# Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
6.25
6.5
6.75
7
Explanation:

 Required run rate = 282 - (3.2 x 10) = 250 = 6.25 40 40

Video Explanation: https://youtu.be/GhK9d8tcqvA

Discussion:
126 comments Page 1 of 13.

Why we are writing 3.2*10 ?

They asking only remainig 40 over run rate. So why use of first 10 over?

How do we arrive at the solution.? What is the logic?

Pratik Mehta said:   1 decade ago
@Kavita : Run rate * overs = runs scored.

So now Run rate = Runs scored/required / overs.

There 282 - (3.2 x 10) = Runs required

Remaining overs are 40.

Why do we minus 282-(3.2*10)...?

So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25

Thanks muhundhan thats great.

Why are you minus that 282 runs?

282 are not minus,here ((3.2(current run rate)*10(overs))=32runs)
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.