Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 4 of 14.
Naresh said:
1 decade ago
Hi friends, please think logically.
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250)
(3) Now check given answers....take 6.2runrate and 40 overs(i.e 6.25*40=250). So ans is "6.25" .
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250)
(3) Now check given answers....take 6.2runrate and 40 overs(i.e 6.25*40=250). So ans is "6.25" .
Ravi said:
1 decade ago
We need to calculate remaining average so we have to deduct score whick is already scored.
Ashish said:
1 decade ago
Hi friends, please think logically.
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250
(3) In 40 overs runs are 250.
Now, Run rate is 250/40 = 6.25 //
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250
(3) In 40 overs runs are 250.
Now, Run rate is 250/40 = 6.25 //
GANGARAJU T C said:
1 decade ago
First 10 overs Score = 10 overs x 3.2 Run Rate = 32 Runs.
Total targeted runs in 50 overs = 282 Runs
Required Runs to be scored in 40 overs = 250
Total 50 overs Runs(282 Runs)-First 10 overs runs Scored(32 Runs)
Required Run Rate in 40 overs = Required Runs/Remaining overs
= 250 Runs /40 overs
= 6.25
Total targeted runs in 50 overs = 282 Runs
Required Runs to be scored in 40 overs = 250
Total 50 overs Runs(282 Runs)-First 10 overs runs Scored(32 Runs)
Required Run Rate in 40 overs = Required Runs/Remaining overs
= 250 Runs /40 overs
= 6.25
(1)
Soudri said:
1 decade ago
10*3.2=32
So 282 - 32 = 250/40= 6.25
So 282 - 32 = 250/40= 6.25
Colbie said:
1 decade ago
Mr.A average on 4 test is 80. what does he need on his fifth test to raise his average to 84?
Apple said:
1 decade ago
@Colbie.
Use this formula to solve the problem:
Average = sum of runs/number of tests.
Given that, average on 4 tests is 80.
Hence, Sum of runs scored = 80 x 4 = 360.
To calculate the number of runs he needs in his fifth test to raise his average to 84 is,
84 = 360 + x / 5 (use the formula given above).
x = 420 - 360 = 60 (answer).
Use this formula to solve the problem:
Average = sum of runs/number of tests.
Given that, average on 4 tests is 80.
Hence, Sum of runs scored = 80 x 4 = 360.
To calculate the number of runs he needs in his fifth test to raise his average to 84 is,
84 = 360 + x / 5 (use the formula given above).
x = 420 - 360 = 60 (answer).
Banita said:
1 decade ago
Excellent explanation Tarun and Deepa, Thanks a lot
Sushank said:
1 decade ago
Run rate in first ten overs = 3.2
Total runs made in first ten overs = 3.2*10 = 32 runs
Remaining runs to make = 282-32 =250
Overs left = 40 overs
Average run rate = 250/40 = 6.25
So, The run rate to make 250 runs in 40 overs is 6.25 RPO(runs per over)
Total runs made in first ten overs = 3.2*10 = 32 runs
Remaining runs to make = 282-32 =250
Overs left = 40 overs
Average run rate = 250/40 = 6.25
So, The run rate to make 250 runs in 40 overs is 6.25 RPO(runs per over)
Pradeep said:
1 decade ago
Total run in 10 over=10*3.2=32
Required run in 40 over=282-32=250
Hence avg=250/40 =6.25
Required run in 40 over=282-32=250
Hence avg=250/40 =6.25
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