Aptitude - Simplification - Discussion

Every time B fires 3 shots, A fires 5 shots
That’s a firing ratio: A: B = 5 : 3, every time B fires 3, A fires 5.
But B, from 3 shots, he misses 1 shot every time he fires and kills 2, so the total he misses is 27.
In simple language, B misses 1 shots and kills 2, We have given no of shots he missed, but it doesn't include the shots he used to kill, which is 2.
To get the total no of shots of B, 27x2=54 shots.
To calculate A shots, which is 5:3, 54/3=18 times A fired, and 1 time firing consists of 5 shots.
So, 18 x 5 = 90.
The total no of shots A fired is 90, kills once in 3 shots, so 90/3= 60.

Total short by B = 2 * 27 = 54,
Total short by A = 5/3 * 57 ==>5*18==>90,
killed by A = 90/3==>30,
A killed 30 birds.

Can anyone please explain the question?

Thanks @Sudip.

Thanks for explaining the answer @Hary.

Thanks for explaining @Smirthi.

B missed 27 times. Hence, B fired,
27 * 2 = 54 shots.

Therefore, the number of shots fired by
A = (54/3)*5,
= 90.
Therefore, the number of birds killed by;
A = 90*(1/3),
= 30.

If A Shoot 5, B will shoot 3.

Assume in 1 Minute A can shoot 5 and B can shoot 3.
A Scores 1 out of 3, B scores 1 out of 2.

In question, we have 27 fails for B.

So in 9 minutes, B shoots 54 and scores 27 and fails 27.
In 9 Minutes, A shoot 90 and scores 30 and fails 60.

Another way of solving this question by logic is,
B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots)
So totally,27+27=54 shots.
A fires 5 shots for b's 3.
A --------- B
5 --------- 3
?? --------- 54.

A=54 * 5/3=90 shots.
A has 90 shots,
A kills once in 3 shots, so 90/3 =30 birds.

Thanks @Sudip.