Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
6.25
6.5
6.75
7
Answer: Option
Explanation:

Required run rate = 282 - (3.2 x 10) = 250    = 6.25
40 40

Video Explanation: https://youtu.be/GhK9d8tcqvA

Discussion:
132 comments Page 1 of 14.

Vinod said:   1 decade ago
Why we are writing 3.2*10 ?

Dilepkumar said:   1 decade ago
They asking only remainig 40 over run rate. So why use of first 10 over?

Kavita said:   1 decade ago
How do we arrive at the solution.? What is the logic?

Pratik Mehta said:   1 decade ago
@Kavita : Run rate * overs = runs scored.

So now Run rate = Runs scored/required / overs.

There 282 - (3.2 x 10) = Runs required

Remaining overs are 40.

Ranjith said:   1 decade ago
Why do we minus 282-(3.2*10)...?

Muhundhan said:   1 decade ago
So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25

Abc said:   1 decade ago
Thanks muhundhan thats great.

Swetha said:   1 decade ago
Why are you minus that 282 runs?

Tarun said:   1 decade ago
282 are not minus,here ((3.2(current run rate)*10(overs))=32runs)
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.

Avinsh said:   1 decade ago
How to solve given problem:.

Rajana traveled a journey of 500km with speed of 50km/hr for 5 liter and traveled withe speed of 60km/hr for 5hr and then is last 5hr covers a distance of 700km and after taking rest of 3 hr again traveled. For 2 hr by covering a distance 120km find average of speed.


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