# Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 8)

8.

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

Answer: Option

Explanation:

Let the total number of shots be *x*. Then,

Shots fired by A = | 5 | x |

8 |

Shots fired by B = | 3 | x |

8 |

Killing shots by A = | 1 | of | 5 | x |
= | 5 | x |

3 | 8 | 24 |

Shots missed by B = | 1 | of | 3 | x |
= | 3 | x |

2 | 8 | 16 |

3x |
= 27 or x = |
27 x 16 | = 144. | |||

16 | 3 |

Birds killed by A = | 5x |
= | 5 | x 144 | = 30. | ||

24 | 24 |

Discussion:

38 comments Page 1 of 4.
Sai said:
5 months ago

Can anyone please explain the question?

(2)

Sonu said:
8 months ago

Thanks @Sudip.

(1)

Mufassil said:
2 years ago

Thanks for explaining the answer @Hary.

(2)

Kaviya said:
2 years ago

Thanks for explaining @Smirthi.

(3)

Ganga said:
3 years ago

B missed 27 times. Hence, B fired,

27 * 2 = 54 shots.

Therefore, the number of shots fired by

A = (54/3)*5,

= 90.

Therefore, the number of birds killed by;

A = 90*(1/3),

= 30.

27 * 2 = 54 shots.

Therefore, the number of shots fired by

A = (54/3)*5,

= 90.

Therefore, the number of birds killed by;

A = 90*(1/3),

= 30.

(20)

Arun Congo said:
5 years ago

If A Shoot 5, B will shoot 3.

Assume in 1 Minute A can shoot 5 and B can shoot 3.

A Scores 1 out of 3, B scores 1 out of 2.

In question, we have 27 fails for B.

So in 9 minutes, B shoots 54 and scores 27 and fails 27.

In 9 Minutes, A shoot 90 and scores 30 and fails 60.

Assume in 1 Minute A can shoot 5 and B can shoot 3.

A Scores 1 out of 3, B scores 1 out of 2.

In question, we have 27 fails for B.

So in 9 minutes, B shoots 54 and scores 27 and fails 27.

In 9 Minutes, A shoot 90 and scores 30 and fails 60.

(4)

Yamini Dhanasekar said:
6 years ago

Another way of solving this question by logic is,

B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots)

So totally,27+27=54 shots.

A fires 5 shots for b's 3.

A --------- B

5 --------- 3

?? --------- 54.

A=54 * 5/3=90 shots.

A has 90 shots,

A kills once in 3 shots, so 90/3 =30 birds.

B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots)

So totally,27+27=54 shots.

A fires 5 shots for b's 3.

A --------- B

5 --------- 3

?? --------- 54.

A=54 * 5/3=90 shots.

A has 90 shots,

A kills once in 3 shots, so 90/3 =30 birds.

(19)

Sapna said:
6 years ago

Thanks @Sudip.

Sudip said:
6 years ago

A:B=5:3.

Let no. of shots by A= 5x and B= 3x.

A kills after every 3 shots,

No. of birds killed by A= 5x/3.

B kills after every 2 shots,

No. of birds killed by B= 3x/2.

No. of shots missed by B= 3x-3x/2= 3x/2=27.

Therefore x= 27 x 2/3= 18.

No. of birds killed by A in that time= 5x/3= 5*18/3= 30.

Let no. of shots by A= 5x and B= 3x.

A kills after every 3 shots,

No. of birds killed by A= 5x/3.

B kills after every 2 shots,

No. of birds killed by B= 3x/2.

No. of shots missed by B= 3x-3x/2= 3x/2=27.

Therefore x= 27 x 2/3= 18.

No. of birds killed by A in that time= 5x/3= 5*18/3= 30.

(7)

Siva said:
6 years ago

Well explained, Thanks @Smrithi.

(1)

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