Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
30 birds
60 birds
72 birds
90 birds
Answer: Option
Explanation:

Let the total number of shots be x. Then,

Shots fired by A = 5 x
8

Shots fired by B = 3 x
8

Killing shots by A = 1 of 5 x = 5 x
3 8 24

Shots missed by B = 1 of 3 x = 3 x
2 8 16

3x = 27 or x = 27 x 16 = 144.
16 3

Birds killed by A = 5x = 5 x 144 = 30.
24 24

Discussion:
40 comments Page 2 of 4.

Sudip said:   8 years ago
A:B=5:3.

Let no. of shots by A= 5x and B= 3x.

A kills after every 3 shots,
No. of birds killed by A= 5x/3.

B kills after every 2 shots,
No. of birds killed by B= 3x/2.
No. of shots missed by B= 3x-3x/2= 3x/2=27.
Therefore x= 27 x 2/3= 18.

No. of birds killed by A in that time= 5x/3= 5*18/3= 30.
(15)

Siva said:   8 years ago
Well explained, Thanks @Smrithi.
(1)

Danish said:   8 years ago
Superb @Smrithi.

Malay giri said:   8 years ago
A-27*5=135,
b-27*3=81,
a-b=135-81,
=54/3=18,
A-18*5=90,
A=90/3=30.
(1)

Taniya said:   8 years ago
Thanks for your explanation @Kajora.

Srinivas said:   8 years ago
Detail explanation of above problem please give me.

SAI RAM said:   8 years ago
Thank you all.

Richa said:   8 years ago
Good job @Kajora.

Dory said:   8 years ago
So if B kills once in 3 shots, miss shots by B = ( 1-(1/3) ) * (3x/8)?

Jas said:   9 years ago
Total shots = 8.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.


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