Aptitude - Simplification - Discussion

B missed 27 times. Hence, B fired,
27 * 2 = 54 shots.

Therefore, the number of shots fired by
A = (54/3)*5,
= 90.
Therefore, the number of birds killed by;
A = 90*(1/3),
= 30.

Another way of solving this question by logic is,
B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots)
So totally,27+27=54 shots.
A fires 5 shots for b's 3.
A --------- B
5 --------- 3
?? --------- 54.

A=54 * 5/3=90 shots.
A has 90 shots,
A kills once in 3 shots, so 90/3 =30 birds.

A:B=5:3.

Let no. of shots by A= 5x and B= 3x.

A kills after every 3 shots,
No. of birds killed by A= 5x/3.

B kills after every 2 shots,
No. of birds killed by B= 3x/2.
No. of shots missed by B= 3x-3x/2= 3x/2=27.
Therefore x= 27 x 2/3= 18.

No. of birds killed by A in that time= 5x/3= 5*18/3= 30.

Total short by B = 2 * 27 = 54,
Total short by A = 5/3 * 57 ==>5*18==>90,
killed by A = 90/3==>30,
A killed 30 birds.

If A Shoot 5, B will shoot 3.

Assume in 1 Minute A can shoot 5 and B can shoot 3.
A Scores 1 out of 3, B scores 1 out of 2.

In question, we have 27 fails for B.

So in 9 minutes, B shoots 54 and scores 27 and fails 27.
In 9 Minutes, A shoot 90 and scores 30 and fails 60.

Can anyone please explain the question?

The ratio of no.of shots by A to the no.of shots by B is 5:3.

Let the actual shots of A and B be 5x and 3x respectively.

B kills once in 2 shots means one shot of B gets success and another shot gets failure.

Total shots = 27 failed shots + 27 successful shots = 54.

That is 3x = 54.

x = (54/3) = 18.

A's total shots = 5x = 5(18) = 90.

A kills once in 3 shots means A's 2 shots get failed and 1 shot.

Achieves the target (kills the bird).

So, A has killed (90/3) = 30 birds.

Both A and B stand side by side and shoot at the same time. 5 bullets com out of A's gun and 3 bullets come out of B's gun. So the total no of bullets fired at once is 8.

Its given that A kills one in 3 shots and B kills one in 2 shots. Its also given that B misses 27 times.

As B Misses 27 times and kills one in two shots, the total bullets fired by B is 27*2 = 54.

We know that 3 bullets came out of B'S gun when he shot once.

So the no of times B shot is 54/3 = 18.

Also the no of bullets came out of A is 5 when he shot once and since both A and B shot same no of times i.e.18 times, so the total no of bullets came out of A's gun is 5*18 = 90 bullets.

As A killed one in three bullets, the total no of birds killed by A is 90/3 = 30.

This can also be solved practically rather than theoretically.

It is given that B has missed 27 times and B kills once for 2 shots. So, total number of shots B has got is 27*2=54.

And also it is given that A gets 5 shots while B gets 3 shots. So,.

54/3=18.

The number of shots A gets is= 18*5=90.

But A kills once in every 3 shots, so 90/3=30.

No of birds killed by A is=30.

Thanks for explaining @Smirthi.