Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
30 birds
60 birds
72 birds
90 birds
Answer: Option
Explanation:

Let the total number of shots be x. Then,

Shots fired by A = 5 x
8

Shots fired by B = 3 x
8

Killing shots by A = 1 of 5 x = 5 x
3 8 24

Shots missed by B = 1 of 3 x = 3 x
2 8 16

3x = 27 or x = 27 x 16 = 144.
16 3

Birds killed by A = 5x = 5 x 144 = 30.
24 24

Discussion:
41 comments Page 2 of 5.

Abhishek Tripathi said:   3 months ago
• B kills once in 2 shots ⇒ B’s hit probability = 1/2. So miss probability = 1 - 1/2 = 1/2.
• B has missed 27 times. Since each shot has a 1/2 chance to miss, the number of shots B fired is
shots by B = 27/(1/2)= 27*2 = 54.
• A fires 5 shots for every 3 shots of B. So when B fired 54 shots, A fired
shots by A = (5/3)*54 = 5*18 = 90.
• A kills once in 3 shots, so the number of kills by A = 90/3=30.

Answer: 30 birds (option A).
(2)

Mufassil said:   3 years ago
Thanks for explaining the answer @Hary.
(2)

Abhinav said:   1 decade ago
B kills once in 2 shots.

No. of failure shots = 1.

No. of succeeded shots = 1.

When no. of failure shots = 27 then no. of succeeded shots = 27,

So, total no. of shots by B = 27+27 = 54.

When B shoots 3 shot then A shoots 5 shots.

So, When B shoots 1 shot then A shoots 5/3 shot.

So, When B shoots 54 shot then A shoots 54*5/3 = 90 shots.

When A shoots 3 it killed 1.

So, when A shoots 90 it killed = 90/3 = 30.
(2)

Rahul said:   1 decade ago
It is given that if A fires 5 shots B fires only 3 times.
It is given that p(A)=1/3 and p(B)=1/2.

It is also given that A missed 27 times so he fired totally 54 times.
From the above we can calculate that totally A fired 90 times.

So total successful firings by A=90*1/3=30.
(1)

Sonu said:   2 years ago
Thanks @Sudip.
(1)

Deepali said:   5 months ago
Every time B fires 3 shots, A fires 5 shots
That’s a firing ratio: A: B = 5 : 3, every time B fires 3, A fires 5.
But B, from 3 shots, he misses 1 shot every time he fires and kills 2, so the total he misses is 27.
In simple language, B misses 1 shots and kills 2, We have given no of shots he missed, but it doesn't include the shots he used to kill, which is 2.
To get the total no of shots of B, 27x2=54 shots.
To calculate A shots, which is 5:3, 54/3=18 times A fired, and 1 time firing consists of 5 shots.
So, 18 x 5 = 90.
The total no of shots A fired is 90, kills once in 3 shots, so 90/3= 60.
(1)

Chetna said:   1 decade ago
How is the no. of failure shots equal to the no. of succeded shots.. i.e. 3x/18=27??
(1)

Naddy said:   1 decade ago
Given:No of shots=8(A=5,B=3)
Suceeded shots of A= 1 of 3,so 1/3
Suceeded shots of B= 1 of 2,so 1/2
Failure shots of B=27

so Suceeded shots by A=1/3 of 5/8x=5/24*x
Suceeded shots by B=1/2 of 3/8x=3/16*x

therefore failure shots,3x/16=27 (because 27 is missed shots as per question),so x=144
Therefore succeded shots by A=5x/24 *144= 30
(1)

Sapna said:   8 years ago
Thanks @Sudip.
(1)

Siva said:   8 years ago
Well explained, Thanks @Smrithi.
(1)


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