Aptitude - Simplification - Discussion

Given:No of shots=8(A=5,B=3)
Suceeded shots of A= 1 of 3,so 1/3
Suceeded shots of B= 1 of 2,so 1/2
Failure shots of B=27

so Suceeded shots by A=1/3 of 5/8x=5/24*x
Suceeded shots by B=1/2 of 3/8x=3/16*x

therefore failure shots,3x/16=27 (because 27 is missed shots as per question),so x=144
Therefore succeded shots by A=5x/24 *144= 30

Superb @Smrithi.

Total shots = 8.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.

Thanks for your explanation @Kajora.

Let A and B be 5x, 3x.

If x = 1, A = 5 B = 3,

If x = 2, A = 10 B = 6,

3x = 54,

=> x = 18,

Total number of shots of A = 5x

= 5 * 18 = 90,

Number of succeeding shots of A = 1/3 * total shots of A

= 1/3 * 90 = 30.

Please anybody explain very simply. ? please help.

No. of failure shots equal to the no. of succeded shots
because B suceeds once in 2 shots
so probability of success is 1/2
probability of failure 1-(probability of success) =>1-1/2 = 1/2

When B shots 2 it missed 1.
So, when B missed 27 B shoots (27*2) = 54.

When B shoots 3 at the same time A shoots 5.
So, total shoots of A = (5/3)*54 = 5*18= 90.

When A shoots 3 it killed 1.
So, when A shoots 90 it killed = 90/3 = 30.

It is hard to understand how 5/8 and 3/8 comes please anyone can explain?

When total no of shots = 8.
A fired 5 times of 8 = 5/8.
B fires 3 times of 8.
Hence B's fired = 3/8.
A succeed 3 times in 5/8 shots.

Hence A succeed = 5/24 times similarly.
B succeed 2 times in 3/8 SHOTS.

B SUCCEED = 3/16 times and also failed 3/16 times.
If total no shots = x .

Then,
B's failed time = 3x/16.

Since,
B failed 27 time = 3x/16.

27=3x/16.
X=144=total no of shots.

A's total shot=failed+succeed.
=27+27=54.

B's shot=total-A's shot.
=144-54=90.

Then,
B's succeed =90/3=30.