Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
Required run rate = | 282 - (3.2 x 10) | = | 250 | = 6.25 | ||
40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
132 comments Page 1 of 14.
Vinod said:
1 decade ago
Why we are writing 3.2*10 ?
Dilepkumar said:
1 decade ago
They asking only remainig 40 over run rate. So why use of first 10 over?
Kavita said:
1 decade ago
How do we arrive at the solution.? What is the logic?
Pratik Mehta said:
1 decade ago
@Kavita : Run rate * overs = runs scored.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
Ranjith said:
1 decade ago
Why do we minus 282-(3.2*10)...?
Muhundhan said:
1 decade ago
So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
Abc said:
1 decade ago
Thanks muhundhan thats great.
Swetha said:
1 decade ago
Why are you minus that 282 runs?
Tarun said:
1 decade ago
282 are not minus,here ((3.2(current run rate)*10(overs))=32runs)
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.
Avinsh said:
1 decade ago
How to solve given problem:.
Rajana traveled a journey of 500km with speed of 50km/hr for 5 liter and traveled withe speed of 60km/hr for 5hr and then is last 5hr covers a distance of 700km and after taking rest of 3 hr again traveled. For 2 hr by covering a distance 120km find average of speed.
Rajana traveled a journey of 500km with speed of 50km/hr for 5 liter and traveled withe speed of 60km/hr for 5hr and then is last 5hr covers a distance of 700km and after taking rest of 3 hr again traveled. For 2 hr by covering a distance 120km find average of speed.
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