Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
Answer: Option
Explanation:
Let the total number of shots be x. Then,
| Shots fired by A = | 5 | x |
| 8 |
| Shots fired by B = | 3 | x |
| 8 |
| Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
| 3 | 8 | 24 |
| Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
| 2 | 8 | 16 |
 |
3x | = 27 or x = |  |
27 x 16 |  |
= 144. |
| 16 | 3 |
| Birds killed by A = | 5x | = | |
5 | x 144 | |
= 30. |
| 24 | 24 |
Discussion:
42 comments Page 4 of 5.
Rajtiwari said:
1 decade ago
When total no of shots = 8.
A fired 5 times of 8 = 5/8.
B fires 3 times of 8.
Hence B's fired = 3/8.
A succeed 3 times in 5/8 shots.
Hence A succeed = 5/24 times similarly.
B succeed 2 times in 3/8 SHOTS.
B SUCCEED = 3/16 times and also failed 3/16 times.
If total no shots = x .
Then,
B's failed time = 3x/16.
Since,
B failed 27 time = 3x/16.
27=3x/16.
X=144=total no of shots.
A's total shot=failed+succeed.
=27+27=54.
B's shot=total-A's shot.
=144-54=90.
Then,
B's succeed =90/3=30.
A fired 5 times of 8 = 5/8.
B fires 3 times of 8.
Hence B's fired = 3/8.
A succeed 3 times in 5/8 shots.
Hence A succeed = 5/24 times similarly.
B succeed 2 times in 3/8 SHOTS.
B SUCCEED = 3/16 times and also failed 3/16 times.
If total no shots = x .
Then,
B's failed time = 3x/16.
Since,
B failed 27 time = 3x/16.
27=3x/16.
X=144=total no of shots.
A's total shot=failed+succeed.
=27+27=54.
B's shot=total-A's shot.
=144-54=90.
Then,
B's succeed =90/3=30.
Promodit said:
1 decade ago
A kills 5 birds while b kills 3. And hit ratio of A and B is 3:2 resp. (given).
Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).
Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).
Varsha said:
1 decade ago
How it is mean while A has shot 54*? And why (5/3) =90 times please tell me any one?
Zehra said:
1 decade ago
A fires 5 shots and kills one in 3.
Therefore effective short by A = 3/5.
Similarly B = 2/3.
Also 3/5A = 2/3B.
Now, the no of birds killed by B in 27 shots would be 27*2/3 = 18.
When B kills 18 birds. No of birds killed by A = 18*5/3 = 30.
Can anybody tell me if I am doing it right?
Therefore effective short by A = 3/5.
Similarly B = 2/3.
Also 3/5A = 2/3B.
Now, the no of birds killed by B in 27 shots would be 27*2/3 = 18.
When B kills 18 birds. No of birds killed by A = 18*5/3 = 30.
Can anybody tell me if I am doing it right?
Srinivas said:
8 years ago
Detail explanation of above problem please give me.
SMRITHI said:
9 years ago
A:B=5:3.
27 shots fired failed by B.
Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.
A/B= 5/3.
Therefore A/54=5/3, hence total shorts of A = 90.
Probability that A hits = 1/3;
Therefore total shorts hit = 90 * 1/3 = 30.
27 shots fired failed by B.
Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.
A/B= 5/3.
Therefore A/54=5/3, hence total shorts of A = 90.
Probability that A hits = 1/3;
Therefore total shorts hit = 90 * 1/3 = 30.
Ryan said:
9 years ago
Any other simple method to solve this problem?
Saif said:
9 years ago
Thank you @Naddy.
Jas said:
9 years ago
Total shots = 8.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.
Pollard said:
2 decades ago
Please anybody explain very simply..?
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