# Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 1)

1.

In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

Answer: Option

Explanation:

Required run rate = | 282 - (3.2 x 10) | = | 250 | = 6.25 | ||

40 | 40 |

Video Explanation: https://youtu.be/GhK9d8tcqvA

Discussion:

131 comments Page 1 of 14.
Karthi said:
2 weeks ago

First 10 - run rate 3.2

3.2 = sum of runs/10

Sum = 3.2×10 = 32

40 over total runs 282.

So, 282 - 32 = 250 remaining runs.

Run rate = 250/40 = 6.25.

3.2 = sum of runs/10

Sum = 3.2×10 = 32

40 over total runs 282.

So, 282 - 32 = 250 remaining runs.

Run rate = 250/40 = 6.25.

(3)

Cherry aishu said:
4 months ago

Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.

(34009+x)/6 = 6500,

34009+x = 39000,

x = 39000-34009,

x = 4991.

(34009+x)/6 = 6500,

34009+x = 39000,

x = 39000-34009,

x = 4991.

(2)

Kondru Durga Srinu said:
4 months ago

Runs scored= overs * runrate.

= 10 *3.2.

Runs scored in 10 overs is 32 runs.

Total runs for 50 overs= 282runs.

Runs for 40 overs is = 282-32.

= 250 runs.

Runrate for 40 overs is = 250/40 is 6.25 (option A).

= 10 *3.2.

Runs scored in 10 overs is 32 runs.

Total runs for 50 overs= 282runs.

Runs for 40 overs is = 282-32.

= 250 runs.

Runrate for 40 overs is = 250/40 is 6.25 (option A).

(44)

Kondru Durga Srinu said:
4 months ago

So we calculate the runs in the first 10 overs = 10 * 3.2

First 10 overs they got 32 runs

Total runs for 50 overs is 282

Then, the remaining 40 overs they got = 282 - 32 = 250.

250/40 = 6.25

First 10 overs they got 32 runs

Total runs for 50 overs is 282

Then, the remaining 40 overs they got = 282 - 32 = 250.

250/40 = 6.25

(7)

Bhukya Praveen said:
5 months ago

10 overs ------------ 3.2 rr

40 overs ------------ ?

Target = 282.

First 10 overs => 10 x 3.2 = 32 Runs.

282 - 32 = 250 Runs Scored in the remaining 40 overs.

Total 50 overs

RunRate in remaining 40 overs => 250/40.

=> 6.25 RR.

40 overs ------------ ?

Target = 282.

First 10 overs => 10 x 3.2 = 32 Runs.

282 - 32 = 250 Runs Scored in the remaining 40 overs.

Total 50 overs

RunRate in remaining 40 overs => 250/40.

=> 6.25 RR.

(21)

Shreya Dakhale said:
11 months ago

Total Runs in 10 overs/number of overs = run rate.

Total Runs in 10 overs/10 = 3.2.

Total Runs in 10 overs = 32.

Scores to achieve - Total Runs in 10 overs.

282 - 32 = 250.

250/40 = run rate.

So, run rate = 6.25.

Total Runs in 10 overs/10 = 3.2.

Total Runs in 10 overs = 32.

Scores to achieve - Total Runs in 10 overs.

282 - 32 = 250.

250/40 = run rate.

So, run rate = 6.25.

(41)

Ahmed Raafat said:
1 year ago

Run rate = number of runs/number of overs.

(14)

ANVITHA said:
3 years ago

Runs scored= run rate*overs.

= 3.2*10,

= 32.

In remaining 40 overs they score 250 runs.

Runs scored=run rate * overs.

250 = run rate * 40.

Run rate = 250/40.

= 6.25.

= 3.2*10,

= 32.

In remaining 40 overs they score 250 runs.

Runs scored=run rate * overs.

250 = run rate * 40.

Run rate = 250/40.

= 6.25.

(103)

Jyothis said:
3 years ago

Assume run rate as average,

Then, Avg of first 10 overs = 3.2.

Avg(10) = total runs for 10overs/no.of overs.

3.2=total runs/10.

Total runs for 10 overs = 3.2 * 10 = 32,

Remaining runs=282-32 = 250,

Avg runs remaining 40 overs = 250/40 = 6.25.

Then, Avg of first 10 overs = 3.2.

Avg(10) = total runs for 10overs/no.of overs.

3.2=total runs/10.

Total runs for 10 overs = 3.2 * 10 = 32,

Remaining runs=282-32 = 250,

Avg runs remaining 40 overs = 250/40 = 6.25.

(36)

Manalan said:
3 years ago

First 10 over,

3.2 = 10 * 3.2 = 32runs.

40 overs is 282 = 282-32.

= 250.

250 Ã· 40 = 6.25,

6.25.

3.2 = 10 * 3.2 = 32runs.

40 overs is 282 = 282-32.

= 250.

250 Ã· 40 = 6.25,

6.25.

(9)

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