### Discussion :: Simplification - General Questions (Q.No.8)

Pollard said: (Aug 18, 2010) | |

Please anybody explain very simply..? |

Suriya said: (Nov 3, 2010) | |

Please anybody explain very simply. ? please help. |

Hary said: (Dec 12, 2010) | |

This can also be solved practically rather than theoretically. It is given that B has missed 27 times and B kills once for 2 shots. So, total number of shots B has got is 27*2=54. And also it is given that A gets 5 shots while B gets 3 shots. So,. 54/3=18. The number of shots A gets is= 18*5=90. But A kills once in every 3 shots, so 90/3=30. No of birds killed by A is=30. |

Naddy said: (Jan 15, 2011) | |

Given:No of shots=8(A=5,B=3) Suceeded shots of A= 1 of 3,so 1/3 Suceeded shots of B= 1 of 2,so 1/2 Failure shots of B=27 so Suceeded shots by A=1/3 of 5/8x=5/24*x Suceeded shots by B=1/2 of 3/8x=3/16*x therefore failure shots,3x/16=27 (because 27 is missed shots as per question),so x=144 Therefore succeded shots by A=5x/24 *144= 30 |

Chetna said: (Mar 25, 2011) | |

How is the no. of failure shots equal to the no. of succeded shots.. i.e. 3x/18=27?? |

Franco said: (Mar 26, 2011) | |

No. of failure shots equal to the no. of succeded shots because B suceeds once in 2 shots so probability of success is 1/2 probability of failure 1-(probability of success) =>1-1/2 = 1/2 |

Nabanita Sarkar said: (Jul 9, 2014) | |

When B shots 2 it missed 1. So, when B missed 27 B shoots (27*2) = 54. When B shoots 3 at the same time A shoots 5. So, total shoots of A = (5/3)*54 = 5*18= 90. When A shoots 3 it killed 1. So, when A shoots 90 it killed = 90/3 = 30. |

Deepak said: (Jul 11, 2014) | |

It is hard to understand how 5/8 and 3/8 comes please anyone can explain? |

Rajtiwari said: (Jul 21, 2014) | |

When total no of shots = 8. A fired 5 times of 8 = 5/8. B fires 3 times of 8. Hence B's fired = 3/8. A succeed 3 times in 5/8 shots. Hence A succeed = 5/24 times similarly. B succeed 2 times in 3/8 SHOTS. B SUCCEED = 3/16 times and also failed 3/16 times. If total no shots = x . Then, B's failed time = 3x/16. Since, B failed 27 time = 3x/16. 27=3x/16. X=144=total no of shots. A's total shot=failed+succeed. =27+27=54. B's shot=total-A's shot. =144-54=90. Then, B's succeed =90/3=30. |

Rahul said: (Oct 15, 2014) | |

It is given that if A fires 5 shots B fires only 3 times. It is given that p(A)=1/3 and p(B)=1/2. It is also given that A missed 27 times so he fired totally 54 times. From the above we can calculate that totally A fired 90 times. So total successful firings by A=90*1/3=30. |

Abhinav said: (Mar 16, 2015) | |

B kills once in 2 shots. No. of failure shots = 1. No. of succeeded shots = 1. When no. of failure shots = 27 then no. of succeeded shots = 27, So, total no. of shots by B = 27+27 = 54. When B shoots 3 shot then A shoots 5 shots. So, When B shoots 1 shot then A shoots 5/3 shot. So, When B shoots 54 shot then A shoots 54*5/3 = 90 shots. When A shoots 3 it killed 1. So, when A shoots 90 it killed = 90/3 = 30. |

Kajora said: (May 13, 2015) | |

The ratio of no.of shots by A to the no.of shots by B is 5:3. Let the actual shots of A and B be 5x and 3x respectively. B kills once in 2 shots means one shot of B gets success and another shot gets failure. Total shots = 27 failed shots + 27 successful shots = 54. That is 3x = 54. x = (54/3) = 18. A's total shots = 5x = 5(18) = 90. A kills once in 3 shots means A's 2 shots get failed and 1 shot. Achieves the target (kills the bird). So, A has killed (90/3) = 30 birds. |

Promodit said: (Jul 30, 2015) | |

A kills 5 birds while b kills 3. And hit ratio of A and B is 3:2 resp. (given). Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer). |

Varsha said: (Aug 27, 2015) | |

How it is mean while A has shot 54*? And why (5/3) =90 times please tell me any one? |

Zehra said: (Aug 30, 2015) | |

A fires 5 shots and kills one in 3. Therefore effective short by A = 3/5. Similarly B = 2/3. Also 3/5A = 2/3B. Now, the no of birds killed by B in 27 shots would be 27*2/3 = 18. When B kills 18 birds. No of birds killed by A = 18*5/3 = 30. Can anybody tell me if I am doing it right? |

Owaiz said: (Jan 27, 2016) | |

Both A and B stand side by side and shoot at the same time. 5 bullets com out of A's gun and 3 bullets come out of B's gun. So the total no of bullets fired at once is 8. Its given that A kills one in 3 shots and B kills one in 2 shots. Its also given that B misses 27 times. As B Misses 27 times and kills one in two shots, the total bullets fired by B is 27*2 = 54. We know that 3 bullets came out of B'S gun when he shot once. So the no of times B shot is 54/3 = 18. Also the no of bullets came out of A is 5 when he shot once and since both A and B shot same no of times i.e.18 times, so the total no of bullets came out of A's gun is 5*18 = 90 bullets. As A killed one in three bullets, the total no of birds killed by A is 90/3 = 30. |

Irshad Ahmad Tawav said: (Aug 13, 2016) | |

Let A and B be 5x, 3x. If x = 1, A = 5 B = 3, If x = 2, A = 10 B = 6, 3x = 54, => x = 18, Total number of shots of A = 5x = 5 * 18 = 90, Number of succeeding shots of A = 1/3 * total shots of A = 1/3 * 90 = 30. |

Smrithi said: (Jan 17, 2017) | |

A:B=5:3. 27 shots fired failed by B. Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54. A/B= 5/3. Therefore A/54=5/3, hence total shorts of A = 90. Probability that A hits = 1/3; Therefore total shorts hit = 90 * 1/3 = 30. |

Ryan said: (Jan 18, 2017) | |

Any other simple method to solve this problem? |

Saif said: (Feb 18, 2017) | |

Thank you @Naddy. |

Jas said: (Feb 18, 2017) | |

Total shots = 8. A = 5/8. B = 3/8. A succeed 3times in 5/8 shots = 5/24. B failed 2 times in 3/8 shots = 3/16. Let total shots = x B's failed = 3x/16. Given 3x/16 = 27, x= 144. Sub in A 5x/24 --> 5x144/24 --> A=30. |

Dory said: (May 17, 2017) | |

So if B kills once in 3 shots, miss shots by B = ( 1-(1/3) ) * (3x/8)? |

Richa said: (Jun 18, 2017) | |

Good job @Kajora. |

Sai Ram said: (Sep 27, 2017) | |

Thank you all. |

Srinivas said: (Nov 8, 2017) | |

Detail explanation of above problem please give me. |

Taniya said: (Nov 29, 2017) | |

Thanks for your explanation @Kajora. |

Malay Giri said: (Dec 22, 2017) | |

A-27*5=135, b-27*3=81, a-b=135-81, =54/3=18, A-18*5=90, A=90/3=30. |

Danish said: (Jan 12, 2018) | |

Superb @Smrithi. |

Siva said: (Jan 24, 2018) | |

Well explained, Thanks @Smrithi. |

Sudip said: (Feb 8, 2018) | |

A:B=5:3. Let no. of shots by A= 5x and B= 3x. A kills after every 3 shots, No. of birds killed by A= 5x/3. B kills after every 2 shots, No. of birds killed by B= 3x/2. No. of shots missed by B= 3x-3x/2= 3x/2=27. Therefore x= 27 x 2/3= 18. No. of birds killed by A in that time= 5x/3= 5*18/3= 30. |

Sapna said: (Mar 5, 2018) | |

Thanks @Sudip. |

Yamini Dhanasekar said: (Aug 20, 2018) | |

Another way of solving this question by logic is, B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots) So totally,27+27=54 shots. A fires 5 shots for b's 3. A --------- B 5 --------- 3 ?? --------- 54. A=54 * 5/3=90 shots. A has 90 shots, A kills once in 3 shots, so 90/3 =30 birds. |

Arun Congo said: (Jun 1, 2019) | |

If A Shoot 5, B will shoot 3. Assume in 1 Minute A can shoot 5 and B can shoot 3. A Scores 1 out of 3, B scores 1 out of 2. In question, we have 27 fails for B. So in 9 minutes, B shoots 54 and scores 27 and fails 27. In 9 Minutes, A shoot 90 and scores 30 and fails 60. |

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