Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
30 birds
60 birds
72 birds
90 birds
Answer: Option
Explanation:

Let the total number of shots be x. Then,

Shots fired by A = 5 x
8

Shots fired by B = 3 x
8

Killing shots by A = 1 of 5 x = 5 x
3 8 24

Shots missed by B = 1 of 3 x = 3 x
2 8 16

3x = 27 or x = 27 x 16 = 144.
16 3

Birds killed by A = 5x = 5 x 144 = 30.
24 24

Discussion:
40 comments Page 4 of 4.

SMRITHI said:   9 years ago
A:B=5:3.

27 shots fired failed by B.

Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.

A/B= 5/3.

Therefore A/54=5/3, hence total shorts of A = 90.

Probability that A hits = 1/3;

Therefore total shorts hit = 90 * 1/3 = 30.

Irshad Ahmad Tawav said:   9 years ago
Let A and B be 5x, 3x.

If x = 1, A = 5 B = 3,

If x = 2, A = 10 B = 6,

3x = 54,

=> x = 18,

Total number of shots of A = 5x

= 5 * 18 = 90,

Number of succeeding shots of A = 1/3 * total shots of A

= 1/3 * 90 = 30.

Zehra said:   10 years ago
A fires 5 shots and kills one in 3.

Therefore effective short by A = 3/5.

Similarly B = 2/3.

Also 3/5A = 2/3B.

Now, the no of birds killed by B in 27 shots would be 27*2/3 = 18.

When B kills 18 birds. No of birds killed by A = 18*5/3 = 30.

Can anybody tell me if I am doing it right?

Varsha said:   10 years ago
How it is mean while A has shot 54*? And why (5/3) =90 times please tell me any one?

Promodit said:   1 decade ago
A kills 5 birds while b kills 3. And hit ratio of A and B is 3:2 resp. (given).

Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).

Rajtiwari said:   1 decade ago
When total no of shots = 8.
A fired 5 times of 8 = 5/8.
B fires 3 times of 8.
Hence B's fired = 3/8.
A succeed 3 times in 5/8 shots.

Hence A succeed = 5/24 times similarly.
B succeed 2 times in 3/8 SHOTS.

B SUCCEED = 3/16 times and also failed 3/16 times.
If total no shots = x .

Then,
B's failed time = 3x/16.

Since,
B failed 27 time = 3x/16.

27=3x/16.
X=144=total no of shots.

A's total shot=failed+succeed.
=27+27=54.

B's shot=total-A's shot.
=144-54=90.

Then,
B's succeed =90/3=30.

Deepak said:   1 decade ago
It is hard to understand how 5/8 and 3/8 comes please anyone can explain?

Nabanita Sarkar said:   1 decade ago
When B shots 2 it missed 1.
So, when B missed 27 B shoots (27*2) = 54.

When B shoots 3 at the same time A shoots 5.
So, total shoots of A = (5/3)*54 = 5*18= 90.

When A shoots 3 it killed 1.
So, when A shoots 90 it killed = 90/3 = 30.

Franco said:   1 decade ago
No. of failure shots equal to the no. of succeded shots
because B suceeds once in 2 shots
so probability of success is 1/2
probability of failure 1-(probability of success) =>1-1/2 = 1/2

Suriya said:   1 decade ago
Please anybody explain very simply. ? please help.


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