Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
132 comments Page 1 of 14.
Srijan said:
2 months ago
I understand the solution with the help of the given explanation. Thanks, everyone.
(12)
Karthi said:
3 months ago
First 10 - run rate 3.2
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
(13)
Cherry aishu said:
6 months ago
Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(4)
Kondru Durga Srinu said:
6 months ago
Runs scored= overs * runrate.
= 10 *3.2.
Runs scored in 10 overs is 32 runs.
Total runs for 50 overs= 282runs.
Runs for 40 overs is = 282-32.
= 250 runs.
Runrate for 40 overs is = 250/40 is 6.25 (option A).
= 10 *3.2.
Runs scored in 10 overs is 32 runs.
Total runs for 50 overs= 282runs.
Runs for 40 overs is = 282-32.
= 250 runs.
Runrate for 40 overs is = 250/40 is 6.25 (option A).
(50)
Kondru Durga Srinu said:
6 months ago
So we calculate the runs in the first 10 overs = 10 * 3.2
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
(8)
Bhukya Praveen said:
7 months ago
10 overs ------------ 3.2 rr
40 overs ------------ ?
Target = 282.
First 10 overs => 10 x 3.2 = 32 Runs.
282 - 32 = 250 Runs Scored in the remaining 40 overs.
Total 50 overs
RunRate in remaining 40 overs => 250/40.
=> 6.25 RR.
40 overs ------------ ?
Target = 282.
First 10 overs => 10 x 3.2 = 32 Runs.
282 - 32 = 250 Runs Scored in the remaining 40 overs.
Total 50 overs
RunRate in remaining 40 overs => 250/40.
=> 6.25 RR.
(24)
Shreya Dakhale said:
1 year ago
Total Runs in 10 overs/number of overs = run rate.
Total Runs in 10 overs/10 = 3.2.
Total Runs in 10 overs = 32.
Scores to achieve - Total Runs in 10 overs.
282 - 32 = 250.
250/40 = run rate.
So, run rate = 6.25.
Total Runs in 10 overs/10 = 3.2.
Total Runs in 10 overs = 32.
Scores to achieve - Total Runs in 10 overs.
282 - 32 = 250.
250/40 = run rate.
So, run rate = 6.25.
(42)
Ahmed Raafat said:
1 year ago
Run rate = number of runs/number of overs.
(14)
ANVITHA said:
3 years ago
Runs scored= run rate*overs.
= 3.2*10,
= 32.
In remaining 40 overs they score 250 runs.
Runs scored=run rate * overs.
250 = run rate * 40.
Run rate = 250/40.
= 6.25.
= 3.2*10,
= 32.
In remaining 40 overs they score 250 runs.
Runs scored=run rate * overs.
250 = run rate * 40.
Run rate = 250/40.
= 6.25.
(105)
Jyothis said:
3 years ago
Assume run rate as average,
Then, Avg of first 10 overs = 3.2.
Avg(10) = total runs for 10overs/no.of overs.
3.2=total runs/10.
Total runs for 10 overs = 3.2 * 10 = 32,
Remaining runs=282-32 = 250,
Avg runs remaining 40 overs = 250/40 = 6.25.
Then, Avg of first 10 overs = 3.2.
Avg(10) = total runs for 10overs/no.of overs.
3.2=total runs/10.
Total runs for 10 overs = 3.2 * 10 = 32,
Remaining runs=282-32 = 250,
Avg runs remaining 40 overs = 250/40 = 6.25.
(36)
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