B shoots 54 shot then A shoots 54*5/3 = 90 shots.

When A shoots 3 it killed 1.

So, when A shoots 90 it killed = 90/3 = 30.

Kajora said: (May 13, 2015)  
The ratio of no.of shots by A to the no.of shots by B is 5:3.

Let the actual shots of A and B be 5x and 3x respectively.

B kills once in 2 shots means one shot of B gets success and another shot gets failure.

Total shots = 27 failed shots + 27 successful shots = 54.

That is 3x = 54.

x = (54/3) = 18.

A's total shots = 5x = 5(18) = 90.

A kills once in 3 shots means A's 2 shots get failed and 1 shot.

Achieves the target (kills the bird).

So, A has killed (90/3) = 30 birds.

Promodit said: (Jul 30, 2015)  
A kills 5 birds while b kills 3. And hit ratio of A and B is 3:2 resp. (given).

Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).

Varsha said: (Aug 27, 2015)  
How it is mean while A has shot 54*? And why (5/3) =90 times please tell me any one?

Zehra said: (Aug 30, 2015)  
A fires 5 shots and kills one in 3.

Therefore effective short by A = 3/5.

Similarly B = 2/3.

Also 3/5A = 2/3B.

Now, the no of birds killed by B in 27 shots would be 27*2/3 = 18.

When B kills 18 birds. No of birds killed by A = 18*5/3 = 30.

Can anybody tell me if I am doing it right?

Owaiz said: (Jan 27, 2016)  
Both A and B stand side by side and shoot at the same time. 5 bullets com out of A's gun and 3 bullets come out of B's gun. So the total no of bullets fired at once is 8.

Its given that A kills one in 3 shots and B kills one in 2 shots. Its also given that B misses 27 times.

As B Misses 27 times and kills one in two shots, the total bullets fired by B is 27*2 = 54.

We know that 3 bullets came out of B'S gun when he shot once.

So the no of times B shot is 54/3 = 18.

Also the no of bullets came out of A is 5 when he shot once and since both A and B shot same no of times i.e.18 times, so the total no of bullets came out of A's gun is 5*18 = 90 bullets.

As A killed one in three bullets, the total no of birds killed by A is 90/3 = 30.

Irshad Ahmad Tawav said: (Aug 13, 2016)  
Let A and B be 5x, 3x.

If x = 1, A = 5 B = 3,

If x = 2, A = 10 B = 6,

3x = 54,

=> x = 18,

Total number of shots of A = 5x

= 5 * 18 = 90,

Number of succeeding shots of A = 1/3 * total shots of A

= 1/3 * 90 = 30.

Smrithi said: (Jan 17, 2017)  
A:B=5:3.

27 shots fired failed by B.

Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.

A/B= 5/3.

Therefore A/54=5/3, hence total shorts of A = 90.

Probability that A hits = 1/3;

Therefore total shorts hit = 90 * 1/3 = 30.

Ryan said: (Jan 18, 2017)  
Any other simple method to solve this problem?

Saif said: (Feb 18, 2017)  
Thank you @Naddy.

Jas said: (Feb 18, 2017)  
Total shots = 8.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.

Dory said: (May 17, 2017)  
So if B kills once in 3 shots, miss shots by B = ( 1-(1/3) ) * (3x/8)?

Richa said: (Jun 18, 2017)  
Good job @Kajora.

Sai Ram said: (Sep 27, 2017)  
Thank you all.

Srinivas said: (Nov 8, 2017)  
Detail explanation of above problem please give me.

Taniya said: (Nov 29, 2017)  
Thanks for your explanation @Kajora.

Malay Giri said: (Dec 22, 2017)  
A-27*5=135,
b-27*3=81,
a-b=135-81,
=54/3=18,
A-18*5=90,
A=90/3=30.

Danish said: (Jan 12, 2018)  
Superb @Smrithi.

Siva said: (Jan 24, 2018)  
Well explained, Thanks @Smrithi.

Sudip said: (Feb 8, 2018)  
A:B=5:3.

Let no. of shots by A= 5x and B= 3x.

A kills after every 3 shots,
No. of birds killed by A= 5x/3.

B kills after every 2 shots,
No. of birds killed by B= 3x/2.
No. of shots missed by B= 3x-3x/2= 3x/2=27.
Therefore x= 27 x 2/3= 18.

No. of birds killed by A in that time= 5x/3= 5*18/3= 30.

Sapna said: (Mar 5, 2018)  
Thanks @Sudip.

Yamini Dhanasekar said: (Aug 20, 2018)  
Another way of solving this question by logic is,
B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots)
So totally,27+27=54 shots.
A fires 5 shots for b's 3.
A --------- B
5 --------- 3
?? --------- 54.

A=54 * 5/3=90 shots.
A has 90 shots,
A kills once in 3 shots, so 90/3 =30 birds.

Arun Congo said: (Jun 1, 2019)  
If A Shoot 5, B will shoot 3.

Assume in 1 Minute A can shoot 5 and B can shoot 3.
A Scores 1 out of 3, B scores 1 out of 2.

In question, we have 27 fails for B.

So in 9 minutes, B shoots 54 and scores 27 and fails 27.
In 9 Minutes, A shoot 90 and scores 30 and fails 60.

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